It's a Question of your Career!

Hi,

Please provide the university/college name so we can help you with more information regarding BSc Computer Science eligibility criteria. The eligibility criteria varies depending on the institution opted by the candidates.

Jharkhand Academic Council usually releases the JAC Class 9 syllabus for the new academic session between May and July. For the 2026–27 session, the updated syllabus is expected to be available soon on the official JAC website.

Hello Pradeep

You can download the AIIMS paramedical previous year question paper from the link given below:

https://medicine.careers360.com/articles/aiims-paramedical-question-paper

Hope it helps.

Hello, the KCET 2026 result is expected to be announced in May 2026. You can check the result through the official website cetonline.karnataka.gov.in by entering your registration number and login details. The scorecard will include the marks and rank obtained in the exam.

You can check the complete KCET result

Hello,

Kripya spasht kijiye aap kisme slection ke baare me puchna chahte hai. Apna prashn sapsht kijiye aapko puri jaankari prdan ki jaayegi.

Hello, with 294 marks in PCM board exams and 84 marks in KCET, you may get a decent rank in KCET. Your OBC 2B category can also help during counselling and seat allotment.

For more details, please check this link here: KCET Rank Predictor 2026

Hello,

Please check the MSCE Pune class 7 scholarship answer key here. The answer key contains all the correct answers to the questions asked in the entrance exam.

Thanks,

Hello Bhagwat

Please specify which exam question paper you need.

Hello, to prepare for JEE Advanced 2027, start with a proper study plan, focus on NCERT concepts, practise previous year questions regularly, and revise topics consistently. It is important to build strong concepts in Physics, Chemistry, and Mathematics, along with regular mock tests and time management practice.

You can check

This Reaction is called the Rosenmund reaction

$\mathrm{RCOCl}+{\mathrm{H}}_2\stackrel{\mathrm{Pd}/{\mathrm{BaSO}}_4}{\to }\mathrm{RCHO}+\mathrm{HCl}$