Question : If $\frac{\sec \theta+\tan \theta}{\sec \theta–\tan \theta}=2 \frac{51}{79}$, then the value of $\sin \theta$ is equal to:
Option 1: $\frac{35}{72}$
Option 2: $\frac{39}{72}$
Option 3: $\frac{91}{144}$
Option 4: $\frac{65}{144}$
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Correct Answer: $\frac{65}{144}$
Solution :
Given: The given equation is $\frac{\sec \theta+\tan \theta}{\sec \theta–\tan \theta}=2 \frac{51}{79}$.
⇒ $\frac{\sec \theta+\tan \theta}{\sec \theta–\tan \theta}=2 \frac{51}{79}$
⇒ $79\sec \theta+79\tan \theta=209\sec \theta–209\tan \theta$
⇒ $288\tan \theta=130\sec \theta$
⇒ $\frac{\sin \theta}{\cos \theta}=\frac{130}{288}\times \frac{1}{\cos \theta}$
⇒ $\sin \theta=\frac{65}{144}$
Hence, the correct answer is $\frac{65}{144}$.
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