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Staff Selection Commission Combined Graduate Level Exam

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Question : $\frac{(1+\sec \theta \operatorname{cosec} \theta)^2(\sec \theta-\tan \theta)^2(1+\sin \theta)}{(\sin \theta+\sec \theta)^2+(\cos \theta+\operatorname{cosec} \theta)^2}, 0^{\circ}<\theta<90^{\circ}$, is equal to:

Option 1: $1-\cos \theta$

Option 2: $1-\sin \theta$

Option 3: $\cos \theta$

Option 4: $\sin \theta$

Team Careers360 15th Jan, 2024

Correct Answer: $1-\sin \theta$


Solution : $\frac{(1+\sec \theta \operatorname{cosec} \theta)^2(\sec \theta-\tan \theta)^2(1+\sin \theta)}{(\sin \theta+\sec \theta)^2+(\cos \theta+\operatorname{cosec} \theta)^2}$
Since $ 0^{\circ}<\theta<90^{\circ}$.
$=\frac{(1+\frac{1}{\cos\theta.\sin\theta})^2(\frac{1}{cos\theta}-\frac{\sin\theta}{\cos\theta})^2 (1+\sin\theta)}{(\sin\theta+\frac{1}{\cos\theta})^2+(\cos\theta+\frac{1}{\sin\theta})^2}$
$=\frac{(\frac{\cos\theta.\sin\theta+1}{\cos\theta.\sin\theta})^2(\frac{1-\sin\theta}{\cos\theta})^2 (1+\sin\theta)}{(\frac{\sin\theta.\cos\theta+1}{\cos\theta})^2+(\frac{\cos\theta\sin\theta+1}{\sin\theta})^2}$
$=\frac{(\frac{1}{\cos\theta.\sin\theta})^2(\frac{1-\sin\theta}{\cos\theta})^2 (1+\sin\theta)}{\frac{\sin^2\theta+\cos^2\theta}{\sin^2\theta.\cos^2\theta}}$
$=\frac{(1-\sin\theta)(1-\sin\theta)(1+\sin\theta)}{\cos^2\theta}$
$=\frac{(1-\sin\theta)(1-\sin^2\theta)}{\cos^2\theta}$
$=\frac{(1-\sin\theta)(\cos^2\theta)}{\cos^2\theta}$
$=1-\sin\theta$
Hence, the correct answer is $1-\sin \theta$.

10 Views

Question : Directions: Arrange the following words as per order in the dictionary.
1. Nest 2. Neck 3. Neat 4. Near

Option 1: 4, 2, 3, 1

Option 2: 4, 2, 1, 3

Option 3: 4, 3, 2, 1

Option 4: 4, 1, 3, 2

Team Careers360 19th Jan, 2024

Correct Answer: 4, 3, 2, 1


Solution : Given:
1. Nest 2. Neck 3. Neat 4. Near

Step 1: Compare the first and second letters of each word. Since all the words have the same letter N and e, so move on to the next letter.
Step 2: The

13 Views

Question : An observer on the top of a mountain, 500 m above sea level, observes the angles of depression of the two boats in his same place of vision to be 45° and 30°, respectively. Then the distance between the boats, if the boats are on the same side of the mountain, is:

Option 1: 456 m

Option 2: 584 m

Option 3: 366 m

Option 4: 699 m

Team Careers360 25th Jan, 2024

Correct Answer: 366 m


Solution :
Given:
AB = Height of mountain = 500 m
$\angle$ACB = 30°; $\angle$ADB = 45°
C and D ⇒ Positions of boats
Let CD = $x$ m
Solution:
From $\triangle$ABD,
$\tan 45° = \frac{AB}{BD}$ 
⇒ AB = BD
⇒ AB = BD = 500

13 Views

Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No Error".

On last Sunday (1) / I met my friend (2) / accidentally. (3) / No Error (4)

Option 1: (1)

Option 2: (2)

Option 3: (3)

Option 4: (4)

Team Careers360 15th Jan, 2024

Correct Answer: (1)


Solution : The error lies in the first part of the sentence.

"On last Sunday" should be replaced with ''Last Sunday'', as it is more widely used to refer to the specific day and the use of the preposition "on" is not required. "Last Sunday" is a

16 Views

Question : If $2\left [x^{2} +\frac{1}{x^{2}}\right]-2\left [x-\frac{1}{x} \right]-8=0$, what are the two values of $\left (x-\frac{1}{x} \right)\;$?

Option 1: –1 or 2

Option 2: 1 or –2

Option 3: –1 or –2

Option 4: 1 or 2

Team Careers360 23rd Jan, 2024

Correct Answer: –1 or 2


Solution : Given: $2\left [x^{2} +\frac{1}{x^{2}} \right]-2\left [ x-\frac{1}{x} \right]-8=0$
$⇒2\left [(x -\frac{1}{x})^{2}+2 \right]-2\left [ x-\frac{1}{x} \right ]-8=0$
Let $(x -\frac{1}{x})=t$
The equation becomes $2(t^{2}+2)-2t-8=0$
$⇒2t^{2}-2t-4=0$
$⇒t^{2}-2t+t-1=0$
$⇒(t-2)(t+1)=0$
$⇒t=-1,2$
So, $(x -\frac{1}{x})=-1,2$
Hence, the correct answer is –1 or 2.

13 Views

Question : At the Rio Olympic , who was the flagbearer of the Indian contingent ?

Option 1: Narsingh Yadav 

Option 2: Abhinav Bindra

Option 3: Dipa Karmakar 

Option 4: Sania Mirza

Team Careers360 19th Jan, 2024

Correct Answer: Abhinav Bindra


Solution : The correct option is - Abhinav Bindra.

In his final Olympic appearance, Abhinav Bindra, the nation's first individual gold medalist, carried the Indian flag during the 2016 Summer Olympics in Rio. He has received the Padma Bhushan award from the Indian government.

9 Views

Question : Directions: In the following question, select the related number from the given alternatives.
6 : 42 :: 12 : ?

Option 1: 48

Option 2: 72

Option 3: 60

Option 4: 84

Team Careers360 18th Jan, 2024

Correct Answer: 84


Solution : Given:
6 : 42 :: 12 : ?

Like, 6 × 7 = 42
Similarly, 12 × 7 = 84

So, 84 is the required answer. Hence, the fourth option is correct.

42 Views

Question : Select the most appropriate ANTONYM of the given word.

Rebellion

Option 1: Uprising

Option 2: Loyalty

Option 3: Sedition

Option 4: Allotment

Team Careers360 19th Jan, 2024

Correct Answer: Loyalty


Solution : The correct choice is the second option.

Rebellion refers to someone who is fighting against authority or refusing to accept rules. Its antonym, loyalty, refers to the quality of being loyal. The meanings of both are contrasting with each other.

The meanings of

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