Question : If $\sin P=\frac{15}{22}$, then what is the value of $\tan P$?
Option 1: $\frac{16}{\sqrt{259}}$
Option 2: $\frac{22}{\sqrt{259}}$
Option 3: $\frac{14}{\sqrt{259}}$
Option 4: $\frac{15}{\sqrt{259}}$
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Correct Answer: $\frac{15}{\sqrt{259}}$
Solution :
$\sin P=\frac{15}{22}$
We know, $\cos A = \sqrt{(1 - \sin^2 A)}$
So, $\cos A = \sqrt{(1 - (\frac{15}{22})^2}$
⇒ $\cos A = \sqrt{(1 - (\frac{225}{484})}$
⇒ $\cos A = \sqrt{\frac{259}{484}}$
⇒ $\cos A = \frac{\sqrt{259}}{22}$
So, $\tan A = \frac{\sin A}{\cos A}= \frac{\frac{15}{22}}{ \frac{\sqrt{259}}{22}}= \frac{15}{\sqrt{259}}$
Hence, the correct answer is $\frac{15}{\sqrt{259}}$.
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