Staff Selection Commission Combined Graduate Level Exam
Question : The following sentence has been divided into parts. One of them may contain an error. Select the part that contains the error from the given options. If you don't find any error, mark 'No error' as your answer.
Darshan wished he hadn't / went to the theme park / in the first place.
Option 1: Darshan wished he hadn't
Option 2: in the first place
Option 3: went to the theme park
Option 4: No error
Correct Answer: went to the theme park
Solution : The correct choice is the third option.
The reason for the error is related to the use of the past participle form of the verb after "hadn't". In English, when forming the past perfect tense, the auxiliary verb "had" is followed
Question : Select the option that expresses the given sentence in passive voice.
The little boy called up his best friend on his birthday.
Option 1: His best friend has been called up by the little boy on his birthday.
Option 2: His best friend was called up by the little boy on his birthday.
Option 3: His best friend is called up by the little boy on his birthday.
Option 4: His best friend was being called up by the little boy on his birthday.
Correct Answer: His best friend was called up by the little boy on his birthday.
Solution : The correct choice is the second option.
Passive voice is the voice in which the object experiences an action rather than the person who performs the action. Hence, the object in the
Question : Directions: Select the correct mirror image of the given figure when the mirror is placed on the right side of the figure.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : As per the mirror image properties, closer things appear closer to the mirror in the reflection. Here, according to the information provided, the mirror is placed at the right of the figure. So, the left of the reflected image will appear as the right and the
Question : When xm is multiplied by xn product is 1. The relation between m and n is:
Option 1: mn = 1
Option 2: m = n
Option 3: m + n = 1
Option 4: m = – n
Correct Answer: m = – n
Solution : xm × xn = 1 ⇒ xm + n = x0 ⇒ m + n = 0 ⇒ m = –n Hence, the correct answer is m = – n.
Question : If $x+\frac{1}{x}=5$, then the value of $\frac{x}{1+x+x^2}$ is:
Option 1: $\frac{1}{5}$
Option 2: $\frac{1}{6}$
Option 3: $5$
Option 4: $6$
Correct Answer: $\frac{1}{6}$
Solution : Given: $x+\frac{1}{x}=5$ Now, $\frac{x}{1+x+x^2}$ Divide the above expression by $x$ in numerator and denominator, ⇒ $\frac{1}{\frac{1}{x}+1+x}$ $=\frac{1}{x+\frac{1}{x}+1}$ $=\frac{1}{5+1}=\frac{1}{6}$ Hence, the correct answer is $\frac{1}{6}$.
Question : Which of the following countries will host the para-badminton championship in 2023?
Option 1: China
Option 2: India
Option 3: Thailand
Option 4: Indonesia
Correct Answer: Thailand
Solution : The correct answer is Thailand.
Thailand will host the Para Badminton World Championship in 2023 according to the Badminton World Federation (BWF). From October 1st through October 8th, 2023, the event will be hosted in Pattaya, Thailand. The Para Badminton World Championships is the world's
Question : If $\cos\left(40^\circ+x\right)=\sin 30^\circ$, then the value of $x$ is:
Option 1: $22^\circ$
Option 2: $20^\circ$
Option 3: $19^\circ$
Option 4: $23^\circ$
Correct Answer: $20^\circ$
Solution : $\cos \left(40^\circ+x\right)=\sin 30^\circ$ ....(1) Now we know that $\sin(90^\circ -x)= \cos x^\circ$ $\therefore$ Equation (1) becomes ⇒ $\cos \left(40^\circ+x\right)=\sin (90^\circ-60^\circ)$ ⇒ $\cos \left(40^\circ+x\right)=\cos 60^\circ$ ⇒ $(40^\circ+x) = 60^\circ$ $\therefore x=20^\circ$ Hence, the correct answer is $20^\circ$.
Question : Identify the freedom fighter who, as a child, hated going to school and found it suffocating and oppressive.
Option 1: Mahatma Gandhi
Option 2: Jawaharlal Nehru
Option 3: Jyotiba Phule
Option 4: Rabindranath Tagore
Correct Answer: Rabindranath Tagore
Solution : The correct option is Rabindranath Tagore.
Rabindra Nath Tagore was a Bengali poet who hated going to school. He got the Nobel Prize in 1913 for his work on Gitanjali. This makes him the first non-European to receive the award. He wrote a
Question : The 3rd and 8th terms of an Arithmetic progression are –14 and 1, respectively. What is the 11th term?
Option 1: 14
Option 2: 16
Option 3: 20
Option 4: 10
Correct Answer: 10
Solution : Given: The 3rd and 8th terms of an Arithmetic progression are –14 and 1. Formula for $n^{th}$ term ⇒ $a +(n-1)d$, where $a$ = 1st term, $d$ = common difference and $n$ = number of terms $3^{rd}$ term ⇒ $a +(3-1)d=–14$ ⇒
Question : Two chords $\mathrm{AB}$ and $\mathrm{CD}$ of a circle with centre $\mathrm{O}$, intersect each other at $\mathrm{P}$. If $\angle\mathrm{ AOD}=100^{\circ}$ and $\angle \mathrm{BOC}=70^{\circ}$, then the value of $\angle \mathrm{APC}$ is:
Option 1: $80^{\circ}$
Option 2: $75^{\circ}$
Option 3: $85^{\circ}$
Option 4: $95^{\circ}$
Correct Answer: $95^{\circ}$
Solution :
In the given problem, $\angle \mathrm{AOD}$ and $\angle \mathrm{BOC}$ are angles subtended by the chords $\mathrm{AB}$ and $\mathrm{CD}$ at the centre of the circle. The angle subtended by a chord at the centre is twice the angle subtended by it at any point on the
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