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Question : Directions: A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
TABQ, VCET, XEHW, ZGKZ, ?

Option 1: BJMC

Option 2: BIND

Option 3: BJNC

Option 4: BINC

Team Careers360 18th Jan, 2024

Correct Answer: BINC


Solution : Given:
TABQ, VCET, XEHW, ZGKZ, ?

In the above-given series, add 2 to the place values of the first and second letters and add 3 to the place values of the third and fourth letters.
TABQ→T + 2 = V; A + 2 = C,

17 Views

Question : Directions: Select the option that represents the correct order of the given words as they would appear in an English dictionary.
1. Effluent
2. Edifice
3. Effleurage
4. Edacious
5. Effeminate
6. Eccentric
7. Effulgent

Option 1: 6, 4, 2, 5, 3, 1, 7

Option 2: 6, 4, 2, 3, 5, 1, 7

Option 3: 6, 4, 2, 5, 1, 3, 7

Option 4: 6, 4, 2, 5, 7, 3, 1

Team Careers360 21st Jan, 2024

Correct Answer: 6, 4, 2, 5, 3, 1, 7


Solution : Given:
1. Effluent 2. Edifice 3. Effleurage 4. Edacious 5. Effeminate 6. Eccentric 7. Effulgent

Step 1: Compare the first letter of each word. Since all the words start with the same letter E. So, move on to

7 Views

Question : Railway tracks are banked on curves so that

Option 1: the necessary centrifugal force may be obtained from the horizontal component of the weight of the train.

Option 2: no frictional force may be produced between the tracks and the wheels of the train.

Option 3: necessary centripetal force may be obtained from the horizontal component of the weight of the train.

Option 4: the train may not fall inwards.

Team Careers360 25th Jan, 2024

Correct Answer: necessary centripetal force may be obtained from the horizontal component of the weight of the train.


Solution : The correct option is necessary centrifugal force may be obtained from the horizontal component of the weight of the train.

A fast-moving train will typically veer off the track

16 Views

Question : Which of the following places is not a find-spot of major rock edicts of Ashoka?

Option 1: Sopara

Option 2: Mansehra

Option 3: Bhabru

Option 4: Jaugada

Team Careers360 22nd Jan, 2024

Correct Answer: Bhabru


Solution : The correct option is Bhabru.

Bhabru is not the major rock edict of Ashoka. It is a Minor edict. This is in Rajasthan. The rock edicts of Ashoka are among the earliest known examples of written records in the Indian subcontinent. This rock edict

10 Views

Question : Find the value of $a$ in the following equation. (Given $a<10 $)
$\frac{(187 \div 17 \times a-3 \times 3)}{\left(8^2-9 \times 7+a^2\right)}=1$

Option 1: 2

Option 2: 1

Option 3: 4

Option 4: 3

Team Careers360 20th Jan, 2024

Correct Answer: 1


Solution : $\frac{(187 \div 17 \times a-3 \times 3)}{\left(8^2-9 \times 7+a^2\right)}=1$
$⇒\frac{(11a-9)}{\left(a^2+1\right)}=1$
$⇒11a - 9 = a^2 + 1$
$⇒a^2 - 11a + 10 = 0$
$⇒(a - 10)(a - 1) = 0$
$⇒a = 10$ and $a = 1$
Since $a<10$
So, $a = 1$
Hence,

41 Views

Question : Which of the following activities is also referred to as the "Gold Collar" profession?

Option 1: Secondary

Option 2: Quaternary

Option 3: Primary

Option 4: Quinary

Team Careers360 20th Jan, 2024

Correct Answer: Quinary


Solution : The correct answer is the Quinary.

Quinary is also referred to as the “Gold Collar” profession. They represent another subdivision of the tertiary sector, which symbolises special and highly paid skills of financial and legal consultants, research assistants, government officials, etc. White Collar profession

24 Views

Question : Using $\operatorname{cosec}(\alpha+\beta)=\frac{\sec \alpha \times \sec \beta \times \operatorname{cosec} \alpha \times \operatorname{cosec} \beta}{\sec \alpha \times \operatorname{cosec} \beta+\operatorname{cosec} \alpha \times \sec \beta}$, find the value of $\operatorname{cosec} 75°$.

Option 1: $\frac{\sqrt{6}+\sqrt{2}}{4}$

Option 2: $\frac{\sqrt{6}-\sqrt{2}}{4}$

Option 3: $\sqrt{6}-\sqrt{2}$

Option 4: $\sqrt{6}+\sqrt{2}$

Team Careers360 19th Jan, 2024

Correct Answer: $\sqrt{6}-\sqrt{2}$


Solution : Given: $\operatorname{cosec}(\alpha+\beta)=\frac{\sec \alpha \times \sec \beta \times \operatorname{cosec} \alpha \times \operatorname{cosec} \beta}{\sec \alpha \times \operatorname{cosec} \beta+\operatorname{cosec} \alpha \times \sec \beta}$
To find the value of $\operatorname{cosec} 75°$, take $\alpha=45°,\beta=30°$
Now putting their values in the equation we get,
$\operatorname{cosec}(45°+30°) = \frac{\sec 45° \times \sec 30°

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