Question : In a triangle, ABC, the line parallel to BC intersects AB and AC at P and Q respectively. If AB : AP = 5 : 3, then AQ : QC is:
Option 1: 3 : 2
Option 2: 2 : 3
Option 3: 3 : 5
Option 4: 1 : 2
Correct Answer: 3 : 2
Solution :
Let AP = 3 units and AB = 5 units
So, PB = 5 – 3 = 2 units
$\therefore \frac{\text{AP}}{\text{PB}}=\frac{\text{AQ}}{\text{QC}}$
⇒ $\frac{\text{AQ}}{\text{QC}}=\frac{3}{2}$
⇒ AQ : QC = 3 : 2
Hence, the correct answer is 3 : 2.
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