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Question : If the sum of all interior angles of a regular polygon is 14 right angles, then its number of sides is:
Option 1: 8
Option 2: 9
Option 3: 7
Option 4: 6
Correct Answer: 9
Solution : Sum of all interior angles = $14×90^{\circ}$ = $1260^{\circ}$ Let the number of sides of the polygon be $n$. ⇒ $1260^{\circ}$ = $(n-2)×180^{\circ}$ ⇒ $(n-2)$ = $\frac{1260}{180}$ ⇒ $(n-2)$ = $7$ ⇒ $n$ = $2+7$ = $9$ Hence, the correct answer is 9.
Question : If $\cos \theta-\sin \theta=\sqrt{2} \sin \theta$, then $(\cos \theta+\sin \theta)$ is:
Option 1: $-\sqrt{2} \cos \theta$
Option 2: $\sqrt{2} \cos \theta$
Option 3: $\sqrt{2} \tan \theta$
Option 4: $-\sqrt{2} \sin \theta$
Correct Answer: $\sqrt{2} \cos \theta$
Solution : According to the question, ⇒ $\cos \theta-\sin \theta=\sqrt{2} \sin \theta$ ⇒ $(\cos\theta + \sin\theta)^{2} = 2 \sin^{2}\theta$ ⇒ $\cos^{2}\theta + \sin^{2}\theta + 2\sin\theta\cos~\theta = 2\sin^{2}\theta$ ⇒ $\sin^{2}\theta - \cos^{2}\theta - 2\sin~\theta~cos\theta = 0$ ⇒ $\sin^{2}\theta + \cos^{2}\theta - 2\sin\theta\cos\theta = 2 \cos^{2}\theta$ ⇒
Question : Let $x$ be the least number of 4 digits that when divided by 2, 3, 4, 5, 6 and 7 leaves a remainder of 1 in each case. If $x$ lies between 2000 and 2500, then what is the sum of the digits of $x$?
Option 1: 4
Option 2: 15
Option 3: 9
Option 4: 10
Correct Answer: 4
Solution :
LCM of 2, 3, 4, 5, 6 and 7 is 420. The number should be between 2000 and 2500. So, the number is = 420 × 5 = 2100 The remainder will be 1 in each case so the number = 2100 + 1 =
Question : Which of the following places is not associated with the Kumbh Mela?
Option 1: Nashik-Trimbakeshwar
Option 2: Ujjain
Option 3: Haridwar
Option 4: Puri
Correct Answer: Puri
Solution : The correct option is Puri.
Puri is not traditionally associated with the Kumbh Mela. The Kumbh Mela is a major Hindu festival and pilgrimage that rotates among four locations: Prayagraj (formerly Allahabad), Haridwar, Nashik and Ujjain. Puri, in the eastern Indian state of Odisha,
Question : Who among the following won the bronze medal at the World U20 Wrestling Championship 2022, which was held in Sofia, Bulgaria?
Option 1: Atul Malhotra
Option 2: Vikas Khedkar
Option 3: Rohit Dahiya
Option 4: Bajrang Punia
Correct Answer: Rohit Dahiya
Solution : The correct answer is Rohit Dahiya.
Rohit Dahiya won bronze medals on the final day of the World Championship 2022 in Sofia, Bulgaria. He defeated his opponent, Ukraine's Ruslan Abdiiev, in the 82 kg. India ended the World U20 Wrestling Championships 2022 with
Question : Indian Navy Sailing Championship 2022, one of the events being conducted by the Indian Navy to commemorate Azadi ka Amrit Mahotsav and khelo India, was held in:
Option 1: Andhra Pradesh
Option 2: West Bengal
Option 3: Tamil Nadu
Option 4: Kerala
Correct Answer: Kerala
Solution : The correct option is Kerala.
The Indian Navy Sailing Championship 2022, celebrating both Azadi ka Amrit Mahotsav, and Khelo India, was held at the picturesque Indian Naval Academy (INA) in Ezhimala, Kerala, from October 18th to 21st, 2022. This premier sailing event saw nearly 100
Question : D and E are points on sides AB and AC of $\Delta ABC$. DE is parallel to BC. If AD : DB = 2 : 3. What is the ratio of the area of $\Delta ADE$ and the area of quadrilateral BDEC?
Option 1: 4 : 21
Option 2: 4 : 25
Option 3: 4 : 29
Option 4: 4 : 9
Correct Answer: 4 : 21
Solution : AD : DB = 2 : 3 Let AD =$2x$ DB = $3x$ Now, the ratio of the area of the similar triangle is equal to the square of the ratio of their corresponding sides. Hence, in similar $\triangle ABC$ and $\triangle ADE$
Question : What is the value of 25 × 7 ÷ 175 - 196 ÷ 14 × 2 + 625 ÷ 25 × 3?
Option 1: 48
Option 2: 38
Option 3: 58
Option 4: 28
Correct Answer: 48
Solution : Given: 25 × 7 ÷ 175 – 196 ÷ 14 × 2 + 625 ÷ 25 × 3 = $25 × \frac{7}{ 175} - \frac{196}{14} × 2 + \frac{625}{ 25} ×3$ = 1 – 14 × 2 + 25 × 3 = 1 – 28
Question : KA Najeeb Vs Union of India case deals with violation of rights under_____.
Option 1: Article 16
Option 2: Article 21
Option 3: Article 14
Option 4: Article 19
Correct Answer: Article 21
Solution : The correct answer is Article 21.
The KA Najeeb vs. Union of India case is primarily concerned with a breach of Article 21 of the Indian Constitution. Article 21 of the Indian Constitution provides the right to life and personal liberty, and the
Question : If $(x-2)(x-p) = x^2-ax+6$, then the value of $(a - p)$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 3
Correct Answer: 2
Solution : Given: $(x-2)(x-p) = x^2-ax+6$ ⇒ $x^2-px-2x+2p=x^2-ax+6$ ⇒ $x^2-(p+2)x+2p=x^2-ax+6$ By comparing both sides of the equation, $p+2=a$ ⇒ $a-p=2$ Hence, the correct answer is 2.
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