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Staff Selection Commission Combined Graduate Level Exam

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Question : Who was associated with the foundation of the Fergusson College?

Option 1: Dadabhai Naoroji

Option 2: Gopal Krishna Gokhale

Option 3: Lala Lajpat Rai

Option 4: Bal Gangadhar Tilak

Team Careers360 20th Jan, 2024

Correct Answer: Bal Gangadhar Tilak


Solution : The correct option is Bal Gangadhar Tilak.

Bal Gangadhar Tilak was associated with the foundation of Fergusson College. Fergusson College is located in Pune, India, and it was established in 1885 by the Deccan Education Society, of which Bal Gangadhar Tilak was a

13 Views

Question : Directions: In the following question, find the odd number pair from the given alternatives.

Option 1: 1 : 8

Option 2: 27 : 64

Option 3: 125 : 218

Option 4: 343 : 512

Team Careers360 14th Jan, 2024

Correct Answer: 125 : 218


Solution : Let's check the options –
First option: 1 – 8→13 = 1; 23 = 8 
Second option: 27 – 64→ 33 = 27; 43 = 64
Third option: 125 – 218→ 53 = 125; 63 = 216

13 Views

Question : What is the surface area (in cm²) of a spherical sculpture whose radius is 35 cm?
(Take $\pi=\frac{22}{7}$)

Option 1: 16540

Option 2: 15700

Option 3: 15400

Option 4: 14500

Team Careers360 21st Jan, 2024

Correct Answer: 15400


Solution : The radius of spherical sculpture, $r$ = 35 cm
Surface area of sphere = $4\pi r^2$
= $4×\frac{22}{7}×{35}^2$
= 15400 cm2
Hence, the correct answer is 15400.

15 Views

Question : At what rate percent per annum will a sum of INR 15, 625 amount to INR 21, 952 in three years, if the interest is compounded annually?

Option 1: 12%

Option 2: 8%

Option 3: 9%

Option 4: 10%

Team Careers360 22nd Jan, 2024

Correct Answer: 12%


Solution : Principal (P) = INR 15, 625
Time (T) = 3 years
Amount (A) = INR 21, 952
Amount = $P(1 + \frac{R}{100})^T$
Let the rate of interest per annum be $R$.
21952 = 15625$(1 + \frac{R}{100})^3$
⇒ $\frac{21952}{15625} = (1 + \frac{R}{100})^3$
⇒ $\sqrt[3]{(\frac{21952}{15625})} =

310 Views

Question : A policeman noticed a thief from 300 m. The thief started running and the policeman was chasing him. The thief and the policeman ran at speeds of 8 km/h and 9 km/h, respectively. What was the distance between them after 3 minutes?

Option 1: 225 m

Option 2: 250 m

Option 3: 300 m

Option 4: 200 m

Team Careers360 21st Jan, 2024

Correct Answer: 250 m


Solution : Given: Distance between the policeman and the thief = 300 m
Speed of the policeman = 9 km//h = $9×\frac{5}{18}=\frac{5}{2}$ m/s
Speed of the thief = 8 km//h = $8×\frac{5}{18}=\frac{20}{9}$ m/s
Relative speed of the policeman and the thief = 9 – 8 =

5 Views

Question : $\frac{\sin ^2 \theta}{\cos \theta(1+\cos \theta)}+\frac{1+\cos \theta}{\cos \theta}=$?

Option 1: $\operatorname{cosec}\theta$

Option 2: $\sec\theta$

Option 3: $2\cos\theta$

Option 4: $2\sec\theta$

Team Careers360 22nd Jan, 2024

Correct Answer: $2\sec\theta$


Solution : $\frac{\sin ^2 \theta}{\cos \theta(1+\cos \theta)}+\frac{1+\cos \theta}{\cos \theta}$
$=\frac{1-\cos ^2 \theta}{\cos \theta(1+\cos \theta)}+\frac{1+\cos \theta}{\cos \theta}$
$=\frac{(1-\cos \theta)(1+\cos \theta)}{\cos \theta(1+\cos \theta)}+\frac{1+\cos \theta}{\cos \theta}$
$=\frac{1-\cos  \theta}{\cos \theta}+\frac{1+\cos \theta}{\cos \theta}$
$=\frac{1-\cos  \theta+1+\cos \theta}{\cos \theta}$
$=\frac{2}{\cos \theta}$
$=2\sec\theta$
Hence, the correct answer is $2\sec\theta$.

12 Views

Question : If a + b = 5 and a – b = 3, then the value of (a2 + b2) is:

Option 1: 17

Option 2: 18

Option 3: 19

Option 4: 20

Team Careers360 14th Jan, 2024

Correct Answer: 17


Solution : Given:
a + b = 5 -----------------------(i)
a – b = 3 ----------------------(ii)
Add both equations (i) and (ii),
⇒ a + b + a – b =  5 + 3
⇒ 2a = 8
⇒ a = 4
From equation (i),
⇒ 4 +

8 Views

Question : If, after giving a discount of 18%, a book is sold for Rs. 1,599, what will be the marked price (in Rs.) of the book?

Option 1: 1,800

Option 2: 1,880

Option 3: 1,950

Option 4: 2,000

Team Careers360 16th Jan, 2024

Correct Answer: 1,950


Solution : Given: After giving a discount of 18%, a book is sold for Rs. 1,599.
Let the Marked Price be 100 units.
So, after an 18% discount the Selling Price = (100 – 18) = 82 units
Here, 82 units are equivalent to Rs. 1,599.
So,

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