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Question : Directions: Select the correct combination of mathematical signs to replace signs and balance the following equation. 21 * 7 * 6 * 9
Option 1: +, ÷, =
Option 2: ÷, +, =
Option 3: =, +, ÷
Option 4: ÷, =, +
Correct Answer: ÷, +, =
Solution : Given: 21 * 7 * 6 * 9
Let's check the options – First option: +, ÷, = ⇒ 21 + 7 ÷ 6 = 9 Solving the L.H.S. of the equation – = 21 + 7 ÷ 6 = 21 + 1.67
Question : Select the most appropriate ANTONYM of the given word. Redemption
Option 1: Salvation
Option 2: Blasphemy
Option 3: Corrugation
Option 4: Conjunction
Correct Answer: Blasphemy
Solution : The second option is the correct choice.
Redemption refers to the action of saving or being saved from sin, error, or evil. It can also mean the act of regaining or gaining something back, often in a positive sense. Blasphemy refers to the act
Question : Select the option that expresses the given sentence in reported speech. I said, "I took a lot of precautions after my surgery."
Option 1: I said that I have taken a lot of precautions after my surgery.
Option 2: I said that I had taken a lot of precautions after my surgery.
Option 3: I said that I will take a lot of precautions after my surgery.
Option 4: I said that I took a lot of precautions after my surgery.
Correct Answer: I said that I had taken a lot of precautions after my surgery.
Solution : The correct choice is the second option.
Indirect speech, also known as reported speech or indirect discourse, is a way of reporting what someone else has said without quoting their exact words.
The
Question : If $x^{2}+y^{2}+6x+5=4(x-y)$, then $(x-y)$ is:
Option 1: $1$
Option 2: $0$
Option 3: $–1$
Option 4: $4$
Correct Answer: $1$
Solution : Given: $x^{2}+y^{2}+6x+5=4(x-y)$ ⇒ $x^{2}+y^{2}+6x+5-4x+4y=0$ ⇒ $x^{2}+y^{2}+2x+5+4y=0$ ⇒ $x^{2}+2x+1+y^{2}+4y+4=0$ ⇒ $x^{2}+2×x×1+1+y^{2}+2×y×2+4=0$ ⇒ $(x+1)^{2}+(y+2)^{2}=0$ ⇒ $x$ = – 1 and $y$ = – 2 [If the sum of two square terms is zero, then each term will also be zero] So, $(x-y) = (–1–( –2))=1$ Hence, the
Question : Who was the founder of Satyashodak Sabha in Maharashtra?
Option 1: Dr. Baba Saheb Ambedkar
Option 2: Dr. Atmaram Pandurang
Option 3: Gopal Baba Walangkar
Option 4: Jyotiba Phule
Correct Answer: Jyotiba Phule
Solution : The correct answer is Jyotiba Phule.
Jyotiba Phule was a Maharashtrian social reformer. Jyotiba Phule founded Satyashodhak Sabha in 1873 in Pune, Maharashtra. It was a social reform society which helped to promote education, social rights, and Justice in deprived sections of the society.
Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No error".
Ramesh smiled when he was remembering (1) / his hard early years (2) / and his long road to success. (3) / No error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (1)
Solution : The error lies in the first part of the sentence.
When we want to talk about our memories, it is common to use the simple past tense i.e., remembered instead of the past continuous tense i.e., was remembering.
Therefore, the correct sentence is: "Ramesh smiled
Question : Directions: In a certain code language, E + M means E is the father of M, E – M means E is the husband of M, E @ M means E is the daughter of M, E # M means E is the mother of M. If R # A – F # H, then how is R related to F?
Option 1: Mother
Option 2: Husband's mother
Option 3: Sister
Option 4: Father's sister
Correct Answer: Husband's mother
Solution : Given: A – F means A is the husband of F. R # A means R is the mother of A. F # H means F is the mother of H.
As per the given instructions, the family tree will be –
Here, the
Question : If successive discounts of 5%, 10%, and p% are equivalent to a single discount of 31.6%, the value of p is:
Option 1: 15
Option 2: 25
Option 3: 20
Option 4: 30
Correct Answer: 20
Solution : Single equivalent discount = $(a+b–\frac{a×b}{100})\%$, where $a$% and $b$% are two successive discounts. Single discount of 5% and 10% $= 5 + 10 - \frac{(50)}{100}=14.5$ Now, single discount of 14.5% and $p$% $= 14.5 + p - \frac{(14.5p)}{100}$ According to the question, $14.5 + p
Question : If $\cot \theta=\frac{4}{3}, 0<\theta<\frac{\pi}{2}$, and $5 p \cos ^2 \theta \sin \theta=\cot ^2 \theta$, then the value of $p$ is:
Option 1: $\frac{7}{27}$
Option 2: $\frac{125}{27}$
Option 3: $\frac{5}{27}$
Option 4: $\frac{25}{27}$
Correct Answer: $\frac{25}{27}$
Solution : Here, $\cot \theta = \frac{\text {Base}} {\text{Perpendicular}}$ Let Base = 4 units and Perpendicular = 3 units Now, Using the Pythagoras theorem, $H^2 = P^2 + B^2$ ⇒ $H = \sqrt{(P2 + B2)}$ ⇒ $H = \sqrt{(32 + 42)}$ ⇒ $H = \sqrt{(9 + 16)}$
Question : Directions: Which two digits should be interchanged in the given equation to make it mathematically correct? 20 ÷ 7 × 2 + 5 – 3 = 12
Option 1: 2 and 3
Option 2: 7 and 5
Option 3: 7 and 2
Option 4: 2 and 5
Correct Answer: 7 and 5
Solution : Given: 20 ÷ 7 × 2 + 5 – 3 = 12
Let's check each option – First Option: 2 and 3 On interchanging the digits, we get – 30 ÷ 7 × 3 + 5 – 2 = 13 On solving the
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