96 Views

A cubic solid has PQR atoms.P is in fcc,Q is all tetra hedral void and R in all octa hedral void.what is the formula?

Shadil Ameen pk 11th Aug, 2020

Answer (1)

Ankita Grover 11th Aug, 2020

Hello,

In FCC unit cell, no. of atoms present = 4, therefore no. of atoms of P = 4

Number of octahedral voids present = 4, therefore no. of atoms of Q = 4

Number of tetrahedral voids present = 2 * Number of octahedral voids = 2 * 4 = 8, therefore no. of atoms of R = 8

Now, P:Q:R = 4:4:8

= P:Q:R = 1:1:2

Therefore, formula of the compound is: PQR2 (Answer)

Share

Facebook Copy Link

More

Comments (0)

Related Questions

the mangnate and paramagnate ions are tetra hedral due to

551 Views

What is the formula of potassium tetra fluoro borate

118 Views

A solid ball of radius R has charge density rho has given by rho=rho not (1-r/R).the electric field outside the ball is

1016 Views

P is twice as fast as Q and R together .Working together ,all three can do a work in 21 days.In how many days can Q and R together do the work

1671 Views

formula of magnetic current due to a hollow solid cylinder

47 Views

Link Copied

The question have been saved in answer later, you can access it from your profile anytime. Access now

Thanks! Your report is submitted, the author will be informed about it

Download Careers360 App

All this at the convenience of your phone

Regular Exam Updates
Best College Recommendations
College & Rank predictors
Detailed Books and Sample Papers
Question and Answers