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Dear candidate
According to the dress code of NEET 2020 t-shirts are allowed but full sleeve t-shirts are not allowed so, make sure you t- shirt doesn't have full sleeves and coming to the color yes, you can wear black t-shirt but i recommend you to wear only light colors
In case of JEE Main it is difficult to get a chance in NITs, IIITs or GFTIs. There is almost no chance for you to get into an NIT. You need to score at least 150 to get a good college and a good branch.
For COMEDK go through this
Hi there,
Unfortunately no you can not get admission at nit hamirpur even in state qouta and your category rank. As your percentile is very poor you have very less chances still you can check other college using our college predictor tool
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
Hello
Hope you are doing well
For nit as we know you have state quota .if you are from east then you may get nit by your state quota in 6-7th round .if suppose you belongs to up then 90 percentile is not sufficient to get IT branch in any
Dear Mansi ,
You may get admission directly through jee mains
Nit allahabad is prestigious and decent colleges of india ,
For admissions to this college a student must need to pass 12th with science stream with 75% marks ,
The competitive exam accepted by this college is JEE MAIN
Hey there
NO absolutely not majority people don't update their recent photo and thus bio metric identification is done at the center if required. You will be allowed to give exams if all your papers are correct.
check the link
https://medicine.careers360.com/articles/neet-rules-and-regulations
good luck
Dear Aspirant,
As you got 14,623 rank in AP EAMCET and also based on your category you have less chances to get seat in government college offering B.SC Agriculture course. you have chances to get seat in AU region if you belong to farmer category.
refer the below link to
Hello,
Some of the colleges/universities which are best for lateral entry students to the B.Tech EEE course are:
The rank (CRL) from percentile is to be calculated by following formula: rank (CRL) = (100-percentile)* Total no of student appeared in exam/100 As per the formula, your CRL rank is coming out to be 86901 approximately, where total no. of student appeared in the exam is 869010 .
Your
Dear Ramani ,
Cutoff for eamcet 2020 for JNUTH will be as expected to be as similar as cut off of 2019
So by looking at 2019 cutoff you may predict the colleges cutoff
detailed link for 2019 cutoff is given below :
https://engineering.careers360.com/articles/ts-eamcet-cutoff
Cut for 2019 of general category
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