It's a Question of your Career!

Correct Answer: $3:2$

Solution : Given: A regular hexagon and an equilateral triangle having the same perimeter.
Let the perimeter of the triangle and the hexagon be $6a$ units.
So, each side of the hexagon = $a$ units
And each side of the triangle = $2a$ units
We know that

Correct Answer: 623

Solution : The total number of scooters produced by the company during the first half of 1992 is the sum of the total production for each month from January to June. 
$\therefore$ The total number of scooters produced by the company = 100 + 105 + 108

Correct Answer: SAJ

Solution : Given:
RBT, OER, KIP, FNN, ZTL, ?

Subtract consecutive numbers from the first letter, add consecutive numbers to the second letter, and subtract 2 from the third letters of the previous term to obtain the next term in the series –
RBT→R – 3 =

Correct Answer: (2)

Solution : The correct choice is the second option.

Explanation: The phrase, ''seldom if ever'' means rarely or almost never. When a sentence begins with ''seldom if ever'', the following part of the sentence follows the law of inversion. The law of inversion means that

Correct Answer: Only conclusions I and II follow

Solution : The possible Venn diagram according to the given statements is as follows –

Let's analyse the conclusions –
Conclusion I: Some boys are males – From the above Venn diagram, it is clear that some part of the circle of

Correct Answer: 10.25%

Solution : Rate, $\frac{R}{2}$ = 10%
Time, $n$ = 1 year
Let principal sum, $P$ be INR 100.
When compounded half-yearly,
Amount = $P(1+\frac{\frac{R}{2}}{200})^{2n}$
= $100(1+\frac{10}{200})^{2}$
= $100(\frac{21}{20})^{2}$
= $\frac{441}{4}$
= INR 110.25
Effective rate = $\frac{110.25-100}{100}×100$
= 10.25%
Hence, the correct answer is 10.25%

Correct Answer: $2$

Solution : Given: $\frac{(a^2+b^2)(a-b)-(a-b)^3}{a^2b-ab^2}$
= $\frac{(a-b)(a^2+b^2-(a-b)^2)}{ab(a-b)}$
= $\frac{a^2+b^2-a^2+2ab-b^2}{ab}$
= $\frac{2ab}{ab}$
= $2$
Hence, the correct answer is $2$.

Correct Answer: 3

Solution : $3 \tan 20°\tan 45° \tan70°$
$= 3 \tan 20°\tan 45° \tan (90° - 20°)$ [Using $\tan \theta = \cot (90° - \theta)$]
$= 3 \tan 20°\tan 45°\cot 20°$
$= 3 \times \tan 45°$
$= 3 \times 1$
$= 3$
Hence, the correct answer is 3.

Correct Answer: $2 \cos \theta$

Solution : We know, $\cos2\theta= 2\cos^2\theta-1$
⇒ $\cos2\theta+1= 2\cos^2\theta$
Putting $\theta=4\theta$ on both sides, we get
$\therefore \cos8\theta+1=2\cos^24\theta$
Given, $\sqrt{2+\sqrt{2+\sqrt{2+2\cos8\theta}}}$
= $\sqrt{2+\sqrt{2+\sqrt{2(1+\cos8\theta)}}}$
= $\sqrt{2+\sqrt{2+\sqrt{2(2\cos^24\theta)}}}$
= $\sqrt{2+\sqrt{2+2\cos4\theta}}$
= $\sqrt{2+\sqrt{2(1+\cos4\theta)}}$
= $\sqrt{2+\sqrt{2(2\cos^22\theta))}}$
= $\sqrt{2+2\cos2\theta}$
= $\sqrt{2(1+\cos2\theta)}$
= $\sqrt{2(2\cos^2\theta)}$
= $2 \cos \theta$
Hence, the correct answer is

Correct Answer: 86th Amendment Act, 2002

Solution : The correct answer is the 86th Amendment Act, of 2002.

The 86th Amendment Act, 2002 came during the Atal Bihari Vajpayee government. This act makes it obligatory on the part of the government to ensure admission, attendance, and completion of elementary