Staff Selection Commission Combined Graduate Level Exam
Question : Find the value of the given expression: $10 \div 5 × 1+3 - [8 - \{5 - (7 - 7 - 9)\}]$
Option 1: 11
Option 2: 10
Option 3: 9
Option 4: 8
Correct Answer: 11
Solution : Given: 10 ÷ 5 × 1 + 3 – [8 – {5 – (7 – 7 – 9)}] Using the BODMAS rule, we get, = 10 ÷ 5 × 1 + 3 – [8 – {5 – ( –9)}] = 10 ÷ 5 × 1
Question : Directions: Select the figure that will replace the question mark (?) in the following figure series.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : According to the given figure series, in every alternate box, the geometrical figures/ letters/ numbers at certain positions shift their position following the below pattern – 1. Box 1 to box 2 and box 3 to box 4 follow the same pattern. 2. Box 2 to
Question : The compound in which a hydroxy group, -OH, is attached to a saturated carbon atom which has two other carbon atoms attached to it is called:
Option 1: aldehyde
Option 2: tertiary alcohol
Option 3: secondary alcohol
Option 4: primary alcohol
Correct Answer: secondary alcohol
Solution : The correct option is secondary alcohol.
The compound in which a hydroxy group, -OH, is attached to a saturated carbon atom which has two other carbon atoms attached to it is called secondary alcohol. In secondary alcohols, the carbon atom bearing the hydroxy group
Question : The expression $\frac{\tan57°+\cot37°}{\tan33°+\cot53°}$ is equal to:
Option 1: $\tan33°\cot57°$
Option 2: $\tan57°\cot37°$
Option 3: $\tan33°\cot53°$
Option 4: $\tan53°\cot37°$
Correct Answer: $\tan57°\cot37°$
Solution : Given: $\frac{\tan57°+\cot37°}{\tan33°+\cot53°}$ = $\frac{\tan57°+\cot37°}{\tan(90°-57°)+\cot(90°-37°)}$ = $\frac{\tan57°+\cot37°}{\cot57°+\tan37°}$ = $\frac{\tan57°+\cot37°}{\frac{1}{\tan57°}+\frac{1}{\cot37°}}$ = $\tan57°\cot37°[\frac{\tan57°+\cot37°}{\tan57°+\cot37°}]$ = $\tan57°\cot37°$ Hence, the correct answer is $\tan57°\cot37°$.
Question : Directions: Which of the following interchanges of signs would make the given equation correct? 1000 – 448 + 14 ÷ 15 × 2 = 998
Option 1: + and ÷
Option 2: × and ÷
Option 3: – and +
Option 4: ÷ and –
Correct Answer: + and ÷
Solution : Given: 1000 – 448 + 14 ÷ 15 × 2 = 998
Let's check the options – First option: + and ÷ The equation becomes ⇒ 1000 – 448 ÷ 14 + 15 × 2 = 998 Solving the L.H.S. of the equation
Question : Directions: Select the set in which the numbers are related in the same way as the numbers of the following set. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g. 13 – operations on 13 such as adding /subtracting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is NOT allowed.) (21, 33, 31) (42, 17, 26)
Option 1: (36, 14, 35)
Option 2: (46, 19, 24)
Option 3: (35, 27, 29)
Option 4: (32, 39, 20)
Correct Answer: (36, 14, 35)
Solution : Given: (21, 33, 31) (42, 17, 26)
Adding all the numbers in the set – ⇒ (21, 33, 31)→21+ 33 + 31 = 85 ⇒ (42, 17, 26)→42 + 17 + 26 = 85
Let's check the options – First option: (36, 14,
Question : Direction: In this question, some equations are solved on the basis of a certain system. On the same basis find out the corrective alternative for the unsolved equation.
1 x 2 x 3 = 231
3 x 4 x 5 = 453
5 x 6 x 7 = ?
Option 1: 657
Option 2: 675
Option 3: 756
Option 4: 765
Correct Answer: 675
Solution : Here, the given equations follows a pattern in which the first number, the middle number and the last number in LHS becomes the units place digit , the hundreds place digit and the tens place digit in the answer part in RHS respectively.
⇒ 1
Question : In the following figure, if l || m, then find the measures of angles marked by a and b.
Option 1: a = 90$^{\circ}$ and b = 90$^{\circ}$
Option 2: a = 55$^{\circ}$ and b = 125$^{\circ}$
Option 3: a = 70$^{\circ}$ and b = 110$^{\circ}$
Option 4: a = 60$^{\circ}$ and b = 120$^{\circ}$
Correct Answer: a = 70$^{\circ}$ and b = 110$^{\circ}$
Solution : Since $l \parallel m$, ⇒ $\angle$ c = 110$^{\circ}$ (corresponding angles are equal) Also, $\angle$ a + $\angle$ c = 180$^{\circ}$ (supplementary angles) ⇒ $\angle$ a = 180$^{\circ}$ – 110$^{\circ}$ = 70$^{\circ}$ Now, $\angle$ b = $\angle$ a +
Question : Directions: Select the set in which the numbers are related in the same way as the numbers of the given set. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g. 13 – operations on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.) (6, 17, 408) (13, 27, 1404)
Option 1: (9, 27, 245)
Option 2: (17, 28, 952)
Option 3: (5, 82, 1200)
Option 4: (4, 26, 416)
Correct Answer: (4, 26, 416)
Solution : Given: (6, 17, 408); (13, 27, 1404)
Multiply the first and the second numbers and then multiply the resultant by four to get the third number of the triad. (6, 17, 408)→6 × 17 = 102; 102 × 4 = 408 (13, 27,
Question : Find the value of the given expression. $\sqrt{20-\sqrt{20-\sqrt{20-\sqrt{20-\cdots \infty}}}}$
Option 1: 4
Option 2: 6
Option 3: 5
Option 4: 2
Correct Answer: 4
Solution : Given expression, $\sqrt{20-\sqrt{20-\sqrt{20-\sqrt{20-\cdots \infty}}}}$ Let us equate this with $y$ ⇒ $y=\sqrt{20-\sqrt{20-\sqrt{20-\sqrt{20-\cdots \infty}}}}$ ⇒ $y=\sqrt{20-y}$ Squaring both sides, ⇒ $y^2=20-y$ ⇒ $y^2+y-20=0$ ⇒ $y^2+5y-4y-20=0$ ⇒ $y(y+5)-4(y+5)=0$ ⇒ $(y+5)(y-4)=0$ ⇒ $y=-5$ and $y=4$ Hence, the correct answer is 4.
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update
