Staff Selection Commission Combined Graduate Level Exam
Question : Directions: Study the given pattern carefully and select the number that can replace the question mark (?) in it. (NOTE; Operation should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g. 13- operations on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.)
Option 1: 7
Option 2: 5
Option 3: 13
Option 4: 9
Correct Answer: 7
Solution : Subtract the number of column 2 from column one and divide the resultant by 3 to get the required missing number –
In the first row: (14 – 5) ÷ 3 = 9 ÷ 3 = 3 In the second row: (24 – 3) ÷
Question : What is the value of S $=\frac{1}{1×3×5}+\frac{1}{1×4}+\frac{1}{3×5×7}+\frac{1}{4×7}+\frac{1}{5×7×9}+\frac{1}{7×10}+....$ Up to 20 terms, then what is the value of S?
Option 1: $\frac{6179}{15275}$
Option 2: $\frac{6070}{14973}$
Option 3: $\frac{7191}{15174}$
Option 4: $\frac{5183}{16423}$
Correct Answer: $\frac{6070}{14973}$
Solution : Given: $S=\frac{1}{1×3×5}+\frac{1}{1×4}+\frac{1}{3×5×7}+\frac{1}{4×7}+\frac{1}{5×7×9}+\frac{1}{7×10}+....$ Up to 20 terms. Rewriting it like, $\frac{1}{1×3×5}+\frac{1}{3×5×7}+\frac{1}{5×7×9}+...+\frac{1}{1×4}+\frac{1}{4×7}+\frac{1}{7×10}+...$Up to 20 terms. $=\frac{1}{4}[\frac{1}{1×3}-\frac{1}{3×5}+\frac{1}{3×5}-\frac{1}{5×7}+\frac{1}{5×7}-\frac{1}{7×9}+...–\frac{1}{21×23}]+\frac{1}{3}[1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...-\frac{1}{31}]$ It will cancel out most of the terms except the first and last term. $=\frac{1}{4}[\frac{1}{1×3}-\frac{1}{21×23}]+\frac{1}{3}[1-\frac{1}{31}]$ $=\frac{40}{483}+\frac{10}{31}$ $=\frac{6070}{14973}$ Hence, the correct answer is $\frac{6070}{14973}$.
Question : Directions: In the question, a part of the sentence is in bold. Below are given alternatives to the bold part at (1), (2), and (3) that may improve the sentence. Choose the correct alternative. In case no improvement is needed, your answer is (4).
Because that there were heavy rains the lake was flooded.
(1) Because of the
(2) As there were
(3) Since there was
(4) No Improvement
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (1)
Solution : The correct answer is the first option.
In the sentence "because of the heavy rains, the lake was flooded," the phrase because of the is used to explain why the lake was flooded. It clearly and concisely indicates that heavy rains were the cause of
Question : Which of the following countries hosted the first edition of the Summer Youth Olympic Games in 2010?
Option 1: China
Option 2: Singapore
Option 3: Argentina
Option 4: Senegal
Correct Answer: Singapore
Solution : The correct answer is Singapore.
Inspired by the Olympic Games, the summit conference of young Olympians with talent happens every four years. In 2010, Singapore hosted the first event, and in 2012, Innsbruck hosted the first-ever winter version. Singapore participated in the 2010 Summer Youth
Question : Directions: Which of the following letter clusters should replace # and % so that the pattern and relationship followed between the letter-cluster pair on the left side of :: is the same as that on the right side of ::? # : KNE :: PQV : %
Option 1: # = NOB, % = SRY
Option 2: # = NKF, % = MTU
Option 3: # = MOB, % = RTT
Option 4: # = HQD, % = MTV
Correct Answer: # = NKF, % = MTU
Solution : Given: # : KNE :: PQV : %
Let's check the options – First option: # = NOB, % = SRY NOB : KNE→N – 3 = K; O – 1 = N; B + 3 = E PQV :
Question : Who is called the "Greatest Investigator of antiquity" ?
Option 1: Aristotle
Option 2: Darwin
Option 3: Cuvier
Option 4: Socrates
Correct Answer: Darwin
Solution : Correct Answer is Darwin
In the 1850s, Charles Darwin penned the controversial and influential book On the Origin of Species. He founded the scientific theory that the process he called "natural selection" produced the branching pattern of evolution .The discovery of human antiquity, which served
Question : Which of the following is not correct about the eligibility criteria for being elected as Vice President of India?
Option 1: He/She should be a citizen of India.
Option 2: He/She should have completed 35 years of age.
Option 3: He/She should not hold any office of profit under the Union government/state government or any subordinate local authority.
Option 4: He/She should be qualified for election as a member of the Lok Sabha.
Correct Answer: He/She should be qualified for election as a member of the Lok Sabha.
Solution : The correct option is He/She should be qualified for election as a member of the Lok Sabha.
The Vice President of India is not required to be qualified for election as a member
Question : Rowlatt Act 1919 was enacted during the period of
Option 1: Lord Chelmsford
Option 2: Lord William
Option 3: Lord Minto
Option 4: Lord Bentinck
Correct Answer: Lord Chelmsford
Solution : The Correct Answer is Lord Chelmsford
The Act's implementation included harsh and unfair restrictions on Indian citizens who were suspected of engaging in acts of nationalist terrorism. The Rowlatt Act, also called the Anarchical and Revolutionary Crimes Act of 1919, is a law that
Question : Which type of democracy do we follow in India?
Option 1: Direct
Option 2: Presidential
Option 3: Representative
Option 4: Dictatorship
Correct Answer: Representative
Solution : The correct answer is Representative.
Democracy can take one of two forms. The first type of democracy is direct democracy, and the second and more popular type is representative democracy. A representative democracy exists in India. India practices indirect democracy. In an indirect democracy,
Question : $D$ and $E$ are points on the sides $AB$ and $AC$ respectively of $\triangle ABC$ such that $DE$ is parallel to $BC$ and $AD: DB = 4:5$, $CD$ and $BE$ intersect each other at $F$. Find the ratio of the areas of $\triangle DEF$ and $\triangle CBF$.
Option 1: $16:25$
Option 2: $16:81$
Option 3: $81:16$
Option 4: $4:9$
Correct Answer: $16:81$
Solution : In $\triangle ADE$ and $\triangle ABC$ $\angle AED=\angle C$ (corresponding angle) $\angle ADE=\angle B$ (corresponding angle) $\angle A=\angle A$ (common angle) $\triangle ADE\sim\triangle ABC$ (by AAA criteria) $\frac{AD}{AB}=\frac{AE}{AC}=\frac{DE}{BC}=\frac{4}{9}$ In $\triangle DEF$ and $\triangle BFC$ $\angle EDF=\angle BCF$ (alternate interior angle) $\angle DEF=\angle CBF$ (alternate interior
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