A plate 0.025mm distance from a fixed plate, moves at 60cm/s and requires a force of 2N per unit area
Answer (1)
30th Mar, 2020
Hi,
Distance between the plates
dy=0.025x10^(-3)m
Velocity of upper plate
u=0.6m/s
F=2.0N/m^2
du=change in velocity=u-0=0.60m/s
dy=change in distance=0.025x10^(-3)m
Force per unit area=2.0N/m^2
Mue=2x0.025x10^(-3)/0.60
=8.33x10^(-4)poise
Distance between the plates
dy=0.025x10^(-3)m
Velocity of upper plate
u=0.6m/s
F=2.0N/m^2
du=change in velocity=u-0=0.60m/s
dy=change in distance=0.025x10^(-3)m
Force per unit area=2.0N/m^2
Mue=2x0.025x10^(-3)/0.60
=8.33x10^(-4)poise
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