1 Million+
Questions
50k +
Active Users
24hrs max.
Answering Time
Question : A, B and C can work separately in 18, 36 and 54 days. They started the work together, but B and C left 5 days and 10 days, respectively, before the completion of the work. In how many days was the work finished?
Option 1: 15 days
Option 2: 13 days
Option 3: 14 days
Option 4: 12 days
Correct Answer: 13 days
Solution : A, B, and C can do work separately in 18, 36, and 54 days Let the total work = LCM (18, 36, and 54) = 108 units Efficiency = $\frac{\text{Total work}}{\text{Number of days}}$ So, Efficiency of A = $\frac{108}{16}$ = 6 Efficiency of B
Question : Directions: In the following question, from the given alternative words, select the word that cannot be formed using the letters of the given word. IMPROVEMENT
Option 1: ROPE
Option 2: TRIM
Option 3: IMPORTANT
Option 4: PROVE
Correct Answer: IMPORTANT
Solution : Given: IMPROVEMENT
Let's compare all the option words with the word IMPROVEMENT – First option: ROPE; All the letters of ROPE are present in the word IMPROVEMENT. Second option: TRIM; All the letters of TRIM are present in the word IMPROVEMENT. Third option: IMPORTANT; Only
Question : The slope of the given line is: :
Option 1: Positive
Option 2: Negative
Option 3: Undefined
Option 4: Zero
Correct Answer: Negative
Solution : The slope of this graph will be negative. Reason: Slope = m = $\tan\theta$ Here the $\theta > 90^{\circ}$ i.e., in the second quadrant. $\therefore\tan\theta$ is negative in the second quadrant. Hence, the correct answer is negative.
Question : If $\cos 21^{\circ}=\frac{x}{y}$, then $(\operatorname{cosec21^{\circ}}-\cos 69^{\circ})$ is equal to:
Option 1: $\frac{x^{2}}{y\sqrt{y^{2}-x^{2}}}$
Option 2:
$\frac{y^{2}}{x\sqrt{y^{2}-x^{2}}}$
Option 3:
$\frac{y^{2}}{x\sqrt{x^{2}-y^{2}}}$
Option 4: $\frac{x^{2}}{y\sqrt{x^{2}-y^{2}}}$
Correct Answer: $\frac{x^{2}}{y\sqrt{y^{2}-x^{2}}}$
Solution : Given: $\cos 21^{\circ}=\frac{x}{y}$ So, $\cos 69^{\circ}=\cos (90^{\circ}-21^{\circ})=\sin 21^{\circ}= \sqrt{1-\cos^2 21º}=\sqrt{1-\frac{x^2}{y^2}}=\frac{\sqrt{y^2-{x^2}}}{y}$ Also, $\operatorname{cosec21^{\circ}}=\frac{1}{\sin 21^{\circ}}=\frac{y}{\sqrt{y^2-{x^2}}}$ Now, $(\operatorname{cosec21^{\circ}}-\cos 69^{\circ})=\frac{y}{\sqrt{y^2-{x^2}}}-\frac{\sqrt{y^2-{x^2}}}{y}$ ⇒ $(\operatorname{cosec21^{\circ}}-\cos 69^{\circ})=\frac{y^2-(y^2-x^2)}{y\sqrt{y^2-{x^2}}}=\frac{x^{2}}{y\sqrt{y^{2}-x^{2}}}$ Hence, the correct answer is $\frac{x^{2}}{y\sqrt{y^{2}-x^{2}}}$.
Question : The distance of a chord OP from the centre of a circle is 6 cm. If the diameter of this circle is 20 cm, then what will be the sum of the radius and length of chord OP?
Option 1: 18 cm
Option 2: 26 cm
Option 3: 16 cm
Option 4: 20 cm
Correct Answer: 26 cm
Solution : Let the radius of the circle as \(r\) and the length of the chord OP as \(L\). Given that the diameter of the circle is 20 cm, the radius is \(r = \frac{20}{2} = 10\) cm. Use the Pythagorean theorem to find the length
Question : Study the given pie chart and answer the question that follows. Break-up (degree-wise) the number of students in five schools (A, B, C, D, and E) in a city. Total number of students is 5200. The number of students in school C is what percentage more than the number of students in school B?
Option 1: 11%
Option 2: 10%
Option 3: 9.5%
Option 4: 7.2%
Correct Answer: 10%
Solution : As per the given graph, The number of students in school C is more than the number of students in school B by $=\frac{( 79.2 − 72 )}{72}$ × 100% $= 10$% Hence, the correct answer is 10%
Question : The given bar graph shows the number of students of two schools over six years. In the bar graph, what is the ratio of the students taken for years 2008, 2012, and 2013 together from school A to the students taken for the years 2009, 2010, and 2011 together from school B?
Option 1: 118: 251
Option 2: 229: 217
Option 3: 251: 118
Option 4: 217: 229
Correct Answer: 229: 217
Solution : The average of total students from school A 2008, 2012, and 2013 = 640 + 900 + 750 = 2290 The average of total students from school B in 2009, 2010, and 2011 = 820 + 600 + 750 = 2170 The required ratio
Question : Select the option that can be used as a one-word substitute for the given group of words. A person having significant experience in an occupation.
Option 1: Agnostic
Option 2: Fastidious
Option 3: Veteran
Option 4: Novice
Correct Answer: Veteran
Solution : The correct choice is the third option.
A veteran is a person who has considerable experience or has been involved in a particular activity, profession, or occupation for a long time. They are highly skilled or knowledgeable due to their extensive experience.
The meanings
Question : Directions: In the following question, a sentence is given with a blank that is to be filled in with an appropriate word. Four alternatives are suggested; choose the correct alternative out of them as your answer.
A person came in with a baby who, she said, _____________ a safety pin.
Option 1: Swallowed
Option 2: Just swallowed
Option 3: Had just swallowed
Option 4: Was just swallowing
Correct Answer: Had just swallowed
Solution : The third option is the correct answer, since "had just swallowed" is the correct verb form to be used here as per past perfect tense. The sentence indicates that the baby had recently swallowed a safety pin before the person brought it
Question : A cylindrical tank of capacity $64\pi$ litres has equal height and radius. What would be the radius of the cylinder? (1 litre = 1000 cm3)
Option 1: 5 cm
Option 2: 40 cm
Option 3: 50 cm
Option 4: 4 cm
Correct Answer: 40 cm
Solution : Let the height and radius of the cylinder be $x$. Given volume = $64\pi$ litres = $64000\pi$ cm3 We know that, Volume of the cylinder = $\pi r^2h$ So, $\pi\times x^2\times x=64000\pi$ ⇒ $x^3=64000$ $\therefore x= 40$ Hence, the correct answer is 40
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update