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Question : ABC is an isosceles right-angle triangle. $\angle ABC = 90 ^{\circ}$ and AB = 12 cm. What is the ratio of the radius of the circle inscribed in it to the radius of the circle circumscribing $\triangle ABC$?

Option 1: $6–\sqrt{2}: 3 \sqrt{2}$

Option 2: $2–\sqrt{2}: \sqrt{2}$

Option 3: $6–3 \sqrt{2}: 1 \sqrt{2}$

Option 4: $6–3 \sqrt{2}: 6 \sqrt{2}$

Team Careers360 17th Jan, 2024

Correct Answer: $2–\sqrt{2}: \sqrt{2}$


Solution :
Given: ABC is an isosceles right-angle triangle. $\angle ABC = 90 ^{\circ}$ and AB = 12 cm.
In $\triangle ABC$, $H^2=B^2+P^2$ (Using Pythagoras theorem).
⇒ $H^2=12^2+12^2$
⇒ $H^2=144+144=288$
⇒ $H=\sqrt{288}=12\sqrt2$ cm
Inradius of inscribed circle of right angled triangle = $\frac{(P + B –

15 Views

Question : What is the value of $\frac{7}{2}+\frac{11}{3}+\frac{7}{6}+\frac{11}{15}+\frac{7}{12}+\frac{11}{35}+\ldots \ldots+\frac{7}{156}+\frac{11}{575}$?

Option 1: $\frac{3917}{355}$

Option 2: $\frac{3816}{325}$

Option 3: $\frac{3714}{345}$

Option 4: $\frac{3216}{315}$

Team Careers360 23rd Jan, 2024

Correct Answer: $\frac{3816}{325}$


Solution : Given: The series is $\frac{7}{2}+\frac{11}{3}+\frac{7}{6}+\frac{11}{15}+\frac{7}{12}+\frac{11}{35}+\ldots \ldots+\frac{7}{156}+\frac{11}{575}$.
Determine the value of the series by solving two distinct series independently.
The sum of the first series = $\frac{7}{2}+\frac{7}{6}+\frac{7}{12}+...+\frac{7}{156}$
⇒ Sum = $7[1–(\frac{1}{2})+(\frac{1}{2}–\frac{1}{3})+(\frac{1}{3}–\frac{1}{4})+...+(\frac{1}{12}–\frac{1}{13})]$
⇒ Sum = $7[1–\frac{1}{13}]$
⇒ Sum = $7\times\frac{12}{13}=\frac{84}{13}$
The sum of the second series =

11 Views

Question : Directions: Select the correct combination of mathematical signs to replace × signs and to balance the following equation.
5 × 9 × 3 × 6 × 8

Option 1: ×, +, =, ×

Option 2: ×, –, =, ×

Option 3: +, ÷, –, =

Option 4: +, ×, ÷, =

Team Careers360 17th Jan, 2024

Correct Answer: ×, +, =, ×


Solution : Given:
5 × 9 × 3 × 6 × 8

On replacing × with the mathematical signs –
First option: ×, +, =, ×
L.H.S. = 5 × 9 + 3 = 45 + 3 = 48
R.H.S. = 6 × 8

26 Views

Question : Directions: Select the option related to the third term in the same way as the second term is related to the first term.
MONDAY : RJSIVD :: TROUBLE : ?

Option 1: XWJPFQJ

Option 2: YVJPFQZ

Option 3: YWJPGQZ

Option 4: CWJQGQZ

Team Careers360 25th Jan, 2024

Correct Answer: YWJPGQZ


Solution : Given:
MONDAY : RJSIVD :: TROUBLE : ?

Add 5 to the consonants and subtract 5 from the vowels of the given term to obtain the required term –
M + 5 = R; O – 5 = J; N + 5 = S; D

21 Views

Question : If $x+\left [\frac{1}{(x+7)}\right]=0$, what is the value of $x-\left [\frac{1}{(x+7)}\right]$?

Option 1: $3\sqrt{5}$

Option 2: $3\sqrt{5}-7$

Option 3: $3\sqrt{5}+7$

Option 4: $8$

Team Careers360 13th Jan, 2024

Correct Answer: $3\sqrt{5}-7$


Solution : Given: $x+[\frac{1}{(x+7)}]=0$
Adding both sides 7, we get,
⇒ $x+7+[\frac{1}{(x+7)}]=7$
Squaring both sides, we get,
⇒ $(x+7)^{2}+(\frac{1}{x+7})^{2}+2=49$
⇒ $(x+7)^{2}+(\frac{1}{x+7})^{2}=47$
Subtracting 2 from both sides,
$(x+7)^{2}+(\frac{1}{x+7})^{2}–2=47-2$
⇒ $[(x+7)-(\frac{1}{x+7})]^{2}=45$
⇒ $[(x+7)-(\frac{1}{x+7})]=\sqrt{45}$
⇒ $[(x-\frac{1}{x+7})]=\sqrt{45}-7=\sqrt{9 \times5}-7=3\sqrt{5}–7$
Hence, the correct answer is $3\sqrt{5}-7$.

8 Views

Question : Directions: The position of how many letters will remain unchanged if each letter in the word KINGDOM is arranged alphabetically.

Option 1: Three

Option 2: None

Option 3: One

Option 4: Two

Team Careers360 17th Jan, 2024

Correct Answer: None


Solution : Given:
KINGDOM

When the letters of KINGDOM are arranged in alphabetical order, the letter cluster formed is DGIKMNO.
Now, the position of the letters that remain unchanged in the new letter cluster formed is as follows –

So, from the above figure, it can be

18 Views

Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No error".

The boy who studies hard (1) / he will pass (2) / with flying colours. (3) / No error (4)

Option 1: (1)

Option 2: (2)

Option 3: (3)

Option 4: (4)

Team Careers360 17th Jan, 2024

Correct Answer: (2)


Solution : The error lies in the second part of the sentence.

The pronoun he should be removed as its use is superfluous and makes the sentence incoherent. The clause will pass with flying colours needs to be linked with the preceding clause, and the removal of

52 Views

Question : Parts of the following sentence have been given as options. Select the option that contains an error.

You need to acknowledge the itinary and accommodation details of your journey as per the given calendar.

Option 1: calendar

Option 2: accommodation

Option 3: acknowledge

Option 4: itinary

Team Careers360 20th Jan, 2024

Correct Answer: itinary


Solution : The correct choice is the fourth option.

The error lies in the misspelling of "itinerary". The correct spelling is itinerary. An itinerary refers to a planned route or travel schedule, and the correct spelling is crucial for clarity and accuracy in communication.

Therefore, the correct

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