It's a Question of your Career!

Hello student ,

Here you have not mentioned for which have forgot to download the application form . That's why I am unable to guide you to download your application form . So first of all ask your question again mentioning some details about your application form so that I

Hello,

Since you have not mentioned your category, assuming that you are from general category, with a score of 520 it is not possible to a state quota seat in government colleges in Jharkhand. However there are chances for private colleges for state quota seats.

There are also chances for

Hello Aspirant,

According to the marks you have mentioned in the question your percentile would be in the range of 99.04-99.24 and your rank would lies in between 6854-8504. On the basis of this rank and percentile you can easily get into top NITs like NIT Uttarakhand,NIT Jaipur,NIT Jamshedpur and

Hello student

TS PG CET 2019 cut off marks is at least of total marks 25% that is 30. Total marks for TS PGCET is 120. The candidates have to to qualify in 10 plus 2 level exam and Graduation with 50% marks with science or Technology for MTech environmental

The National Education Policy 2020 (NEP 2020), which was approved by the Union Cabinet of India on 29 July 2020, outlines the vision of India's new education system.The new policy replaces the previous National Policy on Education, 1986. The policy is applicable  for elementary education to higher education .

But

Hello Aspirant,

For Biology notes and questions ,do check the link below to get the notes. you have to just create the account on the website ,register yourself and then you can access the material available there.

https://www.genextstudents.com/studyzone/Board/UP-BOARD/12-%E0%A4%B5%E0%A4%BF%E0%A4%9C%E0%A5%8D%E0%A4%9E%E0%A4%BE%E0%A4%A8/%E0%A4%9C%E0%A5%80%E0%A4%B5-%E0%A4%B5%E0%A4%BF%E0%A4%9C%E0%A5%8D%E0%A4%9E%E0%A4%BE%E0%A4%A8/607

Hope it helps

Hello,

a)Distance from earth's centre = 6400 + 640=7.04 x 10^6m

Now,

mv^2/r= GMm/r^2

V =   √GM/r  = √56.8 x 10^6

= 7.56 x 10^3 ms ^-1

(B) Total energy after 1500 rounds = Initial energy - Energy loss

= - GMm/2r- 1.42 x 10^5x 1500

=(- 6253-0213) x 10^9

Hello,

You can use the Careers360 Rank Predictor Tool to predict the rank & percentile.

Also you can use,

JEE Main college predictor tool to predict some good colleges for your percentile.

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Good luck!