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Hi,
With a BITSAT score of 188, getting an Integrated M.Sc program at BITS Pilani main campus may be difficult this year. However, you can still have some chances in: • BITS Hyderabad – M.Sc Biological Sciences/Chemistry (borderline) • BITS Goa – difficult but possible only if cutoffs drop slightly.
Hello Dear Student,
Yes, many colleges offer B.Sc Nursing admission without CUET through:
Fee structure varies a lot depending on the college type:
You can use the following link to predict your KCET rank. https://engineering.careers360.com/articles/kcet-rank-predictor
All the best!
Hello Dear Student, With a MET score of 112 and 343/400 (85.75%) in your board exams, you can expect an estimated rank between 4,500 and 8,000. You can check, find and access more information here: https://engineering.careers360.com/articles/met-2026-rank-predictor-by-marks https://engineering.careers360.com/articles/met-marks-vs-rank Hope it helps!
If your JEE Main rank is around 1 lakh and you want CSE, then these are some good options you can target:
• NIT Mizoram – CSE possible in later rounds/home state quota sometimes • NIT Arunachal Pradesh – CSE/related branches possible • IIIT Manipur – some chances in
Hello Dear Student, Could you provide more information about which exam admit card you want! Hope it helps!
You can use the following link to check your results. https://school.careers360.com/articles/oav-entrance-exam-result-2026
Hello Dear Student, With a PCM cutoff of 167.5 and a sports quota score of 135, you have excellent chances of securing ECE or Biotech seats in reputed TNEA colleges like Rajalakshmi Engineering College, St. Joseph’s College of Engineering, and Kumaraguru College of Technology. You can check, find and access
You can use the following link to predict your MET rank https://engineering.careers360.com/articles/met-rank-predictor
The aggregate marks for a B.Tech application are usually calculated by adding the marks obtained in the required subjects (commonly Physics, Chemistry, and Mathematics) and then dividing by the total maximum marks of those subjects, multiplied by 100.
Hope it helps!
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