Staff Selection Commission Combined Graduate Level Exam
Question : A man rows to a place 48 km distance and comes back in 14 hours. He finds that he can row 4 km with the stream at the same time as 3 km against the stream. The speed of the stream is:
Option 1: 1.5 km/h
Option 2: 3.5 km/h
Option 3: 1.8 km/h
Option 4: 1 km/h
Correct Answer: 1 km/h
Solution : Suppose he moves 4 km downstream in $x$ hours. ⇒ Speed downstream =$\frac{4}{x}$ km/hr And, speed upstream =$\frac{3}{x}$ km/hr According to the question, $\frac{48}{\frac{4}{x}}+\frac{48}{\frac{3}{x}}=14$ ⇒ $\frac{48x}{4}+\frac{48x}{3}=14$ ⇒ $\frac{144x+192x}{12}=14$ ⇒ $336x=168$ ⇒ $x=\frac{168}{336}=\frac{1}{2}$ ⇒ Speed downstream = 8 km/hr And, speed upstream = 6 km/hr.
Question : If $x$ = ${\frac{1}{\sqrt{2}+1}}$, then the value of $(x^{2}+2x–1)$ is:
Option 1: $\sqrt[2]{2}$
Option 2: 4
Option 3: 0
Option 4: 2
Correct Answer: 0
Solution : Given: $x= {\frac{1}{\sqrt{2}+1}}$ Rationalising the denominator, we get, ⇒ $x ={\frac{{\sqrt{2}-1}}{(\sqrt{2}+1)×{(\sqrt{2}-1)}}}=\frac{\sqrt{2}-1}{2-1} = {\sqrt{2}-1}$ Putting this value in the expression $(x^{2}+2x-1)$, we get, $=[(\sqrt{2}-1)^{2}+2(\sqrt{2}-1)-1]$ $=2-2\sqrt{2}+1+2\sqrt{2}-2-1 $ $= 0$ Hence, the correct answer is 0.
Question : Directions: Select the correct combination of mathematical signs to sequentially replace the * signs and balance the given equation. 12 * 4 * 15 * 3 * 16 * 24
Option 1: +, –, ÷, ×, =
Option 2: –, +, ÷, ×, =
Option 3: ÷, –, +, ×, =
Option 4: ÷, +, ÷, +, =
Correct Answer: ÷, +, ÷, +, =
Solution : Given: 12 * 4 * 15 * 3 * 16 * 24
Replace * with the mathematical signs and solve the equations one by one using BODMAS. Let's check the given options – First option: +, –, ÷, ×, = ⇒
Question : What is the value of $\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}–\sqrt{5}} \div \frac{\sqrt{14}+\sqrt{10}}{\sqrt{14}–\sqrt{10}}+\frac{\sqrt{10}}{\sqrt{5}}$?
Option 1: $\sqrt{2}+2$
Option 2: $2 \sqrt{2}+2$
Option 3: $\sqrt{2}+1$
Option 4: $2 \sqrt{2}+1$
Correct Answer: $\sqrt{2}+1$
Solution : Given: The expression is $\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}–\sqrt{5}} \div \frac{\sqrt{14}+\sqrt{10}}{\sqrt{14}–\sqrt{10}}+\frac{\sqrt{10}}{\sqrt{5}}$. Take $\sqrt2$ common in the term $\frac{\sqrt{14}+\sqrt{10}}{\sqrt{14}–\sqrt{10}}$, we get, $\frac{\sqrt{14}+\sqrt{10}}{\sqrt{14}–\sqrt{10}}=\frac{\sqrt2}{\sqrt2}\times\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}–\sqrt{5}}=\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}–\sqrt{5}}$ The expression can be written as $\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}–\sqrt{5}} \div\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}–\sqrt{5}} +\frac{\sqrt{10}}{\sqrt{5}}$ = $\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}–\sqrt{5}} \times\frac{\sqrt{7}–\sqrt{5}}{\sqrt{7}+\sqrt{5}} +\frac{\sqrt{10}}{\sqrt{5}}$ = $1+\sqrt2$ = ${\sqrt{2}}+1$ Hence, the correct answer is ${\sqrt{2}}+1$.
