It's a Question of your Career!

Correct Answer: Mercury

Solution : The correct option is mercury.

Mercury, specifically methylmercury, a highly poisonous chemical, responsible for the Minamata sickness. The release of methylmercury into bodies of water poisoned fish, resulting in significant health problems for the people.
 

Correct Answer: CHLP

Solution : Let's check each option –
First option: PUXZ→P + 5 = U; U + 3 = X; X + 2 = Z
Second option: CHLP→C + 5 = H; H + 4 = L; L + 4 = P 
Third option: TYBD→T + 5 =

Correct Answer: Sitar

Solution : The correct option is Sitar.

Ustad Vilayat Khan was a renowned Indian classical musician known for playing the Sitar. He was a legendary Sitar virtuoso and a prominent figure in the world of classical music. He received numerous awards and honours for his contributions to

Correct Answer: Madhya Pradesh

Solution : The correct answer is Madhya Pradesh.

Hazira-Vijaipur-Jagdishpur, or HVJ, is the first interstate gas pipeline in India. To supply gas to fertiliser factories in the state of Uttar Pradesh, the project got underway in 1986 with the formation of GAIL Limited.

With a

Correct Answer: Ocean

Solution : The correct answer is ocean.

The ocean or marine ecosystem is the largest ecosystem in the world and it is the most stable ecosystem. Water covers nearly 71% of the earth's surface area. While ecosystem is a self sustaining unit of interacting living organisms and

Correct Answer: 40

Solution : Given:
Let the original no of men be $x$.
$x$ men can finish it in 60 days,
and $(x+8)$ men can finish in 50 days.
$M_{1}D_{1}=M_{2}D_{2}$, where $M_1$ and $M_2$ are men and $D_1$ and $D_2$ are days.
$⇒60x = 50(x+8)$
$⇒10x= 400$
$\therefore x

Correct Answer: 3576

Solution : Given,
The total price of all these 6 articles is Rs. 5760
P1 = The difference between the average price of K and L and the average price of J and N.
Price of K = $\frac{42°}{360°}\times 5760=672$
And, Price of L = $\frac{116°}{360°}\times5760=1856$
$\therefore$

Correct Answer: cbba

Solution : Given:
bb_aab_caab_ca_

To fill the series we have to divide the series – bb_aa / b_caa / b_ca_
Let's check each option –
First option: abac; bbaaa / bbcaa / bacac (No repeated pattern has been found.)
Second

Correct Answer: 720

Solution : Given: Lateral surface area of prism = 480 cm²
Lateral surface area of prism = perimeter of base × height
Perimeter of triangle = 8 + 15 + 17 = 40 cm 
Let the height of the prime is $h$ cm 
⇒ $40 ×

Correct Answer: – 6.83

Solution : Computing RHS,
$\sin ^2 60^{\circ}+4 \tan ^2 45^{\circ}-\operatorname{cosec}^2 60^{\circ} = (\frac{\sqrt{3}}{2})^2+4\times1^2-(\frac{2}{\sqrt{3}})^2$
⇒ $\sin ^2 60^{\circ}+4 \tan ^2 45^{\circ}-\operatorname{cosec}^2 60^{\circ} = \frac{3}{4}+4-\frac{4}{3}$
⇒ $\sin ^2 60^{\circ}+4 \tan ^2 45^{\circ}-\operatorname{cosec}^2 60^{\circ} = \frac{41}{12}$
Computing LHS,
$ \frac{k-k \cot ^2 30^{\circ}}{1+\cot ^2 30^{\circ}} = k(\frac{1- (\sqrt{3})^2}{1+(\sqrt{3})^2})$
⇒