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16 Views

Question : If $x^{2}+y^{2}+6x+5=4(x-y)$, then $(x-y)$ is:

Option 1: $1$

Option 2: $0$

Option 3: $–1$

Option 4: $4$

Team Careers360 25th Jan, 2024

Correct Answer: $1$


Solution : Given: $x^{2}+y^{2}+6x+5=4(x-y)$
⇒ $x^{2}+y^{2}+6x+5-4x+4y=0$
⇒ $x^{2}+y^{2}+2x+5+4y=0$
⇒ $x^{2}+2x+1+y^{2}+4y+4=0$
⇒ $x^{2}+2×x×1+1+y^{2}+2×y×2+4=0$
⇒ $(x+1)^{2}+(y+2)^{2}=0$
⇒ $x$ = – 1 and $y$ = – 2 [If the sum of two square terms is zero, then each term will also be zero]
So, $(x-y) = (–1–( –2))=1$
Hence, the

16 Views

Question : Who was the founder of Satyashodak Sabha in Maharashtra?

Option 1: Dr. Baba Saheb Ambedkar

Option 2: Dr. Atmaram Pandurang

Option 3: Gopal Baba Walangkar

Option 4: Jyotiba Phule

Team Careers360 25th Jan, 2024

Correct Answer: Jyotiba Phule


Solution : The correct answer is Jyotiba Phule.

Jyotiba Phule was a Maharashtrian social reformer. Jyotiba Phule founded Satyashodhak Sabha in 1873 in Pune, Maharashtra. It was a social reform society which helped to promote education, social rights, and Justice in deprived sections of the society.

10 Views

Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No error".

Ramesh smiled when he was remembering (1) / his hard early years (2) / and his long road to success. (3) / No error (4)

Option 1: (1)

Option 2: (2)

Option 3: (3)

Option 4: (4)

Team Careers360 25th Jan, 2024

Correct Answer: (1)


Solution : The error lies in the first part of the sentence.

When we want to talk about our memories, it is common to use the simple past tense i.e., remembered instead of the past continuous tense i.e., was remembering.

Therefore, the correct sentence is: "Ramesh smiled

435 Views

Question : If successive discounts of 5%, 10%, and p% are equivalent to a single discount of 31.6%, the value of p is:

Option 1: 15

Option 2: 25

Option 3: 20

Option 4: 30

Team Careers360 25th Jan, 2024

Correct Answer: 20


Solution : Single equivalent discount = $(a+b–\frac{a×b}{100})\%$, where $a$% and $b$% are two successive discounts.
Single discount of 5% and 10% $= 5 + 10 - \frac{(50)}{100}=14.5$
Now, single discount of 14.5% and $p$% $= 14.5 + p - \frac{(14.5p)}{100}$
According to the question,
$14.5 + p

18 Views

Question : If $\cot \theta=\frac{4}{3}, 0<\theta<\frac{\pi}{2}$, and $5 p \cos ^2 \theta \sin \theta=\cot ^2 \theta$, then the value of $p$ is:

Option 1: $\frac{7}{27}$

Option 2: $\frac{125}{27}$

Option 3: $\frac{5}{27}$

Option 4: $\frac{25}{27}$

Team Careers360 25th Jan, 2024

Correct Answer: $\frac{25}{27}$


Solution : Here, $\cot \theta = \frac{\text {Base}} {\text{Perpendicular}}$
Let Base = 4 units and Perpendicular = 3 units
Now, Using the Pythagoras theorem,
$H^2 = P^2 + B^2$
⇒ $H = \sqrt{(P2 + B2)}$
⇒ $H = \sqrt{(32 + 42)}$
⇒ $H = \sqrt{(9 + 16)}$

7 Views

Question : Directions: Which two digits should be interchanged in the given equation to make it mathematically correct?
20 ÷ 7 × 2 + 5 – 3 = 12

Option 1: 2 and 3

Option 2: 7 and 5

Option 3: 7 and 2

Option 4: 2 and 5

Team Careers360 25th Jan, 2024

Correct Answer: 7 and 5


Solution : Given:
20 ÷ 7 × 2 + 5 – 3 = 12

Let's check each option –
First Option: 2 and 3
On interchanging the digits, we get –
30 ÷ 7 × 3 + 5 – 2 = 13
On solving the

11 Views

Question : In the following question, out of the given fout alternatives, select the alternative which best expresses the meaning of the Idiom/Phrase.

From rags to riches

Option 1: From everywhere

Option 2: Reasonable pricing

Option 3: To toil very hard to gain something

Option 4: From extreme poverty to wealth

Team Careers360 25th Jan, 2024

Correct Answer: From extreme poverty to wealth


Solution : The correct choice is the fourth option.

The idiom "from rags to riches" conveys the idea of a dramatic improvement in financial or social status, specifically from extreme poverty (symbolised by "rags") to wealth and prosperity ("riches").

Therefore, the alternative "from

67 Views

Question : At the location of which city in Assam, the River Brahmaputra goes south breaking, away from its westward course and entering Bangladesh?

Option 1: Bongaigaon

Option 2: Tezpur

Option 3: Dhubri

Option 4: Barpeta

Team Careers360 25th Jan, 2024

Correct Answer: Dhubri


Solution : The correct answer is Dhubri.

The Brahmaputra River runs west till it reaches Dhubri, Assam. From there, it divides south in the Garo highlands and flows close to Golpara, Bangladesh. It flows past Chilmari, Bangladesh, joins the Tista River on its right bank and

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