Staff Selection Commission Combined Higher Secondary Level Exam
Question : If in a $\triangle$ABC, D and E are on the sides AB and AC, such that, DE is parallel to BC and $\frac{AD}{BD}$ = $\frac{3}{5}$. If AC = 4 cm, then AE is:
Option 1: 1.5 cm
Option 2: 2.0 cm
Option 3: 1.8 cm
Option 4: 2.4 cm
Correct Answer: 1.5 cm
Solution : Given: $\frac{AD}{BD}$ = $\frac{3}{5}$ In $\triangle$ABC and $\triangle$DBE, $\angle$BAC = $\angle$DAE (same angle) $\angle$ADE = $\angle$ABC (corresponding angles) $\angle$AED = $\angle$ACB (corresponding angles) By AAA similarity, $\triangle$ABC ~ $\triangle$ADE ⇒ $\frac{AD}{AB}$ = $\frac{AD}{AD+BD}$ = $\frac{3}{3+5}$ = $\frac{3}{8}$ Now, $\frac{AD}{AB}$ = $\frac{AE}{AC}$ ⇒ $\frac{3}{8}$ =
Question : Who among the following was famously known as the "The parrot of India?"
Option 1: Amir Khusrau
Option 2: Lata Mangeshkar
Option 3: Pandit Ravishankar
Option 4: Kalidas
Correct Answer: Amir Khusrau
Solution : The correct answer is Amir Khusrau.
Amir Khusrau, originally named Amir Khusrau Dehlavi, was a renowned Indian Sufi singer and poet born in Patiala. Known as the 'Parrot of India,' he earned titles like the 'father of Urdu literature' and the 'voice of
Question : India’s First Open Rock Museum is located in which city?
Option 1: Varanasi
Option 2: Chennai
Option 3: Mysuru
Option 4: Hyderabad
Correct Answer: Hyderabad
Solution : The correct option is Hyderabad.
Located in Hyderabad, Telangana, India's first open rock museum features an array of about 35 rock types sourced from diverse regions of the country. These rocks showcase ages ranging from 3.3 billion to approximately 55 million years, representing various
Question : One-third part of a certain journey is covered at the speed of 10 km/hr, one-fourth part at the speed of 15 km/hr, and the rest part at the speed of 20 km/hr. What will be the average speed (in km/hr) for the whole journey?
Option 1: $15$
Option 2: $\frac{200}{17}$
Option 3: $\frac{240}{17}$
Option 4: $\frac{280}{17}$
Correct Answer: $\frac{240}{17}$
Solution : Let the total distance of the journey be $d$ km. One-third of the journey is covered at 10 km/hr, so the time taken is $\frac{d}{3 \times 10} $ hours. One-fourth of the journey is covered at 15 km/hr, so the time taken is $\frac{d}{4 \times
Question : _________ won the Japanese Formula 1 Grand Prix 2022.
Option 1: Charles Leclerc
Option 2: Sergio Perez
Option 3: Max Verstappen
Option 4: Carlos Sainz Jr.
Correct Answer: Max Verstappen
Solution : The correct option is Max Verstappen.
The winner of the Japanese Formula 1 Grand Prix 2022, held on October 9th, was Max Verstappen, driving for Red Bull. He secured his second World Championship title with this victory, a dramatic race featuring a late penalty
Question : Directions: Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series. A_DEFGI_ _LNOPQ_TUV_Y
Option 1: CJKSX
Option 2: CJKRW
Option 3: BJKRW
Option 4: BJKSX
Correct Answer: BJKSX
Solution : Given: A_DEFGI_ _LNOPQ_TUV_Y
To fill the series we have to divide the series – A_DE \ FGI_ \ _LNO \ PQ_T \ UV_Y Let's check each option — First option: CJKSX; ACDE \ FGIJ \ KLNO \ PQST \
Question : If $x^4+\frac{1}{x^4}=194, x>0$, then find the value of $x^3+\frac{1}{x^3}+x+\frac{1}{x}$
Option 1: 76
Option 2: 66
Option 3: 56
Option 4: 46
Correct Answer: 56
Solution : Given: $x^4+\frac{1}{x^4}=194$ $⇒x^4+\frac{1}{x^4}+2=194+2$ $⇒(x^2+\frac{1}{x^2})^2=196$ $⇒x^2+\frac{1}{x^2}=\sqrt{196}$ $⇒x^2+\frac{1}{x^2}=14$ $⇒x^2+\frac{1}{x^2}+2=14+2$ $⇒(x+\frac{1}{x})^2=16$ $⇒x+\frac{1}{x}=4$ -----------------------------(1) Now, $x^3+\frac{1}{x^3}=(x+\frac{1}{x})^3-3×x×\frac{1}{x}(x+\frac{1}{x})$ $⇒x^3+\frac{1}{x^3}=4^3-3 ×4$ $⇒x^3+\frac{1}{x^3}=52$--------------------------------(2) Therefore, $x^3+\frac{1}{x^3}+x+\frac{1}{x}$ = $52+4 = 56$ (from equations (1) and (2)) Hence, the correct answer is 56.
Question : Select the most appropriate option to substitute the underlined segment in the following sentence.
All colleagues of Rohit except Joseph have commemorated the elective courses they are planning to offer.
Option 1: have considered the elective courses
Option 2: have castigated the elective courses
Option 3: have constipated the elective courses
Option 4: have commiserated the elective courses
Correct Answer: have considered the elective courses
Solution : The correct choice is the first option.
The word commemorated means to honour or remember something. In this context, it doesn't fit logically as colleagues wouldn't commemorate elective courses they're planning to offer. Considered makes more sense here, indicating that all
Question : Directions: In the following question, some parts of the sentence may have errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No Error".
I will try to be on time (1) / but don't worry when (2) / I am late. (3) / No Error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (2)
Solution : The correct choice is the second option.
"When" should be replaced with "if" to convey the intended meaning. The conjunction "if" is used in conditional situations instead of "when", which is used to denote a point in time. There is an error in the use
Question : Directions: In the question two statements are given, followed by two conclusions, I and II. You have to consider the statements to be true even if they seem to be at variance from commonly known facts. You have to decide which of the given conclusions, if any, follows from the given statements. Statements: I. Each correct is wrong. II. No wrong is right. Conclusions: I. No correct is right. II. Some wrongs are correct.
Option 1: Only conclusion II follows
Option 2: Both conclusions I and II follow
Option 3: Only conclusion I follows
Option 4: Neither conclusion I nor II follows
Correct Answer: Both conclusions I and II follow
Solution : The possible Venn diagram, according to the given statements is as follows –
Let's analyse the conclusions – Conclusion (I): No correct is right – From the Venn diagram, it is evident that all correct is wrong and no wrong
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