Question : If $a=10$ and $b=3$, then what is the value of $\frac{(a+b)^2}{a^2-b^2}$?
Option 1: $\frac{182}{93}$
Option 2: $\frac{169}{91}$
Option 3: $\frac{185}{91}$
Option 4: $\frac{185}{93}$
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Correct Answer: $\frac{169}{91}$
Solution :
putting the value $a=10$ and $b=3$, we get,
$\frac{(a+b)^2}{a^2-b^2}$
= $\frac{(10+3)^2}{10^2-3^2}$
= $\frac{13^2}{100-9}$
= $\frac{169}{91}$
Hence, the correct answer is $\frac{169}{91}$.
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