Question : In the given figure, the triangle PQR is right-angled at Q. If PQ = 35 cm and QS = 28 cm and a semicircle passes from the point QRS, then what is the value (in cm) of SR?
Option 1: 35.33
Option 2: 37.33
Option 3: 41.33
Option 4: 43.33
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Correct Answer: 37.33
Solution : Given: Triangle PQR is right-angled at Q. If PQ = 35 cm and QS = 28 cm and a semicircle pass from the point QRS.
We know the angle made by the circle's diameter is a right angle.
So, $\angle$QSR = 90°
⇒ $\angle$PSQ = 90°
Now applying Pythagoras theorem in $\triangle$PSQ,
PS = $\sqrt{35^2-28^2}$
⇒ PS = 21 cm
Also, $\triangle$PSQ and $\triangle$QSR are similar triangles,
So, $\frac{PS}{QS}=\frac{QS}{SR}$
⇒ SR = $\frac{QS^2}{PS}$
⇒ SR = $\frac{28^2}{21}$
⇒ SR = $\frac{784}{21}$
⇒ SR = 37.33 cm
Hence, the correct answer is 37.33.
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