Question : A rod of 5 cm radius and 52 cm length is converted into a wire of 100 cm length of uniform thickness. The radius of the wire (in cm) is:
Option 1: $\sqrt{13}$
Option 2: $\sqrt{15}$
Option 3: $\sqrt{23}$
Option 4: $\sqrt{17}$
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: $\sqrt{13}$
Solution :
Let the radius and height of the rod be $r_1$ and $h_1$, and the radius and height of the wire be $r_2$ and $h_2$.
Volume of the rod = Volume of the wire
$\pi r_1^2h_1=\pi r_2^2h_2$
⇒ $5^2\times 52=r_2^2\times 100$
⇒ $r_2^2=\frac{25\times52}{100}$
⇒ $r_2^2=13$
⇒ $r_2=\sqrt{13}\mathrm{\ cm}$
Hence, the correct answer is $\sqrt{13}$.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Admit Card | Eligibility | Application | Answer Key | Preparation Tips | Result | Cutoff
Get Updates Brochure
Your Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
