1 Million+
Questions
50k +
Active Users
24hrs max.
Answering Time
Question : Comprehension: In the following passage, some words have been deleted. Read the passage carefully and select the most appropriate option to fill in each blank. At most of the local dhabas and fast food joints, poor hygienic conditions (1)_____The (2)_____occurs due to poor quality packaging material or (3)_____storage conditions. Food cooked may not be washed or cleaned properly. It is low in (4)_____rich in oil content especially trans fats which make one (5)_____, lousy and dull. Select the most appropriate option to fill in the blank number 2.
Option 1: contamination
Option 2: perfection
Option 3: purification
Option 4: concentration
Correct Answer: contamination
Solution : The first option is the correct answer.
Contamination refers to the presence of unwanted or harmful substances, especially those that can make something impure or unfit for use. In the context of the passage, poor hygienic conditions lead to contamination, affecting the quality of food.
Question : Who founded the Ramakrishna Mission in 1897?
Option 1: Ramakrishna Paramahansa
Option 2: Swami Vivekananda
Option 3: Keshub Chandra Sen
Option 4: Debendranath Tagore
Correct Answer: Swami Vivekananda
Solution : The correct option is Swami Vivekananda.
The Ramakrishna Mission was founded by Swami Vivekananda, a disciple of the 19th-century Indian mystic and saint Sri Ramakrishna. The mission was established in 1897 to carry out philanthropic, educational and spiritual activities for the well-being of society.
Question : In the given figure, the area of isosceles triangle $\mathrm{ABE}$ is $72\;\mathrm{cm^2}$ and $\mathrm{BE = AB}$ and $\mathrm{AB = 2 AD}$, $\mathrm{AE \parallel DC}$, then what is the area (in$\;\mathrm{cm^2}$) of the trapezium $\mathrm{ABCD}$?
Option 1: 108
Option 2: 124
Option 3: 136
Option 4: 144
Correct Answer: 144
Solution : Given that the area of triangle $\mathrm{ABE}$ is $72\;\mathrm{cm^2}$. The triangle is an isosceles. $\mathrm{AB} = \mathrm{BE} = \sqrt{2 \times 72} = 12\;\mathrm{cm}$ $\mathrm{AB = 2 AD}$ ⇒ $\mathrm{AD} = \frac{\mathrm{AB}}{2} = 6\;\mathrm{cm}$ Since $\mathrm{AE} \parallel \mathrm{DC}$ $\mathrm{CE} = \mathrm{AD} = 6\;\mathrm{cm}$, and $\mathrm{BC} =
Question : The length of the shadow of a vertical tower on level ground increases by 10 m when the altitude of the sun changes from 45° to 30°. The height of the tower is:
Option 1: $10 \sqrt{3}$ m
Option 2: $5 \sqrt{3}$ m
Option 3: $5(\sqrt{3}+1)$ m
Option 4: $10(\sqrt{3}+1)$ m
Correct Answer: $5(\sqrt{3}+1)$ m
Solution : Let the height of the tower be $h$ meters. And $p$ is the shadow of the tower In $\triangle ABC$, ⇒ $\tan45^\circ = \frac{h}{p}$ ⇒ $p = h$....................................(equation i) In $\triangle ABD$ ⇒ $\tan30^\circ = \frac{h}{10+p}$ Putting the value $p$ from equation (i), we
Question : The Fundamental Duties were added to the Constitution of India by the ____________ Amendment.
Option 1: 73rd
Option 2: 42nd
Option 3: 34th
Option 4: 44th
Correct Answer: 42nd
Solution : The correct answer is 42nd.
The Fundamental Duties were added to the Constitution of India by the 42nd Amendment Act of 1976. This amendment, which came into effect on November 3, 1976, incorporated a list of ten fundamental duties that citizens of India are expected
Question : Comprehension:
In the following passage, some of the words have been deleted. Read the passage carefully and select the correct answer for the given blank out of the four alternatives.
One headteacher asked what she should say to parents who request guidance (1) _______ getting their child "school-ready" because she was concerned that too (2) ______ parents have become convinced that an expert (the teacher) knows more than they do about their own child's (3) _______. Her intention was not to bash parents, (4) _____ she wanted to know how to encourage parents to see "school" as a distinct domain from "home", where their own (5) ______ ought to hold sway. Question:
Select the most appropriate option to fill in the blank 1.
Option 1: at
Option 2: to
Option 3: of
Option 4: on
Correct Answer: on
Solution : The correct choice is the fourth option.
Explanation:
The sentence structure and context suggest that the headteacher is being asked what to say to parents requesting guidance. The preposition on is commonly used in English to indicate being involved in or seeking advice or assistance
Question : The height of a cylinder is $\frac{2}{3}$rd of its diameter. Its volume is equal to the volume of a sphere whose radius is 4 cm. What is the curved surface area (in cm2) of the cylinder?
Option 1: $\frac{112}{3} \pi$
Option 2: $32 \pi$
Option 3: $\frac{128}{3} \pi$
Option 4: $40 \pi$
Correct Answer: $\frac{128}{3} \pi$
Solution : Given, The height of a cylinder is $\frac23$rd of its diameter. Cylinder volume is equal to the volume of a sphere whose radius is 4 cm. We know, Volume of cylinder = $\pi r^2h$ Volume of sphere = $\frac43\pi R^3$ Curved surface area of
Question : Directions: If a mirror is placed on the line MN, then which of the answer figures is the right image of the given figure?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : As per the mirror image properties, closer things appear closer to the mirror in the reflection. Here, according to the information provided, the mirror is placed at the bottom of the figure (on line MN). So, the top of the reflected image will appear as the
Question : Rajeev invested Rs. 3,000 for 2 years at compound interest (compounded annually) in a company that paid him interest of Rs.1,320. What will be the annual rate of interest at which Rajeev invested his money?
Option 1: 30 percent
Option 2: 24 percent
Option 3: 16 percent
Option 4: 20 percent
Correct Answer: 20 percent
Solution : Given, Principal ($P$) = Rs. 3000 Compound Interest ($CI$) = Rs. 1320 Time (t) = 2 years We know, $CI = P(1 + \frac{r}{100})^t - P$ ⇒ $1320 = 3000(1+\frac{r}{100})^2 - 3000$ ⇒ $1320+3000 = 3000(1+\frac{r}{100})^2$ ⇒ $\frac{4320}{3000}=(1+\frac{r}{100})^2$ ⇒ $\sqrt{1.44}=(1+\frac{r}{100})$ ⇒ $1.2 = (1+\frac{r}{100})$
Question : X and Y together can do a work in 10 days. Y and Z together can do the same work in 15 days. Z and X together can do the same work in 12 days. In how many days can Z alone do the same work?
Option 1: 80 days
Option 2: 60 days
Option 3: 40 days
Option 4: 50 days
Correct Answer: 40 days
Solution : Given, X and Y together can do a work in 10 days. Y and Z together can do the same work in 15 days. Z and X together can do the same work in 12 days. Let the total work = LCM (10, 15,
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update