All Questions

Staff Selection Commission Combined Graduate Level Exam

Follow
Showing 4801 - 4810 out of 16717 Questions
19 Views

Question : Directions: By interchanging the given two signs and numbers which of the following equations will be not correct?
× and ÷, 2 and 6
I. 7 – 4 × 3 ÷ 6 + 2 = 8
II. 6 – 8 × 2 + 9 ÷ 3 = 5

Option 1: Only II

Option 2: Neither I nor II

Option 3: Only I

Option 4: Both I and II

Team Careers360 25th Jan, 2024

Correct Answer: Both I and II


Solution : Given:
I. 7 – 4 × 3 ÷ 6 + 2 = 8
II. 6 – 8 × 2 + 9 ÷ 3 = 5

Let's check each equation after interchanging signs and numbers according to the instructions.
On interchanging the signs

14 Views

Question : Select the option that is similar in meaning to the underlined word.

He gave a concise explanation of the company's retirement plan.

Option 1: Clear

Option 2: Verbose

Option 3: Terse

Option 4: Sharp

Team Careers360 24th Jan, 2024

Correct Answer: Terse


Solution : The third option is correct.

Concise means giving a lot of information clearly and in a few words; it's brief but comprehensive. Terse also means using few words and often seeming rude or unfriendly because you are not saying very much, which is similar to

20 Views

Question : Which German chemist and physicist proposed that an aromatic compound must have an odd number of pairs of electrons, Which can mathematically be written as 4n+2 (n=0,1,2,3, etc.) in 1931?

Option 1: Friedrich Kekule

Option 2: Rosalind Franklin

Option 3: Erich Huckel

Option 4: Antoine Lavoisier

Team Careers360 19th Jan, 2024

Correct Answer: Erich Huckel


Solution : The correct option is Erich Huckel.

German scientist and physicist Erich Huckel put up a theory in 1931 to assist in identifying whether an aromatic property would be present in a planar ring molecule. According to his rule, an aromatic, cyclic, planar molecule

53 Views

Question : Three circles of radius 6 cm are kept touching each other. The string is tightly tied around these three circles. What is the length of the string?

Option 1: $36 + 12\pi\ \text{cm}$

Option 2: $36 + 18\pi\ \text{cm}$

Option 3: $24 + 36\pi\ \text{cm}$

Option 4: $36 + 20\pi\ \text{cm}$

Team Careers360 20th Jan, 2024

Correct Answer: $36 + 12\pi\ \text{cm}$


Solution :
The length of the string not in contact with the circle = $2r+2r+2r=6r=6\times6=36$
By symmetry, the angle swiped by the string on one circle = $120^\circ$
Length of the string touching circle = $\frac{2\pi r}{3}+\frac{2\pi r}{3}+\frac{2\pi r}{3}=\frac{6\pi r}{3} = 2\pi r$
$=2\pi

11 Views

Question : Which law was based on notes of the music?

Option 1: Newton law

Option 2: Law of octaves

Option 3: Mendeleev law

Option 4: Modern periodic law

Team Careers360 25th Jan, 2024

Correct Answer: Law of octaves


Solution : The correct option is the Law of octaves.

The "Law of Octaves" in the context of chemistry was a concept that drew an analogy to the musical scale. In the Law of Octaves, Mendeleev noted that when elements were arranged by increasing

15 Views

Question : The circumference of the two circles is 308 cm and 440 cm, respectively. What is the difference between their radii?

Option 1: 21 cm

Option 2: 49 cm

Option 3: 35 cm

Option 4: 14 cm

Team Careers360 24th Jan, 2024

Correct Answer: 21 cm


Solution : Let the radius of the first circle be $r_1$.
Circumference of the first circle $=2\pi r{_1}$
⇒ $308 = 2×\frac{22}{7}×r{_1}$
⇒ $r_1$ = 49 cm
Let the radius of the 2nd circle be $r_2$.
Circumference of the 2nd circle $=2\pi r{_2}$
⇒ $440 =

8 Views

Question : Directions: In the following question a series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series.
4, 12, 48, 240, 1440, ?

Option 1: 7620

Option 2: 10080

Option 3: 6200

Option 4: 10020

Team Careers360 20th Jan, 2024

Correct Answer: 10080


Solution : Given:
4, 12, 48, 240, 1440, ?

Multiply the numbers of the given series by consecutive natural numbers starting from 3.
4 × 3 = 12; 12 × 4 = 48; 48 × 5 = 240; 240 × 6 = 1440; 1440 × 7 =

The question have been saved in answer later, you can access it from your profile anytime. Access now