Question : A cylinder 84 cm long is made of steel. Its external and internal diameters are 10 cm and 8 cm respectively. What is the volume of the steel in the cylinder (in 10–3 m3 and correct up to three decimal places)?
Option 1: 2.112
Option 2: 9.504
Option 3: 2.376
Option 4: 4.752
Correct Answer: 2.376
Solution :
The volume of a hollow cylinder =$ \pi (R^2 - r^2)h$, where $R$ is the external radius and $r$ is the internal radius, $h$ = height
Given:
Height of the cylinder, $h$ = $84$ cm
External radius of the cylinder, $R = \frac{10}{2} = 5$ cm
Internal radius of the cylinder, $r = \frac{8}{2} = 4$ cm
Now, the volume of the cylinder
$= \pi (R^2 - r^2)h$
$=\frac{22}{7}\times (5^2 - 4^2)\times 84$
$=\frac{22}{7}\times (25 - 16)\times 84$
$= 22\times 9\times 12$
$= 2376$ cm
3
$= \frac{2376}{100\times 100\times 100}$ m
3
$= 2376\times 10^{-6}$ m
3
$= 2.376\times 10^{-3}$ m
3
Hence, the correct answer is 2.376.
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