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26 Views

Question : Choose the incorrectly spelt word.

Option 1: Stone

Option 2: Minyed

Option 3: punch

Option 4: crunch

Team Careers360 25th Jan, 2024

Correct Answer: Minyed


Solution : The correct choice is the first option.

The incorrectly spelled word is "Minyed," which is a misspelling. The correct spelling is "mined," which refers to the extraction of minerals or resources from the earth.

The correct spellings and meanings of the remaining options are as

11 Views

Question : Who among the following was the founder of the Mauryan Empire?

Option 1: Ashoka

Option 2: Bindusara

Option 3: Chandragupta Maurya

Option 4: Brihadratha Maurya

Team Careers360 23rd Jan, 2024

Correct Answer: Chandragupta Maurya


Solution : The correct answer is Chandragupta Maurya.

Chandragupta Maurya established the Mauryan Empire in the 4th century BC. He tried for territorial expansion and integration in India and succeeded except in a few places like Kalinga and South India. In his court, several Greek

23 Views

Question : Sonal Mansingh is associated with which dance form?

Option 1: Kuchipudi and Sattriya

Option 2: Bharatnatyam and Odissi

Option 3: Manipuri and kathak

Option 4: Manipuri and Kuchipudi

Team Careers360 24th Jan, 2024

Correct Answer: Bharatnatyam and Odissi


Solution : The correct option is Bharatnatyam and Odissi.

Sonal Mansingh is associated with Bharatanatyam and Odissi, two classical Indian dance forms. Renowned as a highly accomplished dancer and choreographer, she has made significant contributions to the promotion and preservation of these rich cultural

17 Views

Question : If $a \cot \theta+b \operatorname{cosec} \theta=p$ and $b \cot \theta+a \operatorname{cosec} \theta=q$, then $p^2-q^2$ is equal to ____.

Option 1: $b^2-a^2$

Option 2: $a^2-b^2$

Option 3: $b-a$

Option 4: $a^2+b^2$

Team Careers360 23rd Jan, 2024

Correct Answer: $b^2-a^2$


Solution : $a \cot \theta+b \operatorname{cosec} \theta=p$
$b \cot \theta+a \operatorname{cosec} \theta=q$
So, $p^2-q^2$
= $(a \cot \theta+b \operatorname{cosec} \theta)^2 - (b \cot \theta+a \operatorname{cosec} \theta)^2$
= $a^2 \cot^2 \theta+b^2 \operatorname{cosec}^2 \theta + 2×a \cot \theta×b \operatorname{cosec} \theta$ – $(b^2 \cot^2 \theta+a^2 \operatorname{cosec}^2\theta+2×b \cot \theta×a \operatorname{cosec} \theta)$

17 Views

Question : Direction: If SPANK is coded as PSNAK, then THROW is coded as?

Option 1: HTWOR

Option 2: HTWRO

Option 3: HTROW

Option 4: HTORW

Team Careers360 23rd Jan, 2024

Correct Answer: HTORW


Solution : Given:

SPANK → PSNAK

In the coded language,

S ⇔ P; A ⇔ N

Similarly, THROW will be coded as:

T ⇔ H; R ⇔ O

THROW → HTORW

Hence, the fourth option is correct.

19 Views

Question : Which one of the following is also called a 'power house' of the cell?

Option 1: Golgi body

Option 2: Mitrochondria

Option 3: Ribosome

Option 4: Lysosome

Team Careers360 23rd Jan, 2024

Correct Answer: Mitrochondria


Solution : The correct answer is Mitrochondria.

The Mitrochondria is also known as the cell's powerhouse. Mitochondria are organelles found in every eukaryotic cell. They are in charge of turning food into energy in the form of ATP, the cell's primary energy currency.

8 Views

Question : If $\small a^{4}+1=\left [\frac{a^{2}}{b^{2}}\right ]\left (4b^{2}-b^{4}-1\right),$ then what is the value of $a^{4}+b^{4}?$

Option 1: 2

Option 2: 16

Option 3: 32

Option 4: 64

Team Careers360 24th Jan, 2024

Correct Answer: 2


Solution : Given: $a^{4}+1=\frac{a^{2}}{b^{2}}( 4b^{2}-b^{4}-1)$
⇒ $\frac{(a^{4}+1)}{a^2}=\frac{1}{b^{2}}( 4b^{2}-b^{4}-1)$
⇒ $a^2+\frac{1}{a^2}=4 -b^2-\frac{1}{b^2}$
⇒ $a^2+\frac{1}{a^2}+2+b^2+\frac{1}{b^2} +2 =0$
⇒ $(a-\frac{1}{a})^2+(b-\frac{1}{b})^2=0$
So, $(a-\frac{1}{a})^2=0 \;$and$\; (b-\frac{1}{b})^2=0$
⇒ $a-\frac{1}{a}=0 \; $ and$\; b-\frac{1}{b}=0$
⇒ $a=\frac{1}{a} \; $ and$\; b=\frac{1}{b}$
⇒ $a^2=1 \;$ and $\; b^2 = 1$
$\therefore a^{4}+b^{4}=2$
Hence, the correct answer

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