Question : Who coined the word 'Geography'?
Option 1: Ptolemy
Option 2: Eratosthenese
Option 3: Hacatus
Option 4: Herodatus
Correct Answer: Eratosthenese
Solution : The correct answer is Erastothenese.
Erastothenese was a Greek astronomer, mathematician and philosopher. He was the first to used the word geography which meant Earth writing in Greek. He is also known as father of geography. He invented the system of latitudes and longitudes and
Question : Directions: Which of the following numbers will replace the question mark (?) in the given series? 382, 322, 272, 232, 202, ?
Option 1: 168
Option 2: 150
Option 3: 182
Option 4: 132
Correct Answer: 182
Solution : Given: 382, 322, 272, 232, 202, ?
Subtract the multiples of 10 (in decreasing order), starting from 60 from the previous number to obtain the following number of the series. 382 – 60 = 322; 322 – 50 = 272; 272 – 40 = 232;
Question : Aryabhata and Kalidasa were in the court of which Gupta Emperor?
Option 1: Kumaragupta I
Option 2: Chandragupta II
Option 3: Samudragupta
Option 4: Skandagupta
Correct Answer: Chandragupta II
Solution : The correct answer is Chandragupta II.
Chandragupta II, who was famously called Chandragupta Vikramaditya, served as a Gupta emperor. His royal assembly boasted the esteemed presence of both Aryabhata and Kalidasa. Among the nine pearls of Chandragupta's court was the celebrated Sanskrit writer Kalidasa.
Question : Who among the following is known as a pioneering dance educationist and a prominent Mohiniyattam exponent?
Option 1: Madhavi Mudgal
Option 2: Shagun Butani
Option 3: Mohanrao Kallianpurkar
Option 4: Dr. Kanak Rele
Correct Answer: Dr. Kanak Rele
Solution : The correct answer is Dr. Kanak Rele.
Kanak Rele was a prominent Indian dancer, choreographer, and academic renowned for her expertise in Mohiniyattam. She gained recognition not only for her contributions as a performer but also for her role as an advisor on
Question : Comprehension:
In the following passage, some words have been deleted. Read the passage carefully and select the most appropriate option to fill in each blank.
The phrase non-governmental or non-profit is commonly used to refer to the various organisations that (1)______ civil society. In general, such organisations are distinguished by the (2)______ that they operate for reasons other than financial gain. Surveys indicate that NGOs have a high degree of public (3)______, which can make them a useful proxy for the concerns of society and stakeholders. NGOs range from small pressure groups on specific environmental concerns or human rights (4)______, to educational charities, women's refuges, cultural associations, religious organisations, legal foundations, humanitarian assistance programmes – and the list could go on – to large international organisations with hundreds or even thousands of branches or members around the world.
Question:
Select the most appropriate option to fill in the blank number 4.
Option 1: evaluation
Option 2: discrimination
Option 3: prohibitions
Option 4: violations
Correct Answer: violations
Solution : The correct choice is the fourth option.
Explanation:
In the context of the sentence, the blank describes the range of activities or issues that NGOs address. The word that best fits in this context is violations. This term can encompass a broad spectrum of
Question : Directions: A sentence or a part of the sentence is printed in bold. Below are alternatives to the bold part that may improve the sentence. Choose the correct alternative. In case no improvement is needed, choose "No Improvement".
People should also look at the art to learn how to be creative, live creatively, and how to think outside of the box.
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 2
Solution : The sentence can be improved using the second option.
The phrase "how to think out of the box" is the correct and idiomatic expression. "Out of the box" is an established idiom that means thinking in an innovative, creative, or unconventional way. The correct form
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