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Question : If A's income is 60% less than B's income, then B's income is what percentage more than that of A's income?
Option 1: 40%
Option 2: 150%
Option 3: 120%
Option 4: 80%
Correct Answer: 150%
Solution : Let the B's income = 100 Since A's income is 60% less than B's income A's income = 100 – 60 = 40 So, A's income is 60 more than B's income The required percentage = $\frac{60}{40}$ × 100 = 150% So, A's income is
Question : Directions: In the question, a part of the sentence is in bold. Below are given alternatives to the bold part at 1, 2 and 3 that may improve the sentence. Choose the correct alternative. In case no improvement is needed, your answer is (4).
We do not believe in a dual policy of the company.
(1) in this dual
(2) in these dual
(3) on these dual
(4) No Improvement
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 1
Solution : The correct improvement for the sentence is: in this dual
Explanation: This option suggests replacing "in a dual" with "in this dual." "We do not believe in this dual policy of the company" provides a more specific and clear reference to the policy being discussed.
Question : Directions: Which two numbers should be interchanged to make the given equation correct? 5 × 7 – 4 + 21 ÷ 6 = 29
Option 1: 6 and 5
Option 2: 6 and 7
Option 3: 21 and 29
Option 4: 5 and 4
Correct Answer: 6 and 7
Solution : Given: 5 × 7 – 4 + 21 ÷ 6 = 29
Replace the given numbers in the options with the original numbers in the given equation. First option: 6 and 5 Solving the L.H.S. of the equation – = 6 × 7
Question : A car starts from point A towards point B, travelling at the speed of 20 km/hr. $1\frac{1}{2}$ hours later, another car starts from the point and travels at the speed of 30 km/hr and reaches $2\frac{1}{2}$ hours before the first car. Find the distance between A and B.
Option 1: 300 km
Option 2: 240 km
Option 3: 260 km
Option 4: 280 km
Correct Answer: 240 km
Solution : Let the time taken by the first car to reach point B be $t$ hours. The time taken by the second car to reach point B = $t - 1\frac{1}{2} - 2\frac{1}{2} = t - 4$ hours Since the distance travelled is the same
Question : Directions: In each of the following questions, a piece of paper is folded and cut as shown below in the question figures. From the given answer figures, indicate how it will appear when opened.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : When the given folded paper is unfolded, it will look like –
Hence, the second option is correct.
Question : If $\sin A=\frac{5}{13}$ and $7 \cot B=24$, then the value of $(\sec A \cos B)(\operatorname{cosec} B \tan A)$ is:
Option 1: $\frac{65}{42}$
Option 2: $\frac{13}{14}$
Option 3: $\frac{15}{13}$
Option 4: $\frac{13}{7}$
Correct Answer: $\frac{65}{42}$
Solution : Given that $\sin A=\frac{5}{13}$ and $7 \cot B=24$, $\sin A=\frac{5}{13}$, Use the identity $\sin^2 A + \cos^2 A = 1$ $⇒\cos A = \sqrt{1 - \sin^2 A} = \sqrt{1 - \left(\frac{5}{13}\right)^2} = \frac{12}{13}$ $\therefore\tan A = \frac{\sin A}{\cos A} = \frac{5}{12}$ $\therefore\sec A = \frac{1}{\cos
Question : Which one of the following is the first national park in India?
Option 1: Corbett National Park
Option 2: Bandipur National Park
Option 3: Kanha National Park
Option 4: Sariska Tiger Reserve
Correct Answer: Corbett National Park
Solution : The correct answer is Corbett National Park.
Jim Corbett National Park was the first national park in India. National parks in India are established under the Wildlife Protection Act of 1972. Jim Corbett National Park was established in 1936. Earlier, it was
Question : If $\frac{x-x\tan^{2}30^{\circ}}{1+\tan^{2}30^{\circ}}=\sin^{2}30^{\circ}+4\cot^{2}45^{\circ}-\sec^{2}60^{\circ}$, then value of $x$ is:
Option 1: $\frac{1}{4}$
Option 2: $\frac{1}{5}$
Option 3: $\frac{1}{2}$
Option 4: $\frac{1}{\sqrt3}$
Correct Answer: $\frac{1}{2}$
Solution : Given the equation, $\frac{x-x\tan^{2}30^{\circ}}{1+\tan^{2}30^{\circ}}=\sin^{2}30^{\circ}+4\cot^{2}45^{\circ}-\sec^{2}60^{\circ}$ We know that $\tan30^{\circ} = \frac{1}{\sqrt{3}}$, $\sin30^{\circ} = \frac{1}{2}$, $\cot45^{\circ} = 1$, and $\sec60^{\circ} = 2$. $⇒\frac{x-x(\frac{1}{3})}{1+( \frac{1}{3})}=\left(\frac{1}{2}\right)^2+4(1)^2-(2)^2$ $⇒\frac{\frac{2x}{3}}{\frac{4}{3}}=\frac{1}{4}+4-4$ $⇒\frac{1}{2}x=\frac{1}{4}$ $⇒x=\frac{1}{2}$ Hence, the correct answer is $\frac{1}{2}$.
Question : Choose the word that can substitute the given group of words. A game that results neither in victory nor in defeat
Option 1: Void
Option 2: Cynic
Option 3: Draw
Option 4: Fawn
Correct Answer: Draw
Solution : The correct choice is the third option.
Draw means a result of a game or competition in which both players or teams get the same score so that neither of them wins. For the substitution of the given phrase, the word "draw" is the
Question : Directions: Which two numbers from amongst the given options should be interchanged to make the given equation correct? (63 ÷ 9 + 17) ÷ 11 = 15 – 195 ÷ 17 – 2
Option 1: 11 and 15
Option 2: 17 and 15
Option 3: 195 and 63
Option 4: 2 and 15
Correct Answer: 17 and 15
Solution : Given: (63 ÷ 9 + 17) ÷ 11 = 15 – 195 ÷ 17 – 2
Replace the given numbers in the options one by one with the original numbers in the given equation. First option: 11 and 15 ⇒ (63 ÷ 9
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