Correct Answer: Virat Kohli

Solution : The correct option is Virat Kohli.

Virat Kohli surpassed Australia's Don Bradman to create the record of scoring the most 150-plus scores as a captain. He broke the record of Don Bradman who made 8 times and Virat Kohli made this record a

Correct Answer: $1$

Solution : Given:
$\sin^4\theta+\cos^4\theta=2\sin^2\theta \cos^2\theta$ and $\theta$ is an acute angle.
We know the algebraic identity, $(a-b)^2=a^2+b^2-2ab$.
$\sin^4\theta+\cos^4\theta-2\sin^2\theta \cos^2\theta=0$
Or, $(\sin^2\theta-\cos^2\theta)^2=0$
Or, $\sin^2\theta-\cos^2\theta=0$
Or, $\sin^2\theta=\cos^2\theta$
Or, $\tan^2\theta=1$
$\therefore \tan \theta=\pm 1$
Since, $\theta$ is an acute angle, then the value of $\tan\theta$ is $1$.
Hence, the correct

Correct Answer: To do something without worrying about the risk

Solution : The correct answer is the third option.

The most appropriate understanding of the idiom "to throw caution to the wind" is to undertake an action without considering the potential risks involved.

The idiom "to throw caution to the

Correct Answer: 4.2 and 4.4

Solution : Given: $\frac{\frac{1}{3}+[4 \frac{3}{4}–(3 \frac{1}{6}–2 \frac{1}{3})]}{(\frac{1}{5} \text { of } \frac{1}{5} \div \frac{1}{5}) \div(\frac{1}{5} \div \frac{1}{5} \times \frac{1}{5})}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–(\frac{19}{6}– \frac{7}{3})]}{(\frac{1}{25} \div \frac{1}{5}) \div(\frac{1}{5} \times 5 \times \frac{1}{5})}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–(\frac{19–7\times 2}{6})]}{(\frac{1}{25} \times 5) \div(\ \frac{1}{5})}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–\frac{19–14}{6}]}{\frac{1}{5} \div\ \frac{1}{5}}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–\frac{5}{6}]}{\frac{1}{5} \times 5}$
$=\frac{\frac{1}{3}+[

Correct Answer: Book : Chapter

Solution : Given:
Fan : Blades :: ? : ?

Blades are an important part of the fan to blow the air.
Similarly, chapters are important chunks in the book.

The relation in the fourth option is between a thing and its component, while in

Correct Answer: x and +

Solution : Given:
42 ÷ 7 + 11 × 87 – 12 = 141

Let's check the options –
First option: ÷ and –
42 – 7 + 11 × 87 ÷ 12 = 141
42 – 7 + 11 × 7.25 = 141
42

Correct Answer: 1955

Solution : The correct answer is 1955.

The first four Republic Day parades were held at different places between 1950 to 1954. For the first time in 1955, Rajpath was decided to be a permanent venue for the Republic Day celebrations. Republic Day is celebrated on

Correct Answer:

Solution : Because there is no restriction on the rotation of the figure, we will check all the possible angles where the question figure can fit itself in the given option figures.
By comparison of all the option figures, the given question figure is embedded only in the

Correct Answer: 65

Solution :

Given, $\angle PQR=100^{\circ}$ and $\angle STR=105^{\circ}$
Since the angle subtended by the chord at the centre is double the angle subtended by the chord at the circumference,
reflex$\angle SOR = 2\angle STR = 210^\circ$
So, $\angle SOR = 360^\circ-210^\circ = 150^\circ$
By angle sum property

Correct Answer: INSTRUCTIONS

Solution : Given:
ABSTRACTIONISTS

Now, let's compare all the option words with the word ABSTRACTIONISTS –
First option: ATTRACTION; All the letters of ATTRACTION are present in the word ABSTRACTIONISTS.
Second option: INSTRUCTIONS; U is not present in the word ABSTRACTIONISTS. Also, the letter N appears only