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6 Views

Question : If $x^4+\frac{1}{x^4}=194$ and $x^3+\frac{1}{x^3}=?$

Option 1: 52

Option 2: 58

Option 3: 76

Option 4: 67

Team Careers360 25th Jan, 2024

Correct Answer: 52


Solution : $x^4+\frac{1}{x^4}=194$
Adding 2 on both sides,
⇒ $x^4+\frac{1}{x^4}+2=194+2$
⇒ $(x^2+\frac{1}{x^2})^2=196$
Taking square root on both sides,
⇒ $x^2+\frac{1}{x^2}=14$
Adding 2 on both sides,
⇒ $x^2+\frac{1}{x^2}+2=14+2$
⇒ $(x+\frac{1}{x})^2=16$
Taking square root on both sides,
⇒ $x+\frac{1}{x}=4$
⇒ $(x+\frac{1}{x})^3=4^3$
⇒ $x^3+\frac{1}{x^3}+3(x+\frac{1}{x})=64$
⇒ $x^3+\frac{1}{x^3}+3×4=64$
⇒ $x^3+\frac{1}{x^3}=64-12 = 52$

12 Views

Question : Directions: A is the mother of B. C is the son of A. D is the brother of E, and E is the daughter of B. Who is the grandmother of E?

Option 1: A

Option 2: B

Option 3: C

Option 4: D

Team Careers360 25th Jan, 2024

Correct Answer: A


Solution : As per the given information, the family tree will be as follows –

Here, the quadrilateral represents the male, and the circular figure represents the female in the figure.

So, from the above family tree, A is the grandmother of E. Hence, the first option

21 Views

Question : A can do a work alone in 60 days and B can do the same work alone in 33.33% less time taken by A. Find the time taken by B to complete the work alone.

Option 1: 30 days

Option 2: 17 days

Option 3: 22 days

Option 4: 40 days

Team Careers360 25th Jan, 2024

Correct Answer: 40 days


Solution : Time taken by A alone to complete the work = 60 days
Time taken by B alone to complete the work
= 33.33% less than 60 days
= $(1-\frac{1}{3})×60$
= $\frac{2}{3}×60$ = 40 days
Hence, the correct answer is 40 days.

9 Views

Question : Direction: If  ANCIENT is coded as 2516859 and NATURE is coded as 529048, then TRAIN will be coded as.

Option 1: 94285

Option 2: 92456

Option 3: 94265

Option 4: 94168

Team Careers360 25th Jan, 2024

Correct Answer: 94265


Solution : Given:

ANCIENT is coded as 2516859 and NATURE is coded as 529048

The code of letters in the given word ANCIENT is A → 2; N → 5; C → 1; I → 6; E → 8; N→ 5; T → 9

The code of

23 Views

Question : If $a=\frac{1}{a-\sqrt{6}}$ and $(a>0)$, then the value of $\left(a+\frac{1}{a}\right)$ is:

Option 1: $\sqrt{6}$

Option 2: $\sqrt{10}$

Option 3: $\sqrt{15}$

Option 4: $\sqrt{7}$

Team Careers360 25th Jan, 2024

Correct Answer: $\sqrt{10}$


Solution : $a=\frac{1}{a-\sqrt{6}}(x>0)$
$⇒a^2-a\sqrt 6-1=0$
$⇒a^2-1=a\sqrt 6$
Multiplying both sides by $\frac{1}{a}$, we get,
$⇒a-\frac{1}{a}=\sqrt 6$
Squaring both sides, we get,
$⇒(a-\frac{1}{a})^2=(\sqrt 6)^2$
$⇒a^2+\frac{1}{a^2}-2=6$
Adding 4 to both sides, we get,
$⇒a^2+\frac{1}{a^2}+2=6+4$
$⇒(a+\frac{1}{a})^2=10$
$\therefore a+\frac{1}{a}=\sqrt{10}$
Hence, the correct answer is $\sqrt{10}$.

23 Views

Question : Two circles of radii 15 cm and 10 cm intersect each other and the length of their common chord is 16 cm. What is the distance (in cm) between their centres?

Option 1: $12+3 \sqrt{7}$

Option 2: $15+2 \sqrt{161}$

Option 3: $10+\sqrt{161}$

Option 4: $6+\sqrt{161}$

Team Careers360 25th Jan, 2024

Correct Answer: $6+\sqrt{161}$


Solution :
Let PQ be a common chord. O and O' are the centres of the two circles such that
OP = 15 cm, O'P = 10 cm, and PQ = 16 cm
OO' perpendicularly bisects PQ at L. 
So, PL = $\frac{1}{2}$ × PQ = $\frac{16}{2}$

21 Views

Question : Men's FIH Hockey World Cup 2023 was held in which of the following states in India?

Option 1: Maharashtra

Option 2: Jharkhand

Option 3: West Bengal

Option 4: Odisha

Team Careers360 25th Jan, 2024

Correct Answer: Odisha


Solution : The correct answer is Odisha.

The state of Odisha in India hosted the 2023 Men's Hockey World Cup. The two locations for the games were Birsa Munda International Hockey Stadium in Rourkela and Kalinga Stadium in Bhubaneswar. At the opening ceremony, Chief Minister Naveen

9 Views

Question : Which country hosted the 1982 edition of the Asian Games?

Option 1: India

Option 2: China

Option 3: Qatar

Option 4: Pakistan

Team Careers360 25th Jan, 2024

Correct Answer: India


Solution : The correct answer is India.

India hosted the 1982 Asian Games in Delhi from November 19 to December 4. India secured the 5th rank with a total of 57 medals, comprising 13 gold, 19 silver, and 25 bronze medals. India also hosted the Asian

20 Views

Question : If $x=5$ ; $y=6$ and $z=-11$, then the value of $x^{3}+y^{3}+z^{3}$ is:

Option 1:  –890

Option 2:  –970

Option 3:  –870

Option 4:  –990

Team Careers360 25th Jan, 2024

Correct Answer:  –990


Solution : Given:
$x=5$, $y=6$ and $z=-11$
Here $x+y+z= 5 + 6 -11 = 0$
So, $x^{3}+y^{3}+z^{3} = 3xyz = 3\times 5\times 6 \times (-11) = -990$
Hence, the correct answer is $-990$.

21 Views

Question : The potential for air pollution increases when the ventilation coefficient is:

Option 1: > 11,000 m2/s

Option 2: > 7,600 m2/s

Option 3: < 3,600 m2/s

Option 4: < 6,000 m2/s

Team Careers360 25th Jan, 2024

Correct Answer: < 6,000 m2/s


Solution : The correct answer is < 6,000 m2/s.

When the ventilation coefficient reaches 6,000 m2/s, the possibility of air pollution increases. The ventilation coefficient measures the capacity of the atmosphere to diffuse and dilute pollutants. It is computed

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