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Staff Selection Commission Combined Graduate Level Exam

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Question : Ringworm is a ........ disease.

Option 1: Bacterial

Option 2: Protozoan

Option 3: Viral

Option 4: Fungal

Team Careers360 24th Jan, 2024

Correct Answer: Fungal


Solution : The correct option is Fungal.

Ringworm is a fungal infection. Despite its name, it is caused by fungus that can infect the skin, hair, or nails, rather than worms. Ringworm is also known as dermatophytosis, and it is caused by fungus such as Trichophyton, Microsporum,

14 Views

Question : Select the most appropriate ANTONYM of the given word.
Hazard

Option 1: Peril

Option 2: Jeopardy

Option 3: Protection

Option 4: Danger

Team Careers360 21st Jan, 2024

Correct Answer: Protection


Solution : The correct choice is the third option.

ExplanationHazard refers to something that poses a threat or danger, while protection refers to measures taken to prevent or shield against that danger.

The meanings of the other options are as follows:

  • Peril and jeopardy are
13 Views

Question : The amount of Rs. 10,000 after 2 years, compounded annually with the rate of interest being 10% per annum during the first year and 12% per annum during the second year, would be (in rupees):

Option 1: 11,320

Option 2: 12,000

Option 3: 12,320

Option 4: 12,500

Team Careers360 24th Jan, 2024

Correct Answer: 12,320


Solution : Present value (P) = Rs. 10,000
Interest rate for 1st year,
$r_1$ = 10% per annum
Interest rate for 2nd year,
$r_2$ = 12% per annum
Time = 2 years
Amount(A) = P × (1 + $\frac{r_1}{100}$) × (1 + $\frac{r_2}{100}$)
= 10000 × (1

16 Views

Question : $\frac{(1+\tan \theta+\sec \theta)(1+\cot \theta-\operatorname{cosec} \theta)}{(\sec \theta+\tan \theta)(1-\sin \theta)}$ is equal to:

Option 1: $2 \sec \theta$

Option 2: $2 \operatorname{cosec} \theta$

Option 3: $\operatorname{cosec} \theta$

Option 4: $\sec \theta$

Team Careers360 24th Jan, 2024

Correct Answer: $2 \sec \theta$


Solution : $\frac{(1+\tan \theta+\sec \theta)(1+\cot \theta-\operatorname{cosec} \theta)}{(\sec \theta+\tan \theta)(1-\sin \theta)}$
$=\frac{(1+\frac{\sin \theta}{\cos \theta}+\frac{1}{\cos \theta})(1+\frac {\cos \theta}{\sin \theta}-\frac {1}{\sin \theta})}{(\frac{1}{\cos \theta}+\frac{\sin \theta}{\cos \theta})(1-\sin \theta)}$
$=\frac{(\frac{\cos \theta+\sin \theta+1}{\cos \theta})(\frac {\sin \theta+\cos \theta-1}{\sin \theta})}{(\frac{1+\sin \theta}{\cos \theta})(1-\sin \theta)}$
$=\frac{(\cos \theta+\sin \theta+1)(\sin \theta+\cos \theta-1)}{\sin \theta(1-\sin \theta)}$
$=\frac{(\cos \theta+\sin \theta)^2-1}{\sin \theta\cos^2

18 Views

Question : Directions: Select the option that represents the correct order of the given words as they would appear in an English dictionary.
1. Subtract
2. Submerge
3. Subside
4. Submit
5. Subscribe
6. Subtle

Option 1: 245361

Option 2: 423561

Option 3: 425361

Option 4: 243561

Team Careers360 22nd Jan, 2024

Correct Answer: 245361


Solution : Given:
1. Subtract 2. Submerge 3. Subside 4. Submit 5. Subscribe 6. Subtle

Step 1: The first three letters of each word are same – s, u, b, so move to the next letter.
Step 2: The fourth letter of each word is – t,

26 Views

Question : Directions: Select a suitable figure from the answer figures that would replace the question mark (?).

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 22nd Jan, 2024

Correct Answer:


Solution : According to the given figures –
1. The diamond-shaped figure and the circles inside and outside rotate by 90° in the anti-clockwise direction.
2. The number of circles around the diamond-shaped figure inside each box decreases by 1.
So, following the above pattern, the required figure

14 Views

Question : If $x+\frac{1}{x}=2 \cos \theta$, then $x^3+\frac{1}{x^3}=?$

Option 1: $2 \cos 2θ$

Option 2: $\cos 3θ$

Option 3: $2 \cos 3θ$

Option 4: $\cos 2θ$

Team Careers360 22nd Jan, 2024

Correct Answer: $2 \cos 3θ$


Solution : Given: $x+\frac{1}{x}=2 \cos \theta$.
Cubing both sides, we get:
$⇒\left(x^3+\frac{1}{x^3}\right) + 3\left(x+\frac{1}{x}\right) = 8\cos^3 \theta$
Putting the values, we get:
$⇒x^3+\frac{1}{x^3} = 8\cos^3 \theta- 3(2 \cos \theta)$
$⇒x^3+\frac{1}{x^3}= 8\cos^3 \theta- 6 \cos \theta$
$⇒x^3+\frac{1}{x^3}=2(4\cos^3 \theta- 3 \cos \theta)$
$⇒x^3+\frac{1}{x^3}=2 \cos 3 \theta$
Hence,

20 Views

Question : If $\cot A=\frac{12}{5}$, then the value of $(\sin A+\cos A) \times \operatorname{cosec} A$ is_____.

Option 1: $\frac{13}{5}$

Option 2: $\frac{17}{5}$

Option 3: $\frac{14}{5}$

Option 4: 1

Team Careers360 21st Jan, 2024

Correct Answer: $\frac{17}{5}$


Solution : Given: $\cot A=\frac{12}{5}$
Now, $(\sin A+\cos A)×\operatorname{cosec}A$
$= (\sin A×\operatorname{cosec}A)+(\cos A×\operatorname{cosec}A)$
$= 1+\cot A$
$= (1+\frac{12}{5})$
$= \frac{17}{5}$
Hence, the correct answer is $\frac{17}{5}$.

14 Views

Question : If $l+m+n=9$ and $l^{2}+m^{2}+n^{2}=31$, then the value of $(lm+mn+nl )$ will be:

Option 1: 22

Option 2: 50

Option 3: 25

Option 4: –25

Team Careers360 22nd Jan, 2024

Correct Answer: 25


Solution : Given: $l^{2}+m^{2}+n^{2}=31$
And $l+m+n=9$
Squaring both sides,
$(l+m+n)^2=81$
⇒ $l^2+m^2+n^2+2(lm+mn+nl)= 81$
⇒ $31+2(lm+mn+nl) = 81$
⇒ $2(lm+mn+nl) = 81 – 31 = 50$
Thus, $(lm+mn+nl)=\frac{50}{2}=25$
Hence, the correct answer is 25.

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