Staff Selection Commission Combined Higher Secondary Level Exam
Question : One nanometer is equal to ______ meters.
Option 1: 10 raised to the power (-3)
Option 2: 10 raised to the power (-6)
Option 3: 10 raised to the power (-9)
Option 4: 10 raised to the power (-12)
Correct Answer: 10 raised to the power (-9)
Solution : The correct answer is 10 raised to the power (-9)
A nanometer is one billionth of a meter in length. One meter contains one billion nanometers. The unit for small objects, such as atoms and molecules, is called a nanometer.
Question : Tamil Nadu's Archana Suseendran won how many gold medals at AFI Indian Grand Prix 2 held in Kerala on 27 March 2023?
Option 1: 6
Option 2: 4
Option 3: 3
Option 4: 2
Correct Answer: 2
Solution : The correct option is 2.
Tamil Nadu's Archana Suseendran defeated Hima Das in the 100 m final. She also won 200 m to claim a double gold in the AFI Indian Grand Prix 2. This double victory led her to the Asian Games.
Question : The Zoji La Pass connects:
Option 1: Srinagar and Leh
Option 2: Arunachal Pradesh and Tibet
Option 3: Chamba and spiti
Option 4: Kalimpong and Lhasa
Correct Answer: Srinagar and Leh
Solution : The correct option is Srinagar and Leh.
In India's western Himalayan mountain range, between Srinagar and Leh, there is a high mountain pass called Zoji La. It is accessible by Indian National Highway 1. Ladakh and Kashmir are connected through Zoji La.
Question : If $\sin (p+q)=1$ and $\cos (p-q)=\frac{\sqrt{3}}{2}$, then find $p$.
Option 1: 90°
Option 2: 80°
Option 3: 60°
Option 4: 120°
Correct Answer: 60°
Solution : Given: $\sin (p+q)=1$ and $\cos (p-q)=\frac{\sqrt{3}}{2}$ $\sin (p+q)=\sin 90°$ and $\cos (p-q)=\cos 30°$ ⇒ $(p+q)=90°$ ------------(1) And $(p-q)=30°$ --------- (2) Adding equations (1) and (2), we have, ⇒ $2p=120°$ ⇒ $p=60°$ Hence, the correct answer is 60°.
Question : If $x=5–\sqrt{21}$, the value of $\frac{\sqrt{x}}{\sqrt{32–2x}–\sqrt{21}}$ is:
Option 1: $\frac{1}{\sqrt2}(\sqrt{3}–\sqrt{7})$
Option 2: $\frac{1}{\sqrt2}(\sqrt{7}–\sqrt{3})$
Option 3: $\frac{1}{\sqrt2}(\sqrt{7}+\sqrt{3})$
Option 4: $\frac{1}{\sqrt2}(7–\sqrt{3})$
Correct Answer: $\frac{1}{\sqrt2}(\sqrt{7}–\sqrt{3})$
Solution : Given: $x=5–\sqrt{21}$ ⇒ $\sqrt{x}=\sqrt{5–\sqrt{21}}$ ⇒ $\sqrt{x}={\sqrt \frac{10–2\sqrt{21}}{2}}$ ⇒ $\sqrt{x}=\sqrt{\frac{7+3–2\sqrt{7}\sqrt{3}}{2}}$ ⇒ $\sqrt{x}=\sqrt{\frac{(\sqrt{7}–\sqrt{3})^{2}}{2}}$ ⇒ $\sqrt{x}=\frac{\sqrt{7}–\sqrt{3}}{\sqrt{2}}$ Putting the value of $\sqrt{x}$ in the expression $\frac{\sqrt{x}}{\sqrt{32–2x}–\sqrt{21}}$, we have: = $\frac{\frac{\sqrt{7}–\sqrt{3}}{\sqrt{2}}}{\sqrt{32–10+2\sqrt{21}}–\sqrt{21}}$ = $\frac{\frac{\sqrt{7}–\sqrt{3}}{\sqrt{2}}}{\sqrt{22+2\sqrt{21}}–\sqrt{21}}$ = $\frac{\frac{\sqrt{7}–\sqrt{3}}{\sqrt{2}}}{\sqrt{21+1+2\sqrt{21}.\sqrt{1}}–\sqrt{21}}$ = $\frac{\frac{\sqrt{7}–\sqrt{3}}{\sqrt{2}}}{\sqrt{(\sqrt{21}+\sqrt{1})^{2}}–\sqrt{21}}$ = $\frac{\frac{\sqrt{7}–\sqrt{3}}{\sqrt{2}}}{\sqrt{21}+1–\sqrt{21}}$ = $\frac{1}{\sqrt{2}}(\sqrt{7}–\sqrt{3})$ Hence, the correct answer is $\frac{1}{\sqrt{2}}(\sqrt{7}–\sqrt{3})$.
Question : An element that does not occur in nature but can produced artificially is
Option 1: Thorium
Option 2: Radium
Option 3: Plutonium
Option 4: Uranium
Correct Answer: Plutonium
Solution : The correct answer is Plutonium.
Plutonium is an artificial metal i.e. it is not found naturally in large amounts. It has an atomic number of 94 and is placed in actinide series in the periodic table. It is an radioactive material and is formed when
Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No Error".
The collector (1) / visits the office regularly (2) / Isn't it? (3) / No Error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (3)
Solution : The error lies in the third part of the sentence.
A question tag is a short clause that is added at the end of a statement to turn it into a question. In the case of a positive statement, a negative question tag is formed
Question : Select the most appropriate homophone to fill in the blank.
Ants _______ food during the summer and save it for winter.
Option 1: horde
Option 2: hoard
Option 3: heard
Option 4: herd
Correct Answer: hoard
Solution : The correct choice is the second option.
Hoard means to accumulate and store away for future use. In the context of the sentence, it refers to ants collecting and storing food during the summer to use later in the winter.
The meanings of the
Question : Directions: In a certain code language, HUMAN is coded as JYSIX. What is the code for IMAGE in that code language?
Option 1: KOGQO
Option 2: KQGOM
Option 3: KQGOA
Option 4: KQGOO
Correct Answer: KQGOO
Solution : Given: HUMAN is coded as JYSIX.
Add consecutive even numbers to the positional value of each letter of HUMAN to obtain the required code – H + 2 = J; U + 4 = Y; M + 6 = S; A + 8 = I;
Question : In the human body, ligaments are made up of
Option 1: white fibres and some yellow fibres
Option 2: white fibres only
Option 3: yellow fibres only
Option 4: yellow fibres and muscle fibres
Correct Answer: white fibres and some yellow fibres
Solution : The correct options are white fibres and some yellow fibres.
Ligaments are made up of white collagen fibres and some yellow elastic fibres. White collagen fibres are the fundamental structural component of ligaments, providing strength and stability. Yellow Elastic
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