Question : If TM and TN are the two tangents to a circle with centre O so that $\angle$MON = 105°, then $\angle$MTN will be equal to:
Option 1: 70°
Option 2: 60°
Option 3: 75°
Option 4: 85°
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 75°
Solution :
Given: $\angle$MON = 105°
We know,
$\angle$OMT = $\angle$ONT = 90$°$ (Angle between the tangent and the radial line at the point of intersection of the tangent at the circle)
Now, in quadrilateral MONT
Sum of angles = 360$°$
$\angle$OMT + $\angle$ONT + $\angle$MTN + $\angle$MON = 360°
⇒ 90$°$ + 90$°$ + $\angle$MTN + 105$°$ = 360$°$
⇒ $\angle$MTN = 360$°$ − 285$°$
⇒ $\angle$MTN = 75$°$
Hence, the correct answer is 75°.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Answer Key | Eligibility | Application | Admit Card | Preparation Tips | Result | Cutoff
Get Updates BrochureYour Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.




