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Staff Selection Commission Sub Inspector Exam

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Question : Directions: In the following question, a series is given with one or more alphabet missing. Choose the correct alternative from the given options.
A, ?, I, O, ?

Option 1: D, T

Option 2: F, V

Option 3: E, U

Option 4: C, W

Team Careers360 12th Jan, 2024

Correct Answer: E, U


Solution : Given:
A, ?, I, O, ?

The vowels of the English alphabet are A, E, I, O, U.

So, E and U are the missing terms in the series. Hence, the third option is correct.

17 Views

Question : $\sqrt{\frac{1+\sin\theta}{1-\sin\theta}}+\sqrt{\frac{1-\sin\theta}{1+\sin\theta}}$ is equal to:

Option 1: $2\cos\theta$

Option 2: $2\sin\theta$

Option 3: $2\cot\theta$

Option 4: $2\sec\theta$

Team Careers360 17th Jan, 2024

Correct Answer: $2\sec\theta$


Solution : Given:
$\sqrt{\frac{1+\sin\theta}{1-\sin\theta}}+\sqrt{\frac{1-\sin\theta}{1+\sin\theta}}$
= $\sqrt{\frac{(1+\sin\theta)(1+\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}}+\sqrt{\frac{(1-\sin\theta)(1-\sin\theta)}{(1+\sin\theta)(1-\sin\theta)}}$
= $\sqrt{\frac{(1+\sin\theta)(1+\sin\theta)}{(1-\sin^2\theta)}}+\sqrt{\frac{(1-\sin\theta)^2}{(1-\sin^2\theta)}}$
= $\sqrt{\frac{(1+\sin\theta)(1+\sin\theta)}{(cos^2\theta)}}+\sqrt{\frac{(1-\sin\theta)^2}{(cos^2\theta)}}$
= $\frac{(1+\sin\theta)}{\cos\theta}+\frac{(1-\sin\theta)}{\cos\theta}$
= $\frac{2}{\cos\theta}$
= $2 \sec\theta$
Hence, the correct answer is $2\sec\theta$.

34 Views

Question : A boat travels 60 kilometres downstream and 20 kilometres upstream in 4 hours. The same boat travels 40 kilometres downstream and 40 kilometres upstream in 6 hours. What is the speed (in km/hr) of the stream?

Option 1: 24 km/hr

Option 2: 16 km/hr

Option 3: 18 km/hr

Option 4: 20 km/hr

Team Careers360 22nd Jan, 2024

Correct Answer: 16 km/hr


Solution : Time taken to travel 60 km downstream and 20 km upstream = 4 hours
Time taken to travel 40 km downstream and 40 km upstream = 6 hours
Let the speed of the boat in still water be $x$ km/hr and the speed of

20 Views

Question : Though there is no single theory that can explain the origin of the south-west monsoon, it is believed that the main mechanism is the differential heating of land and sea during

Option 1: Winter months

Option 2: Summer months

Option 3: Cyclonic storms

Option 4: South-west trade wind flow

Team Careers360 15th Jan, 2024

Correct Answer: Summer months


Solution : The correct answer is the Summer months.

The monsoon is a complex phenomenon. It is believed that due to differential heating of land and sea in the summer months in the Northern Hemisphere, monsoonal winds blow from the Indian Ocean towards India.

6 Views

Question : Directions: In the following question, out of the four alternatives, select the alternative that will improve the bracketed part of the sentence. In case no improvement is needed, select "No Improvement".

It will take four hours to walk (across) the caves.

(1) over

(2) through

(3) between

(4) No Improvement

Option 1: 1

Option 2: 2

Option 3: 3

Option 4: 4

Team Careers360 18th Jan, 2024

Correct Answer: 2


Solution : The correct choice is the second option.

The preposition across should be replaced with through which is the suitable preposition to be used in this context.

The meanings of the other options are as follows:

  • Across implies moving from side to side.
  • Over means upon
22 Views

Question : The value of $\frac{\left(1 \frac{1}{9} × 1 \frac{1}{20} ÷ \frac{21}{38}-\frac{1}{3}\right) ÷\left(2 \frac{4}{9} ÷ 1 \frac{7}{15} \text { of } \frac{3}{5}\right)}{\frac{1}{5} \text { of } \frac{1}{5} ÷ \frac{1}{125}-\frac{1}{25} ÷ \frac{1}{5} \text { of } \frac{1}{5}}$ lies between ____.

Option 1: 0.1 and 0.15

Option 2: 0.2 and 0.25

Option 3: 0.15 and 0.2

Option 4: 0.25 and 0.3

Team Careers360 14th Jan, 2024

Correct Answer: 0.15 and 0.2


Solution : Given: $\frac{\left(1 \frac{1}{9} × 1 \frac{1}{20} ÷ \frac{21}{38}-\frac{1}{3}\right) ÷\left(2 \frac{4}{9} ÷ 1 \frac{7}{15} \text { of } \frac{3}{5}\right)}{\frac{1}{5} \text { of } \frac{1}{5} ÷ \frac{1}{125}-\frac{1}{25} ÷ \frac{1}{5} \text { of } \frac{1}{5}}$
= $\frac{(\frac{10}{9} × \frac{21}{20}\div\frac{21}{38} – \frac{1}{3})\div(\frac{22}{9}\div(\frac{22}{15}\times\frac{3}{5}))}{(\frac{1}{5} \times \frac{1}{5}) ÷ \frac{1}{125}-\frac{1}{25} ÷

49 Views

Question : The average weight of some students in a class was 60.5 kg. When 8 students, whose average weight was 65 kg, joined the class, then the average weight of all the students increased by 0.9 kg. The number of students in the class, initially, was:

Option 1: 37

Option 2: 42

Option 3: 32

Option 4: 40

Team Careers360 13th Jan, 2024

Correct Answer: 32


Solution :

Let the total number of students be $x$.
Average weight of $x$ students = 60.5 kg
The sum of the weights of $x$ students = $60.5x$ kg
The average weight of 8 students = 65 kg
The sum of the weights of 8 students =

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