Question : If $a=\frac{b^{2}}{b–a}$, the value of $a^{3}+b^{3}$ is:
Option 1: $6ab$
Option 2: 0
Option 3: 1
Option 4: 2
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Correct Answer: 0
Solution :
Given: $a=\frac{b^{2}}{b–a}$
⇒ $ab–a^{2}=b^{2}$
$\therefore a^{2}+b^{2}–ab=0$
We know that $a^{3}+b^{3}=(a+b)(a^{2}+b^{2}–ab)$
$\therefore a^{3}+b^{3}=0$
Hence, the correct answer is 0.
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