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Question : During the British rule, who was the first Inspector General of Forests in India?
Option 1: Salim Ali
Option 2: James Edward Corbett
Option 3: John Shore
Option 4: Dietrich Brandis
Correct Answer: Dietrich Brandis
Solution : The correct answer is Dietrich Brandis.
Dietrich Brandis served as India's first Inspector General of Forests. He contributed to the British government's 1865 Indian Forest Act drafting. He made sure a framework was in place so that forests could be managed properly. In 1864,
Question : Simplify $\frac{\cos ^4 \theta-\sin ^4 \theta}{\sin ^2 \theta}$.
Option 1: $1-\tan ^2 \theta$
Option 2: $\tan ^2 \theta-1$
Option 3: $\cot ^2 \theta-1$
Option 4: $1-\cot ^2 \theta$
Correct Answer: $\cot ^2 \theta-1$
Solution : $\frac{\cos ^4 \theta-\sin ^4 \theta}{\sin ^2 \theta}$ $= \frac{(\cos^2 \theta - \sin^2 \theta)(\cos^2 \theta + \sin^2 \theta)}{\sin ^2 \theta}$ $=\frac{\cos^2 \theta - \sin^2 \theta}{\sin ^2 \theta}$ [As $\cos^2 \theta + \sin^2 \theta = 1$] $=\frac{\cos^2 \theta}{\sin ^2 \theta}-\frac{\sin^2 \theta}{\sin^2 \theta}$ $=\cot ^2 \theta-1$
Question : The perimeter of the top of a rectangular table is 56 metres and its area is 192 m2. What is the length of its diagonal?
Option 1: 22 metres
Option 2: 20 metres
Option 3: 16 metres
Option 4: 18 metres
Correct Answer: 20 metres
Solution : Given: The perimeter of the top of a rectangular table is 56 metres and its area is 192 m2. Use the formulas, Perimeter = $2(l+b)$ Area = $l\times b$ Length of diagonal = $\sqrt{l^2+b^2}$ Where $l$ and $b$ are length and breadth.
Question : ABCD is a cyclic quadrilateral, AB is the diameter of the circle. If angle $\angle ACD=45^{\circ}$, then what is the value of $\angle BAD$?
Option 1: $90^{\circ}$
Option 2: $45^{\circ}$
Option 3: $135^{\circ}$
Option 4: $35^{\circ}$
Correct Answer: $45^{\circ}$
Solution :
Since, an angle subtended by the diameter of a circle at the circumference = $90^{\circ}$ ⇒ $\angle$ ACB = $90^{\circ}$ $\angle$ BCD = $\angle$ ACD + $\angle$ ACB = $45^{\circ} + 90^{\circ}=135^{\circ}$ Since the opposite angles of a cyclic quadrilateral are supplementary, $\angle$ BCD +
Question : 2nd October is observed as________.
Option 1: International Non-Violence Day
Option 2: World Social Justice Day
Option 3: World Wildlife Day
Option 4: International Education Day
Correct Answer: International Non-Violence Day
Solution : The correct answer is International Non-Violence Day.
October 2nd is indeed observed as the International Day of Non-Violence. This date is significant because it marks the birthday of Mahatma Gandhi, the leader of the Indian independence movement against British colonial rule and a
Question : The value of $[(0.87)^2+(0.13)^2+(0.87)×(0.26)]^{2013}$ is:
Option 1: 0
Option 2: 2013
Option 3: 1
Option 4: –1
Correct Answer: 1
Solution : Given: $[(0.87)^2+(0.13)^2+(0.87)×(0.26)]^{2013}$ = $[(0.87)^2+(0.13)^2+(0.87)×2×(0.13)]^{2013}$ = $(0.87+0.13)^{2\times 2013}$ = $(1)^{2\times 2013}$ = $1$ Hence, the correct answer is 1.
Question : Directions: Select the option that is related to the third term in the same way as the second term is related to the first term and the sixth term is related to the fifth term. 18 : 123 :: 15 : ? :: 19 : 130
Option 1: 114
Option 2: 112
Option 3: 102
Option 4: 120
Correct Answer: 102
Solution : Given: 18 : 123 :: 15 : ? :: 19 : 130
Like, 18 : 123→(18 × 7) – 3 = 126 – 3 = 123 19 : 130→(19 × 7) – 3 = 133 – 3 = 130 Similarly, follow the same pattern for
Question : A mask manufacturing company manufactured an ‘$x$’ number of masks in 2018. It increased its manufacturing capacity by 30% in 2019 and further increased its manufacturing by 15% in 2020. In 2021, due to the machinery breakdown, its manufacturing declined by 40%. What is the value of ‘X’ if it manufactured 179400 masks in 2021?
Option 1: 180000
Option 2: 230000
Option 3: 200000
Option 4: 210000
Correct Answer: 200000
Solution : Given: A mask manufacturing company manufactured an ‘$x$’ number of masks in 2018. It increased its manufacturing capacity by 30% in 2019 and further increased its manufacturing by 15% in 2020. Mask manufactured in 2019 = $x × \frac{130}{100}$ = $\frac{13x}{10}$ Mask manufactured in 2020
Question : Select the option that expresses the given sentence in direct speech. I said that when it stopped drizzling we would have to start digging again.
Option 1: I said, "When it stopped to drizzle we must start digging again."
Option 2: I said, "When it stops drizzling we must start digging again."
Option 3: I said, "When drizzle will stop then we will start digging again."
Option 4: I said, "When it stops to drizzle we will start digging again."
Correct Answer: I said, "When it stops drizzling we must start digging again."
Solution : The second option is correct.
Narration conversion:
Therefore, the correct sentence is: I
Question : If $xy = -6$ and $x^3+ y^3= 19$ ($x$ and $y$ are integers), then what is the value of $\frac{1}{x^{–1}}+\frac{1}{y^{–1}}$?
Option 1: –1
Option 2: –2
Option 4: 2
Solution : Given: $xy = -6$ and $x^3+ y^3= 19$ ($x$ and $y$ are integers) We know the algebraic identity, $(x+y)^3=x^3 + y^3+3xy(x+y)$. Substitute the given values in the above formula, ⇒ $(x+y)^3=19+3\times(-6)\times(x+y)$ ⇒ $(x+y)^3=19-18\times(x+y)$ Let $(x+y)=u$. ⇒ $u^3+18u–19=0$ ⇒ $u^3–u^2+u^2–u+19u–19=0$ ⇒ $u^2(u–1)+u(u–1)+19(u–1)=0$ ⇒ $(u–1)(u^2+u+19)=0$ ⇒ $u-1=0$
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