It's a Question of your Career!

1 Million+

Questions

50k +

Active Users

24hrs max.

Answering Time

Showing 15741 - 15750 out of 57859 Questions
6 Views

Question : Directions: Which answer figure will complete the pattern in the question figure?

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 21st Jan, 2024

Correct Answer:


Solution : On comparing the question figure and all the option figures, the following figure will combine and make the complete pattern –

Hence, the second option is correct.

11 Views

Question : In places, the groundwater is stored between layers of hard rock below the water table. This is known as a/an ______.

Option 1: pond

Option 2: lake

Option 3: well

Option 4: aquifer

Team Careers360 20th Jan, 2024

Correct Answer: aquifer


Solution : The correct answer is an aquifer.

In some places, the groundwater is stored between layers of hard rock below the water table. This geological formation is known as an "aquifer." Aquifers act as natural reservoirs, holding and supplying water to wells and springs. They

21 Views

Question : Which of the following Fundamental Rights cannot be suspended even when an ‘Emergency’ is declared in the country?

Option 1: Articles 22 and 23

Option 2: Articles 20 and 21

Option 3: Articles 19 and 20

Option 4: Articles 21 and 22

Team Careers360 22nd Jan, 2024

Correct Answer: Articles 20 and 21


Solution : The correct answer is Articles 20 and 21.

During a national emergency in India, Article 20 and Article 21 maintain their inviolable status.

  • Article 20 ensures that individuals cannot be subjected to retrospective or ex post facto laws, meaning a person cannot
15 Views

Question : If $\tan\alpha=2$, then the value of $\frac{\operatorname{cosec}^{2}\alpha-\sec^{2}\alpha}{\operatorname{cosec}^{2}\alpha+\sec^{2}\alpha}$ is:

Option 1: $-\frac{15}{9}$

Option 2: $-\frac{3}{5}$

Option 3: $\frac{3}{5}$

Option 4: $\frac{17}{5}$

Team Careers360 23rd Jan, 2024

Correct Answer: $-\frac{3}{5}$


Solution : Given: $\tan\alpha=2$
We know that $\sec^{2}\alpha = 1 + \tan^{2}\alpha$ and $\operatorname{cosec}^{2}\alpha = 1 + \cot^{2}\alpha$
Since $\tan\alpha = 2$, we have $\sec^{2}\alpha = 1 + (2)^{2} = 5$
Also, $\cot\alpha = \frac{1}{\tan\alpha} = \frac{1}{2}$
So $\operatorname{cosec}^{2}\alpha = 1 + (\frac{1}{2})^{2} = \frac{5}{4}$
Putting the

16 Views

Question : What is the value of $\left[\frac{1}{5}+\left\{\frac{1}{6}\right.\right.$ of $\left.\left.\left(\frac{42}{35} \div \frac{6}{25}\right)–\left(\frac{2}{7} \times \frac{6}{5} \div \frac{18}{42}\right)\right\}+\frac{19}{30}\right]$?

Option 1: $\frac{17}{15}$

Option 2: $\frac{13}{15}$

Option 3: $\frac{14}{15}$

Option 4: $\frac{11}{15}$

Team Careers360 23rd Jan, 2024

Correct Answer: $\frac{13}{15}$


Solution : $\left[\frac{1}{5}+\left\{\frac{1}{6}\right.\right.$ of $\left.\left.\left(\frac{42}{35} \div \frac{6}{25}\right)–\left(\frac{2}{7} \times \frac{6}{5} \div \frac{18}{42}\right)\right\}+\frac{19}{30}\right]$
$=\left[\frac{1}{5}+\left\{\frac{1}{6}\right.\right.$ of $\left.\left.\left(\frac{42}{35} \times \frac{25}{6}\right)–\left(\frac{2}{7} \times \frac{6}{5} \times \frac{42}{18}\right)\right\}+\frac{19}{30}\right]$
$=[\frac{1}{5}+(\frac{1}{6}\times 5–\frac{4}{5})+\frac{19}{30}]$
$=[\frac{1}{5}+(\frac{5}{6}–\frac{4}{5})+\frac{19}{30}]$
$=[\frac{1}{5}+\frac{1}{30}+\frac{19}{30}]$
$=\frac{26}{30}$
$=\frac{13}{15}$
Hence, the correct answer is $\frac{13}{15}$.

10 Views

Question : If the radius of a circle is increased by 16%, its area increases by 

Option 1: 34.56%

Option 2: 32%

Option 3: 16%

Option 4: 17.28%

Team Careers360 21st Jan, 2024

Correct Answer: 34.56%


Solution : Let the radius of the original circle = $r$
So, the Area of the original circle = $\pi r^2$
 Radius of circle after 16% increase = $r+\frac{16r}{100} =1.16r$
Area of new circle = $\pi \times 1.16^2 = 1.3456r^2$
Percentage increase in area 
$\frac{1.3456\pi r^2- \pi

33 Views

Question : The radii of two concentric circles are 13 cm and 8 cm. AB is the diameter of the bigger circle and BD is a tangent to the smaller circle touching it at D and the bigger circle at E. Point A is joined to D. The length of AD is:

Option 1: 20 cm

Option 2: 19 cm

Option 3: 18 cm

Option 4: 17 cm

Team Careers360 25th Jan, 2024

Correct Answer: 19 cm


Solution :
Let the line BD intersect the bigger circle at point C.
Join AC.
OD $\perp$ BD ⇒ OD $\perp$ BC
So, BD = DC
⇒ D is the midpoint of BC.
Also, O is the midpoint of AB.
In $\triangle$BAC, O is the midpoint

10 Views

Question : Directions: In the question, a part of the sentence is in bold. Below are given alternatives to the bold part at 1, 2 and 3 that may improve the sentence. Choose the correct alternative. In case no improvement is needed, your answer is (4).

The gold is a precious metal.

(1) Gold

(2) A gold

(3) An gold

(4) No Improvement 

Option 1: 1

Option 2: 2

Option 3: 3

Option 4: 4

Team Careers360 24th Jan, 2024

Correct Answer: 1


Solution : The correct answer is the first option. 

"The gold" should be replaced with "Gold" as articles never come before a material noun so the article "the" should be removed. "Gold" is correctly used as a noun referring to the precious metal.

Therefore, the correct statement

15 Views

Question : Formalised system of trading agreements with groups of countries is known as

Option 1: Trading blocks

Option 2: Trade ventures

Option 3: Trade partners

Option 4: Trade organisations

Team Careers360 19th Jan, 2024

Correct Answer: Trading blocks


Solution : The Correct Answer is Trading blocks

Trading blocs are merely associations of nations that set the rules for international commerce. An example of an intergovernmental agreement is a trade bloc, which is frequently a component of a regional intergovernmental organization. In a trade bloc,

17 Views

Question : ABCD is a rhombus with $\angle$ABC = 52°. The measure of $\angle$ACD is:

Option 1: 54°

Option 2: 26°

Option 3: 48°

Option 4: 64°

Team Careers360 20th Jan, 2024

Correct Answer: 64°


Solution :
Since opposite angles of a rhombus are equal
So, $\angle$ADC = $\angle$ABC = 52°
Also, $\angle$DAC = $\angle$DCA = $x$ (say) [since AD = DC]
In $\triangle$ ADC,
$\angle$ADC + $\angle$DAC + $\angle$DCA = 180°
⇒ $x+x+52°$ = 180°
⇒ $x$ = 64°
⇒ $\angle$DCA

The question have been saved in answer later, you can access it from your profile anytime. Access now