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Question : If $x^4+\frac{1}{x^4}=194$ and $x^3+\frac{1}{x^3}=?$
Option 1: 52
Option 2: 58
Option 3: 76
Option 4: 67
Correct Answer: 52
Solution : $x^4+\frac{1}{x^4}=194$ Adding 2 on both sides, ⇒ $x^4+\frac{1}{x^4}+2=194+2$ ⇒ $(x^2+\frac{1}{x^2})^2=196$ Taking square root on both sides, ⇒ $x^2+\frac{1}{x^2}=14$ Adding 2 on both sides, ⇒ $x^2+\frac{1}{x^2}+2=14+2$ ⇒ $(x+\frac{1}{x})^2=16$ Taking square root on both sides, ⇒ $x+\frac{1}{x}=4$ ⇒ $(x+\frac{1}{x})^3=4^3$ ⇒ $x^3+\frac{1}{x^3}+3(x+\frac{1}{x})=64$ ⇒ $x^3+\frac{1}{x^3}+3×4=64$ ⇒ $x^3+\frac{1}{x^3}=64-12 = 52$
Question : Directions: A is the mother of B. C is the son of A. D is the brother of E, and E is the daughter of B. Who is the grandmother of E?
Option 1: A
Option 2: B
Option 3: C
Option 4: D
Correct Answer: A
Solution : As per the given information, the family tree will be as follows –
Here, the quadrilateral represents the male, and the circular figure represents the female in the figure.
So, from the above family tree, A is the grandmother of E. Hence, the first option
Question : A can do a work alone in 60 days and B can do the same work alone in 33.33% less time taken by A. Find the time taken by B to complete the work alone.
Option 1: 30 days
Option 2: 17 days
Option 3: 22 days
Option 4: 40 days
Correct Answer: 40 days
Solution : Time taken by A alone to complete the work = 60 days Time taken by B alone to complete the work = 33.33% less than 60 days = $(1-\frac{1}{3})×60$ = $\frac{2}{3}×60$ = 40 days Hence, the correct answer is 40 days.
Question : Direction: If ANCIENT is coded as 2516859 and NATURE is coded as 529048, then TRAIN will be coded as.
Option 1: 94285
Option 2: 92456
Option 3: 94265
Option 4: 94168
Correct Answer: 94265
Solution : Given:
ANCIENT is coded as 2516859 and NATURE is coded as 529048
The code of letters in the given word ANCIENT is A → 2; N → 5; C → 1; I → 6; E → 8; N→ 5; T → 9
The code of
Question : If $a=\frac{1}{a-\sqrt{6}}$ and $(a>0)$, then the value of $\left(a+\frac{1}{a}\right)$ is:
Option 1: $\sqrt{6}$
Option 2: $\sqrt{10}$
Option 3: $\sqrt{15}$
Option 4: $\sqrt{7}$
Correct Answer: $\sqrt{10}$
Solution : $a=\frac{1}{a-\sqrt{6}}(x>0)$ $⇒a^2-a\sqrt 6-1=0$ $⇒a^2-1=a\sqrt 6$ Multiplying both sides by $\frac{1}{a}$, we get, $⇒a-\frac{1}{a}=\sqrt 6$ Squaring both sides, we get, $⇒(a-\frac{1}{a})^2=(\sqrt 6)^2$ $⇒a^2+\frac{1}{a^2}-2=6$ Adding 4 to both sides, we get, $⇒a^2+\frac{1}{a^2}+2=6+4$ $⇒(a+\frac{1}{a})^2=10$ $\therefore a+\frac{1}{a}=\sqrt{10}$ Hence, the correct answer is $\sqrt{10}$.
Question : Two circles of radii 15 cm and 10 cm intersect each other and the length of their common chord is 16 cm. What is the distance (in cm) between their centres?
Option 1: $12+3 \sqrt{7}$
Option 2: $15+2 \sqrt{161}$
Option 3: $10+\sqrt{161}$
Option 4: $6+\sqrt{161}$
Correct Answer: $6+\sqrt{161}$
Solution : Let PQ be a common chord. O and O' are the centres of the two circles such that OP = 15 cm, O'P = 10 cm, and PQ = 16 cm OO' perpendicularly bisects PQ at L. So, PL = $\frac{1}{2}$ × PQ = $\frac{16}{2}$
Question : Men's FIH Hockey World Cup 2023 was held in which of the following states in India?
Option 1: Maharashtra
Option 2: Jharkhand
Option 3: West Bengal
Option 4: Odisha
Correct Answer: Odisha
Solution : The correct answer is Odisha.
The state of Odisha in India hosted the 2023 Men's Hockey World Cup. The two locations for the games were Birsa Munda International Hockey Stadium in Rourkela and Kalinga Stadium in Bhubaneswar. At the opening ceremony, Chief Minister Naveen
Question : Which country hosted the 1982 edition of the Asian Games?
Option 1: India
Option 2: China
Option 3: Qatar
Option 4: Pakistan
Correct Answer: India
Solution : The correct answer is India.
India hosted the 1982 Asian Games in Delhi from November 19 to December 4. India secured the 5th rank with a total of 57 medals, comprising 13 gold, 19 silver, and 25 bronze medals. India also hosted the Asian
Question : If $x=5$ ; $y=6$ and $z=-11$, then the value of $x^{3}+y^{3}+z^{3}$ is:
Option 1: –890
Option 2: –970
Option 3: –870
Option 4: –990
Correct Answer: –990
Solution : Given: $x=5$, $y=6$ and $z=-11$ Here $x+y+z= 5 + 6 -11 = 0$ So, $x^{3}+y^{3}+z^{3} = 3xyz = 3\times 5\times 6 \times (-11) = -990$ Hence, the correct answer is $-990$.
Question : The potential for air pollution increases when the ventilation coefficient is:
Option 1: > 11,000 m2/s
Option 2: > 7,600 m2/s
Option 3: < 3,600 m2/s
Option 4: < 6,000 m2/s
Correct Answer: < 6,000 m2/s
Solution : The correct answer is < 6,000 m2/s.
When the ventilation coefficient reaches 6,000 m2/s, the possibility of air pollution increases. The ventilation coefficient measures the capacity of the atmosphere to diffuse and dilute pollutants. It is computed
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