Question : An incircle with center O is drawn inside an equilateral triangle ABC and the length of the side is 12 cm. Find the area (in sq cm) of the triangle which is not in the incircle.
Option 1: 24.67
Option 2: 21.48
Option 3: 37.71
Option 4: 30.64
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Correct Answer: 24.67
Solution :
Side of an equilateral triangle, $a$ = 12 cm
Radius of incircle, $r = \frac{a}{2\sqrt3}= \frac{12}{2\sqrt3}= \frac{6}{\sqrt3}= 2\sqrt3$ cm
Area of incircle $= \pi r^2= \pi × ( 2\sqrt3)^2= 12\pi $
$\therefore$ Area of equilateral triangle $= \frac{\sqrt3}{4} a^2= \frac{\sqrt3}{4} ×12^2= 36\sqrt3$
Area of triangle outside incircle
$= 36\sqrt3 - 12\pi$
$= (36 × 1.732) - (12 × 3.14)$
$= 62.352 - 37.68$
$= 24.67$ sq. cm
Hence, the correct answer is 24.67.
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