Staff Selection Commission Combined Graduate Level Exam
Question : Study of organisms in relation to their environment is called:
Option 1: Ecology
Option 2: Zoology
Option 3: Entomology
Option 4: Palynology
Correct Answer: Ecology
Solution : The correct answer is Ecology.
The branch of science which studies the interaction between organism and its environment is known as ecology. Ecology term was coined by a German botanist, Ernst Haeckel. It is studied at different level like organism, population, community etc. Alexander con
Question : P and Q together complete a job in $4 \frac{2}{5}$ days. R and S complete the same job in $4 \frac{8}{9}$ days. If P, Q, R, and S work together, how many days do they need to complete the same job?
Option 1: $2 \frac{7}{18}$
Option 2: $1 \frac{7}{18}$
Option 3: $1 \frac{6}{19}$
Option 4: $2 \frac{6}{19}$
Correct Answer: $2 \frac{6}{19}$
Solution : P and Q complete the job in $4 \frac{2}{5}$ days = $\frac{22}{5}$ days R and S complete the same job in $4 \frac{8}{9}$ days = $\frac{44}{9}$ days P, Q, R, and S, working together, would complete in 1 day $=\frac{5}{22}+ \frac{9}{44} = \frac{10+9}{44} =
Question : Which article of the Indian Constitution stipulates that the law declared by the Supreme Court shall be binding on all courts within the territory of India?
Option 1: Article 141
Option 2: Article 140
Option 3: Article 142
Option 4: Article 145
Correct Answer: Article 141
Solution : The correct answer is Article 141.
By Article 141 of the Indian Constitution's Stare Decisis Doctrine established in 1950, any law pronounced by the Supreme Court holds authority over all courts within the jurisdiction of India. This imparts conclusive authority to the Supreme Court's
Question : Directions: In this question, a part of the sentence is in bold. Below are given alternatives to the bold part at 1, 2, and 3 which may improve the sentence. Choose the correct alternative. In case no improvement is needed your answer is 4.
Kim is too impatient with tolerating any delay.
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 3
Solution : The correct choice is the third option.
The sentence tends to convey that Kim is so impatient that he cannot tolerate any delay. The correct structure to use is "too + adjective + infinitive".
The other alternatives do not provide the correct structure for
Question : Identify the segment in the sentence which contains a grammatical error. If there is no error, select 'No error'.
These experiments had been going on since several months.
Option 1: These experiments
Option 2: had been going on
Option 3: No error
Option 4: since several months
Correct Answer: since several months
Solution : The error lies in the fourth option.
"Since" should be replaced by "for". The words "for" and "since" even though they denote a period of time, can neither be used interchangeably nor synonymously. "For" is used with a period of time in
Question : The sum of two numbers is 680. If the bigger number is decreased by 15% and the smaller number is increased by 15%, then the resultant numbers are equal. Find the smaller number.
Option 1: 307
Option 2: 285
Option 3: 289
Option 4: 304
Correct Answer: 289
Solution : Let the bigger number be $x$. Smaller number = $680 - x$ According to the question, $x(1 - 15\%) = (680 - x)(1 + 15\%)$ ⇒ $\frac{x}{(680 - x)} = \frac{23}{17}$ ⇒ $17x = 23 × 680 - 23x$ ⇒ $40x = 23 × 680$
Question : If $\sin \theta+\sin ^2 \theta=1$, then the value of $\cos ^2 \theta+\cos ^4 \theta$ is equal to:
Option 1: 5
Option 2: $\frac{1}{2}$
Option 3: $1$
Option 4: $0$
Correct Answer: $1$
Solution : Given: $\sin \theta+\sin ^2 \theta=1$ Use the trigonometric identity, $\sin^2 \theta+\cos^2 \theta=1$. $\sin \theta+\sin ^2 \theta=1$ ⇒ $\sin \theta=1–\sin ^2 \theta$ ⇒ $\sin \theta=\cos ^2 \theta$ The value of $\cos ^2 \theta+\cos ^4 \theta=\sin \theta+\sin^2 \theta =1$. Hence, the correct answer is 1.
Question : If $\tan(\alpha -\beta)=1,\sec(\alpha +\beta)=\frac{2}{\sqrt{3}}$ and $\alpha ,\beta$ are positive, then the smallest value of $\alpha$ is:
Option 1: $142\frac{1}{2}°$
Option 2: $187\frac{1}{2}°$
Option 3: $7\frac{1}{2}°$
Option 4: $37\frac{1}{2}°$
Correct Answer: $37\frac{1}{2}°$
Solution : Given: $\tan(\alpha -\beta)=1$ $\sec(\alpha +\beta)=\frac{2}{\sqrt{3}}$ Formula Used: $\tan 45° = 1$ $\sec 45° = \frac{2}{\sqrt{3}}$ Calculation: $\tan(\alpha -\beta)=1$ ⇒ $\alpha -\beta = 45°$..............(i) Also, $\sec(\alpha +\beta)=\frac{2}{\sqrt{3}}$ ⇒ $\alpha +\beta = 30°$................(ii) Adding (i) + (ii) $2\alpha = 45° + 30°$ ⇒ $\alpha= \frac{75}{2} = 37\frac{1}{2}°$
Question : Which of the following statements is correct concerning the Prashastis and land grants?
I. Prashastis was composed of learned Brahmanas.
II. Kings often rewarded Brahmanas with grants of land, which were recorded on copper plates.
Option 1: Only I
Option 2: Both I and II
Option 3: Only II
Option 4: Neither I nor II
Correct Answer: Both I and II
Solution : The correct option is Both I and II.
Prashasti were composed of learned Brahmanas, who were scholars and priests in ancient Indian society.
Kings often rewarded Brahmanas and individuals for their services by granting them land or other privileges. These grants
Question : A car driver leaves Bangalore at 8.30 A.M. and expects to reach a place 300 km from Bangalore at 12.30 P.M. At 10.30 A.M., he finds that he has covered only 40% of the distance. By how much, he has to increase the speed of the car in order to keep up his schedule?
Option 1: 45 km/hr
Option 2: 40 km/hr
Option 3: 35 km/hr
Option 4: 30 km/hr
Correct Answer: 30 km/hr
Solution : Given: Driver started at 8:30 A.M. to cover a distance of 300 km till 12:30 P.M. At 10.30 A.M., he finds that he has covered only 40% of the distance. Distance covered in 2 hours = 300 × $\frac{40}{100}$ = 120 km Remaining distance
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