Staff Selection Commission Combined Graduate Level Exam
Question : $\frac{(1+\sec \theta \operatorname{cosec} \theta)^2(\sec \theta-\tan \theta)^2(1+\sin \theta)}{(\sin \theta+\sec \theta)^2+(\cos \theta+\operatorname{cosec} \theta)^2}, 0^{\circ}<\theta<90^{\circ}$, is equal to:
Option 1: $1-\cos \theta$
Option 2: $1-\sin \theta$
Option 3: $\cos \theta$
Option 4: $\sin \theta$
Correct Answer: $1-\sin \theta$
Solution : $\frac{(1+\sec \theta \operatorname{cosec} \theta)^2(\sec \theta-\tan \theta)^2(1+\sin \theta)}{(\sin \theta+\sec \theta)^2+(\cos \theta+\operatorname{cosec} \theta)^2}$ Since $ 0^{\circ}<\theta<90^{\circ}$. $=\frac{(1+\frac{1}{\cos\theta.\sin\theta})^2(\frac{1}{cos\theta}-\frac{\sin\theta}{\cos\theta})^2 (1+\sin\theta)}{(\sin\theta+\frac{1}{\cos\theta})^2+(\cos\theta+\frac{1}{\sin\theta})^2}$ $=\frac{(\frac{\cos\theta.\sin\theta+1}{\cos\theta.\sin\theta})^2(\frac{1-\sin\theta}{\cos\theta})^2 (1+\sin\theta)}{(\frac{\sin\theta.\cos\theta+1}{\cos\theta})^2+(\frac{\cos\theta\sin\theta+1}{\sin\theta})^2}$ $=\frac{(\frac{1}{\cos\theta.\sin\theta})^2(\frac{1-\sin\theta}{\cos\theta})^2 (1+\sin\theta)}{\frac{\sin^2\theta+\cos^2\theta}{\sin^2\theta.\cos^2\theta}}$ $=\frac{(1-\sin\theta)(1-\sin\theta)(1+\sin\theta)}{\cos^2\theta}$ $=\frac{(1-\sin\theta)(1-\sin^2\theta)}{\cos^2\theta}$ $=\frac{(1-\sin\theta)(\cos^2\theta)}{\cos^2\theta}$ $=1-\sin\theta$ Hence, the correct answer is $1-\sin \theta$.
Question : Directions: Arrange the following words as per order in the dictionary. 1. Nest 2. Neck 3. Neat 4. Near
Option 1: 4, 2, 3, 1
Option 2: 4, 2, 1, 3
Option 3: 4, 3, 2, 1
Option 4: 4, 1, 3, 2
Correct Answer: 4, 3, 2, 1
Solution : Given: 1. Nest 2. Neck 3. Neat 4. Near
Step 1: Compare the first and second letters of each word. Since all the words have the same letter N and e, so move on to the next letter. Step 2: The
Question : An observer on the top of a mountain, 500 m above sea level, observes the angles of depression of the two boats in his same place of vision to be 45° and 30°, respectively. Then the distance between the boats, if the boats are on the same side of the mountain, is:
Option 1: 456 m
Option 2: 584 m
Option 3: 366 m
Option 4: 699 m
Correct Answer: 366 m
Solution : Given: AB = Height of mountain = 500 m $\angle$ACB = 30°; $\angle$ADB = 45° C and D ⇒ Positions of boats Let CD = $x$ m Solution: From $\triangle$ABD, $\tan 45° = \frac{AB}{BD}$ ⇒ AB = BD ⇒ AB = BD = 500
Question : Directions: If A ÷ B means that A is the mother of B, A – B means that A is the father of B, and A + B means that A is the sister of B, then which of the following expressions shows that P is the mother of R?
Option 1: P + Q – R
Option 2: P ÷ Q + R
Option 3: P – R + Q
Option 4: Q + P – R
Correct Answer: P ÷ Q + R
Solution : Given: A ÷ B means that A is the mother of B, A – B means that A is the father of B, and A + B means that A is the sister of B.
Let's check the options – First
Question : Directions: Select the option that is related to the fifth letter cluster in the same way as the second letter cluster is related to the first letter cluster and the fourth letter cluster is related to the third letter cluster. CNY : GRC :: FRL : JVP :: ITK : ?
Option 1: MYO
Option 2: EOG
Option 3: MXO
Option 4: EPG
Correct Answer: MXO
Solution : Given: CNY : GRC :: FRL : JVP :: ITK : ?
Add 4 to the place value of each letter of CNY to get the required code – C + 4 = G; N + 4 = R; Y + 4 = C Thus,
Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No Error".
On last Sunday (1) / I met my friend (2) / accidentally. (3) / No Error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (1)
Solution : The error lies in the first part of the sentence.
"On last Sunday" should be replaced with ''Last Sunday'', as it is more widely used to refer to the specific day and the use of the preposition "on" is not required. "Last Sunday" is a
Question : If $2\left [x^{2} +\frac{1}{x^{2}}\right]-2\left [x-\frac{1}{x} \right]-8=0$, what are the two values of $\left (x-\frac{1}{x} \right)\;$?
Option 1: –1 or 2
Option 2: 1 or –2
Option 3: –1 or –2
Option 4: 1 or 2
Correct Answer: –1 or 2
Solution : Given: $2\left [x^{2} +\frac{1}{x^{2}} \right]-2\left [ x-\frac{1}{x} \right]-8=0$ $⇒2\left [(x -\frac{1}{x})^{2}+2 \right]-2\left [ x-\frac{1}{x} \right ]-8=0$ Let $(x -\frac{1}{x})=t$ The equation becomes $2(t^{2}+2)-2t-8=0$ $⇒2t^{2}-2t-4=0$ $⇒t^{2}-2t+t-1=0$ $⇒(t-2)(t+1)=0$ $⇒t=-1,2$ So, $(x -\frac{1}{x})=-1,2$ Hence, the correct answer is –1 or 2.
Question : At the Rio Olympic , who was the flagbearer of the Indian contingent ?
Option 1: Narsingh Yadav
Option 2: Abhinav Bindra
Option 3: Dipa Karmakar
Option 4: Sania Mirza
Correct Answer: Abhinav Bindra
Solution : The correct option is - Abhinav Bindra.
In his final Olympic appearance, Abhinav Bindra, the nation's first individual gold medalist, carried the Indian flag during the 2016 Summer Olympics in Rio. He has received the Padma Bhushan award from the Indian government.
Question : Directions: In the following question, select the related number from the given alternatives. 6 : 42 :: 12 : ?
Option 1: 48
Option 2: 72
Option 3: 60
Option 4: 84
Correct Answer: 84
Solution : Given: 6 : 42 :: 12 : ?
Like, 6 × 7 = 42 Similarly, 12 × 7 = 84
So, 84 is the required answer. Hence, the fourth option is correct.
Question : Select the most appropriate ANTONYM of the given word.
Rebellion
Option 1: Uprising
Option 2: Loyalty
Option 3: Sedition
Option 4: Allotment
Correct Answer: Loyalty
Solution : The correct choice is the second option.
Rebellion refers to someone who is fighting against authority or refusing to accept rules. Its antonym, loyalty, refers to the quality of being loyal. The meanings of both are contrasting with each other.
The meanings of
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