Correct Answer: hostile

Solution : The correct choice is the third option.

The most appropriate antonym for affable is hostile, because affable denotes pleasant or friendly, while hostile means having very strong feelings against somebody or something.

The meanings of other options are as follows:

• Aggravate: It denotes

Correct Answer: JEOW

Solution : Given:
DMTS is related to FOVU and KGQO is related to MISQ.

Add 2 to the place value of each letter of DMTS and KGQO to obtain their respective codes –
DMTS→D + 2 = F; M + 2 = O; T + 2 =

Correct Answer: 2

Solution : The correct choice is the second option.

Explanation: When we express admiration or emphasise the quality of something, we often use the structure "What a [adjective] [noun]!". The addition of the article "a" in this case is grammatically correct and aligns with the pattern

Correct Answer: Brother

Solution : As per the given information, the family tree will be as follows –

Here, the quadrilateral represents the male, and the circular figure represents the female in the figure.

So, from the above family tree, E is the brother of G. Hence, the first option

Correct Answer:

$10\%$

Solution : Let the selling price of one orange = Re. 1
The selling price of 36 oranges = Rs. 36
Loss on 36 oranges = Rs. 4
The cost price of 36 oranges = 36 + 4 = Rs. 40
Loss percentage = $\frac{\text{Loss}}{\text {Cost Price}}$

Correct Answer: 64 – 4032

Solution : Let's check each option –
First option: (64 – 4032); 64² = 4096 ≠ 4032
Second option: (38 – 1444); 38² = 1444
Third option: (42 – 1764); 42² = 1764
Fourth option: (52 – 2704); 52² = 2704

Correct Answer: 33

Solution : Given:
183, 173, 153, 123, 83, ?

Subtract multiples of 10 to the previous number to obtain the next number.
183 – 10 = 173, 173 – 20 = 153, 153 – 30 = 123, 123 – 40 = 83, 83 – 50 = 33

Correct Answer: $\frac{13}{12},\frac{13}{5}$

Solution : Given, $\tan A=\frac{12}{5}$
$\tan A = \frac{\text{perpendicular}}{\text{base}}$
Using pythagoras theorem,
$\small\text{Hypotenuse}^2=\text{Base}^2+\text{Perpendicular}^2$
⇒ $h^2=5^2+12^2$
⇒ $h^2=25+144$
⇒ $h^2=169$
⇒ $h=13$
$\therefore$ $\operatorname{cosec A}=\frac{\text{Hypotenuse}}{\text{Perpendicular}}=\frac{13}{12}$
And, $\sec A=\frac{\text{Hypotenuse}}{\text{Base}}=\frac{13}{5}$
Hence, the correct answer is $\frac{13}{12},\frac{13}{5}$.

Correct Answer: $\sqrt2-\sqrt3$

Solution : Given: $\operatorname{cosec}\theta=\sqrt3$
$⇒\frac{1}{\sin\theta}=\sqrt3$
$⇒\sin\theta=\frac{1}{\sqrt3}$
We know that,
$\cos\theta = \sqrt{1-\sin^2\theta}=\sqrt{1-(\frac{1}{\sqrt3})^2}=\sqrt{1-\frac{1}{3}}=\sqrt\frac{2}{3}$
So, $\cot\theta-\operatorname{cosec}\theta$
$=\frac{\cos\theta}{\sin\theta}-\operatorname{cosec}\theta$
$=\frac{\sqrt\frac{2}{3}}{\frac{1}{\sqrt3}}-\sqrt3$
$=\sqrt\frac{2}{3}×\sqrt3-\sqrt3$
$=\sqrt2-\sqrt3$
Hence, the correct answer is $\sqrt2-\sqrt3$.

Correct Answer: ZDW

Solution : Given:
HPA, FMZ, DJY, BGX, ?

Here, subtract 2, 3, and 1 in the first, second, and third letters respectively to obtain the letters of the next term.
HPA→H – 2 = F; P – 3 = M; A – 1 = Z→FMZ
FMZ→F –