Question : If $a+\frac{1}{a}=P^2$, then find $a^2+\frac{1}{a^2}$.
Option 1: $p^2 - 2$
Option 2: $p^2 + 2$
Option 3: $p^4 - 2$
Option 4: $p^4 + 2$
Correct Answer: $p^4 - 2$
Solution :
Given: $a+\frac{1}{a}=P^2$
Squaring both sides, we get:
⇒ $(a+\frac{1}{a})^2=(P^2)^2$
⇒ $a^2+\frac{1}{a^2}+2\times a\times\frac{1}{a}=P^4$
$\therefore a^2+\frac{1}{a^2}=P^4-2$
Hence, the correct answer is $P^4-2$.
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