Question : If $\left(2^2+4\right)^2 \times(3-5)+20 \%$ of $400+x \%$ of $30=30 \%$ of $30$, find the value of $x$.
Option 1: 150
Option 2: 120
Option 3: 190
Option 4: 160
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Correct Answer: 190
Solution :
$\left(2^2+4\right)^2 \times(3-5)+20 \%$ of $400+x \%$ of $30=30 \%$ of $30$
⇒ $(4+4)^2 \times (-2) + \frac{20\times 400}{100} + \frac{30x}{100} = \frac{30\times 30}{100}$
⇒ $8^2 \times (-2) + 80 + 0.3x = 9$
⇒ $-128 + 80 + 0.3 x = 9$
⇒ $-48 + 0.3x = 9$
⇒ $0.3x = 57$
$\therefore x = \frac{570}{3} = 190$
Hence, the correct answer is 190.
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