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Staff Selection Commission Combined Graduate Level Exam

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Question : Who became the first woman officer to join the Army Aviation Corps as a Combat Aviator after the successful completion of training in May 2022?

Option 1: Captain Abhilasha Barak

Option 2: Captain Shiva Chauhan

Option 3: Captain Gursimran Kaur

Option 4: Captain Manju Sharma

Team Careers360 22nd Jan, 2024

Correct Answer: Captain Abhilasha Barak


Solution : The correct option is Captain Abhilasha Barak.

After completing her training successfully, Captain Abhilasha Barak became the first female officer to join the Army Aviation Corps as a combat aviator. One of the Army's components, the Army Aviation Corps, was established in

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Question : Which Constitutional Amendment Act deals with the disqualification of MPs and MLAs?

Option 1: 42nd Amendment Act

Option 2: 52nd Amendment Act

Option 3: 62nd Amendment Act

Option 4: 32nd Amendment Act

Team Careers360 20th Jan, 2024

Correct Answer: 52nd Amendment Act


Solution : The correct option is the 52nd Amendment Act.

The Tenth Schedule of the Indian Constitution, also referred to as the "Anti-Defection Law", primarily governs the disqualification of Members of Parliament (MPs) and Members of Legislative Assemblies (MLAs) in India. The 52nd Amendment

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Question : Which fraction among the following is the least?
$\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}$

Option 1: $\frac{5}{11}$

Option 2: $\frac{7}{12}$

Option 3: $\frac{9}{17}$

Option 4: $\frac{8}{13}$

Team Careers360 25th Jan, 2024

Correct Answer: $\frac{5}{11}$


Solution : Given: The fractions are $\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}$.
Determine which fraction is the smallest by converting the fractions to decimals.
$\frac{5}{11}=0.4545, \frac{7}{12}=0.5833, \frac{8}{13}=0.6153, \frac{9}{17}=0.5294$
So, $\frac{5}{11}$ is the least fraction.
Hence, the correct answer is $\frac{5}{11}$.

10 Views

Question : The sum of three fractions is $2\frac{11}{24}$. On dividing the largest faction by the smallest fraction, $\frac{7}{6}$ is obtained which is $\frac{1}{3}$ greater than the middle fraction. The smallest fraction is:

Option 1: $\frac{5}{8}$

Option 2: $\frac{3}{4}$

Option 3: $\frac{5}{6}$

Option 4: $\frac{3}{7}$

Team Careers360 21st Jan, 2024

Correct Answer: $\frac{3}{4}$


Solution : Let the largest fraction be $x$, the middle fraction be $y$ and the smallest fraction be $z$.
From the question, on dividing the largest fraction by the smallest fraction i.e. $\frac{x}{z}=\frac{7}{6}⇒x=\frac{7}{6}z$
Now, the middle fraction is $\frac{1}{3}$ more than $\frac{7}{6}$.
$ y=\frac{7}{6}-\frac{1}{3 }=\frac{5}{6}$
Putting the

17 Views

Question : In a right triangle for an acute angle $x$, if $\sin x=\frac{3}{7}$, then find the value of $\cos x$.

Option 1: $\frac{2}{7}$

Option 2: $\frac{3}{4}$

Option 3: $\frac{1}{\sqrt{3}}$

Option 4: $\frac{2\sqrt{10}}{7}$

Team Careers360 21st Jan, 2024

Correct Answer: $\frac{2\sqrt{10}}{7}$


Solution : Given that, it is a right-angle triangle with an acute angle $x$.
$\therefore$ Angle $x$ lies between $0$ to $\frac{\pi}{2}$
Given: $\sin x=\frac{3}{7}$
Squaring both sides,
$\sin^2 x=\frac{9}{49}$
Since $\sin^2 x+ \cos^2 x=1$,
So, $\cos^2 x=1-\frac{9}{49}$
⇒ $\cos x =\frac{2\sqrt {10}}{7}$
Hence, the correct answer

19 Views

Question : In INR 150, B buys 10 pens for INR 8 each, 10 erasers for INR 5 each and some sharpeners for INR 4 each. What is the average price per item in INR?

Option 1: 8

Option 2: 7

Option 3: 10

Option 4: 6

Team Careers360 23rd Jan, 2024

Correct Answer: 6


Solution : Let $x$ be the number of sharpeners he buys.
According to the question,
$10\times 8 + 10\times 5 + x\times 4 = 150$
⇒ $80+50+4x = 150$
⇒ $4x = 150 - 130 = 20$
$\therefore x = 5$
Average price of per item =

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Question : Solve the following: 22 – [9 – {6 – (10 – 4 + 3 )}] ÷ 2 × 3

Option 1: 12

Option 2: 4

Option 3: 3

Option 4: 20

Team Careers360 19th Jan, 2024

Correct Answer: 4


Solution : 22 – [9 – {6 – (10 – 4 + 3 )}] ÷ 2 × 3
= 22 – [9 – {6 – (9)}] ÷ 2 × 3
= 22 – [9 + 3] ÷ 2 × 3
= 22 – [12] ÷ 2 ×

18 Views

Question : A wholesaler had 200 dozen of mangoes. He sold some of these mangoes at 20% profit and the rest at 10% profit so he made 13% profit on selling all the mangoes. How many mangoes (in dozens) did he sell at 20% profit?

Option 1: 140

Option 2: 60

Option 3: 80

Option 4: 120

Team Careers360 20th Jan, 2024

Correct Answer: 60


Solution : Let the number of dozens of mangoes sold at $20\%$ profit as $x$ and the number of dozens sold at $10\%$ profit as $(200 - x)$.
Given that the wholesaler made a total profit of $13\%$ on selling all the mangoes.
⇒ $0.20x + 0.10(200

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