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19 Views

Question : The expression $\frac{\tan ^6 \theta-\sec ^6 \theta+3 \sec ^2 \theta \tan ^2 \theta}{\tan ^2 \theta+\cot ^2 \theta+2}, 0^{\circ}<\theta<90^{\circ}$, is equal to:

Option 1: $\sec ^2 \theta \operatorname{cosec}^2 \theta$

Option 2: $-\sec ^2 \theta \operatorname{cosec}^2 \theta$

Option 3: $\cos ^2 \theta \sin ^2 \theta$

Option 4: $-\cos ^2 \theta \sin ^2 \theta$

Team Careers360 21st Jan, 2024

Correct Answer: $-\cos ^2 \theta \sin ^2 \theta$


Solution : $\frac{\tan ^6 \theta-\sec ^6 \theta+3 \sec ^2 \theta \tan ^2 \theta}{\tan ^2 \theta+\cot ^2 \theta+2}$
Since $0^{\circ}<\theta<90^{\circ}$, putting $\theta=45^{\circ}$
$\frac{\tan ^6 45^{\circ}-\sec ^6 45^{\circ}+3 \sec ^2 45^{\circ} \tan ^2 45^{\circ}}{\tan ^2 45^{\circ}+\cot ^245^{\circ}+2}$
$=\frac{1-(\sqrt2)^6+ 3\times (\sqrt2)^2\times 1}{1+1+2}$
$=\frac{1-8+6}{1+1+2}=-\frac{1}{4}$
From option

12 Views

Question : Directions: How many triangles are there in the given figure?

Option 1: 14

Option 2: 15

Option 3: 16

Option 4: 19

Team Careers360 14th Jan, 2024

Correct Answer: 15


Solution : The figure can be labeled as shown below –

There are a total of 15 triangles in the figure. They are AHB, AHD, BHC, DHC, ABD, BCD, BAC, ADC, EHC, CHF, GHF, CHG, BHE, DHG, DHF.

Hence, the second option is correct.

23 Views

Question : Simplify the given expression.
$
\frac{432 \times 432+247 \times 247-432 \times 247}{432 \times 432 \times 432+247 \times 247 \times 247}
$

Option 1: $\frac{1}{259}$

Option 2: $\frac{1}{185}$

Option 3: $\frac{1}{679}$

Option 4: $\frac{1}{450}$

Team Careers360 15th Jan, 2024

Correct Answer: $\frac{1}{679}$


Solution : $\frac{432^2+247^2-432 \times 247}{432^3+247^3}$
Using identity $x^3+y^3 = (x+y)(x^2+y^2-x \times y)$, 
$\frac{432^2+247^2-432 \times 247}{(432+247)(432^2+247^2-432 \times 247)}$
$=\frac{1}{(432+247)}$
$= \frac{1}{679}$
Hence, the correct answer is $\frac{1}{679}$.

41 Views

Question : Select the option that expresses the given sentence in active voice.

By whom can the problem be solved?

Option 1: Whom can solve the problem?

Option 2: Who can solved the problem?

Option 3: Whom can solved the problem?

Option 4: Who can solve the problem?

Team Careers360 20th Jan, 2024

Correct Answer: Who can solve the problem?


Solution : The correct choice is the fourth option.

The active voice sentence follows the structure: Subject + Verb + Object.

The original sentence is in the passive voice. The active voice version shifts the focus to the doer of the action,

64 Views

Question : A bag has Rs. 20.1 in the form of 1 rupee, 50-paise, and 10-paise coins in the ratio of $5:3:2$. What is the number of 50-paise coins in the bag?

Option 1: 6

Option 2: 9

Option 3: 15

Option 4: 3

Team Careers360 19th Jan, 2024

Correct Answer: 9


Solution : Given: The ratio of 1 rupee, 50 paise and 10 paise coins = $5:3:2$
And the total amount of money in the bag = Rs. 20.1
Let the number of 1 rupee, 50 paise, and 10 paise coins be $5x, 3x$ and $2x$ respectively.
Amount

65 Views

Question : Identify the segment that contains a grammatical error. If there is no error, select 'No error.'

Before he could devote many more / thought to the matter, Pranav / had stepped up to him.

Option 1: before he could devote many more

Option 2: thought to the matter, Pranav

Option 3: had stepped up to him

Option 4: No error

Team Careers360 23rd Jan, 2024

Correct Answer: before he could devote many more


Solution : The error lies in the first option.

  • The use of "many more" is incorrect in this context.
  • The word "many" is not needed here. Instead, it should be "any more" to convey the idea that before Pranav could give additional
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