Question : Abha and Anuj working together completed a job in $\frac{40}{9}$ days. If Abha had worked twice as efficiently as she actually did and Anuj had worked $\frac{1}{3}$ of his actual efficiency, then the work would have been completed in $\frac{60}{17}$ days. Find the time Abha would take to complete the work alone.
Option 1: 10 days
Option 2: 8 days
Option 3: 12 days
Option 4: 6 days
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Correct Answer: 8 days
Solution :
Let the total work be 1 unit.
Let the efficiency of Abha be $x$ work/day.
Let the efficiency of Anuj be $y$ work/day.
Two workers A and B working together completed a job in $\frac{40}{9}$ days.
So, $\frac{1}{x+y}=\frac{40}{9}$
$⇒9=40x+40y$ ------(1)
If Abha worked twice as efficiently as she did and Anuj worked $\frac{1}3$rd as efficiently as he did the work would have been completed in $\frac{60}{17}$ day.
So, $\frac{1}{2x+\frac{1}3y}=\frac{60}{17}$
$⇒17=120x+20y$ -------(2)
From equations (1) and (2), we get,
$200x = 25$
$\therefore x=\frac{1}{8}$
So, Abha alone could complete the work in 8 days.
Hence, the correct answer is 8 days.
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