Question : If $5 x-\frac{5}{x}+6=0$, then $x^2+\frac{1}{x^2}$ is:
Option 1: $\frac{86}{25}$
Option 2: $\frac{43}{12}$
Option 3: $\frac{81}{10}$
Option 4: $\frac{86}{11}$
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Correct Answer: $\frac{86}{25}$
Solution :
Given, $5 x-\frac{5}{x}+6=0$
$⇒5(x-\frac{1}{x})+6=0$
$⇒x-\frac{1}{x}=-\frac{6}{5}$
Squaring both sides, we get:
$⇒x^2+\frac{1}{x^2}-2=\frac{36}{25}$
$⇒x^2+\frac{1}{x^2}=\frac{36}{25}+2$
$\therefore x^2+\frac{1}{x^2}=\frac{86}{25}$
Hence, the correct answer is $\frac{86}{25}$.
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